Cell Structure And Transport Flashcards
Describe how you could use cell fractionation to isolate chloroplasts from leaf tissue. (3)
- break cells open by homogenising the tissue in an ice cold isotonic, buffer solution and blender
- filter homogenised solution to remove cell debris
- centrifuge at low speed to get pellets of nuclei
- centrifuge the supernatant at a higher speed, for a longer time and the pellet at the bottom is chloroplast ( the second pellet)
Describe how you would use the student’s results in table 3 to find the water potential of the potato tissue. (3)
- plot a graph of results
- conc of sucrose on the x-axis and %change in mass of potato on y-axis
- find conc where curve crosses the x-axis
- find water potential of this sucrose solution
The scientist concluded that the cells in flask ‘G’ (flask with animal tissue and sodium ions in to investigate the uptake on sodium ions by animal tissue, flask F also has a solution that prevents the formation of ATP by cells. Graph shows the measured conc of sodium ions remaining every every 10 mins; curve of ‘G’ is steadily going down.) took up sodium ions by active transport. Explain how the information given supports this conclusion. (4)
- uptake in flask G is much greater than flask F
- showing use of ATP in flask G
- sodium ion conc in flask G falls to 0
- showing uptake against conc gradient -active transport
The curve levelled off after 20 mins. Explain why. (2)
- cells taking up sodium ions by facilitated diffusion
- equilibrium reached so no conc gradient (no ATP so can’t take up by active transport, against conc gradient)
Explain why the solution the biologist used was ice-cold, buffered and isotonic. (3)
- Ice cold: prevents action of enzymes within cell that might cause self-digestion of organelles
- Buffered: maintains pH so that proteins aren’t denatured
- Isotonic: prevents osmotic lysis of cell
Explain why the biologist used a blender and then filtered the mixture. (2)
- blended moisture to homogenise it, this breaks open the cells
- filter the mixture to remove cell debris that didn’t burst during homogenising
A scientist placed plant cells in solutions containing different conc of calcium ions. She measured the rate of uptake of calcium ions by plant cells. A graph shows her results showing conc of calcium ions in solution against rate of uptake of calcium ions; curve Y goes upwards curving round to about 27 and this had oxygen, curve X starts at 0.1 and is a straight line going up to 10 and this had no oxygen.
What can you conclude from the graph about cell processes involved in the uptake of calcium ions by these plant cells? (5)
- between 0.0 and 0.1 calcium ions can’t enter by facilitated diffusion
- between 0.1 and 0.3 ions enter via facilitated diffusion as it doesn’t need oxygen
- between 0.0 and 0.1 ions enter by active transport as its against conc gradient
- oxygen is required for active transport
Suggest one way in which the scientist could have ensured the solutions she used for curve X had no oxygen. (1)
- layer of oil on top/ boiled and cooled water
(diagram of plant cell producing its cell wall)
Y is a protein. One function of Y is to transport cellulose molecules across the phospholipid bilayer.
Using information from figure 3, describe the other function of Y. (2)
- Y is an enzyme and forms ES complexes
- that attaches substrate to cellulose
What is the evidence in figure 3 that the phospholipid bilayer is shown as pat of the cell-surface membrane? (1)
- cell wall forms outside cell-surface membrane
- picture shows cellulose on the outside
Give a function of mitochondria. (1)
Site of aerobic respiration yielding ATP
Glycogen and cellulose are both carbohydrates.
Describe two differences between the structure of a cellulose molecule and a glycogen molecule. (2)
- cellulose is made of b-glucose and glycogen is made of a-glucose
- cellulose has straight chains and glycogen is branched/ coiled
The cells of beetroot contain pigment. A student investigated the effect of temp on the loss of red pigment of beetroot. He put discs cut from beetroot into tubes containing water. He maintained each tube at different temps. After 25 mins, he measured the % of light passing through the water in each tube.
The student put the same volume of water in each tube.
Explain why it was important that he controlled this experimental variable. (2)
- if too much water then the conc of pigment in the solution will be lower
- so results are comparable
The cells of beetroot contain pigment. A student investigated the effect of temp on the loss of red pigment of beetroot. He put discs cut from beetroot into tubes containing water. He maintained each tube at different temps. After 25 mins, he measured the % of light passing through the water in each tube.
Describe a method the student could have used to monitor the temp of the water in each tube. (1)
Take reading during the experiment using a thermometer
The cells of beetroot contain pigment. A student investigated the effect of temp on the loss of red pigment of beetroot. He put discs cut from beetroot into tubes containing water. He maintained each tube at different temps. After 25 mins, he measured the % of light passing through the water in each tube.
The decrease in the % of light passing through the water between 25’c and 60’c is caused by the release of red pigment from cells of the beetroot.
Suggest how the increase in temp of the water caused the release of the red pigment. (2)
- damage to cell-surface membrane
- membrane proteins denature
- increased fluidity due to damaged phospholipid bilayer