Cell Recognition And The Immune System - Mark Scheme Answers (study Mind) Flashcards
Explain why antibody A attaches only to the protein found in species of Plasmodium.
- Antibody has tertiary structure;
- Complementary to binding site on protein.
Explain why antibody B is important.
- Prevents false negative results;
- (Since) shows antibody A has moved up strip / has not bound to any Plasmodium protein.
(a) HSV infects nerve cells in the face (line 1). Explain why it infects only nerve cells.
- Outside of virus has antigens / proteins;
- With complementary shape to receptor / protein in membrane of cells;
- (Receptor / protein) found only on membrane of nerve cells.
(b) HSV can remain inactive inside the body for years (lines 2–3). Explain why this virus can be described as inactive.
- No more (nerve) cells infected / no more cold sores form;
- (Because) virus is not replicating.
(c) Suggest one advantage of programmed cell death (line 4).
Prevents replication of virus.
The scientists concluded that production of this microRNA allows HSV to remain in
the body for years (lines 10–12).
Explain how this microRNA allows HSV to remain in the body for years.
- (Binds) by specific base pairing;
- (So) prevents mRNA being read by ribosomes;
- (So) prevents translation / production of proteins;
- (Proteins) that cause cell death.
A mutation of a tumour suppressor gene can result in the formation of a tumour. Explain how
- (Tumour suppressor) gene inactivated / not able to control / slow down cell division;
- Rate of cell division too fast / out of control.
(ii) Not all mutations result in a change to the amino acid sequence of the
encoded polypeptide.
Explain why.
- (Genetic) code degenerate;
- Mutation in intron.
Some cancer cells have a receptor protein in their cell-surface membrane that binds
to a hormone called growth factor. This stimulates the cancer cells to divide.
Scientists have produced a monoclonal antibody that stops this stimulation.
Use your knowledge of monoclonal antibodies to
suggest how this antibody stops
the growth of a tumour.
- Antibody has specific tertiary structure / binding site / variable region;
- Complementary (shape / fit) to receptor protein / GF / binds to receptor protein / to GF;
- Prevents GF binding (to receptor).
(a) The scientists gave an injection to a mouse to make it produce the monoclonal
antibody used in this investigation (line 7).
What should this injection have contained?
Regulator protein.
(b) LDL enters the liver cells (lines 3−4).
Using your knowledge of the structure of the cell-surface membrane, suggest how
LDL enters the cell.
- Lipid soluble / hydrophobic
- Enters through (phospholipid) bilayer
(c) Explain how the monoclonal antibody would prevent the regulator protein from
working (lines 7−8).
- (Monoclonal antibody) has a specific tertiary structure / variable region / is complementary to regulator protein
- Binds to / forms complex with (regulator protein)
(d) Describe how the control group should have been treated.
- Injection with salt solution
- Otherwise treated the same.
(a) Suggest two reasons why the percentage of infants vaccinated decreased between
1973 and 1975.
- (Decrease linked to) few(er) cases of whooping cough;
- (Decrease linked to) risk of / fear of side effects;
- Insufficient vaccine available / too expensive to produce / distribute.
Between 1980 and 1990, there were three peaks in the number of reported cases of
whooping cough. After 1981, the number of cases of whooping cough in each peak
decreased.
Use the information from the graph to suggest why.
- Vaccination rate increases;
- Fewer people to spread the disease / whooping cough / more people immune / fewer susceptible.
The percentage of the population vaccinated does not need to be 100% to be
effective in preventing the spread of whooping cough.
Suggest why.
- More people are immune / fewer people carry the pathogen;
- So susceptible / unvaccinated people less likely to contact infected
people.
(a) Give two ways in which pathogens can cause disease.
- (Releases) toxins;
- Kills cells / tissues.
(b) Putting bee honey on a cut kills bacteria. Honey contains a high concentration of
sugar.
Use your knowledge of water potential to suggest how putting honey on a cut kills
bacteria.
- Water potential in (bacterial) cells higher (than in honey) / water
potential in honey lower (than in bacterial cells);
- Water leaves bacteria / cells by osmosis;
- (Loss of water) stops (metabolic) reactions.
Describe how HIV is replicated.
- Attachment proteins attach to receptors on helper T cell/lymphocyte;
- Nucleic acid/RNA enters cell;
- Reverse transcriptase converts RNA to DNA;
- Viral protein/capsid/enzymes produced;
- Virus (particles) assembled and released (from cell);
Use your knowledge of phagocytosis to describe how an ADC enters and
kills the tumour cell.
- Cell ingests/engulfs the antibody/ADC
- Lysosomes fuse with vesicle/phagosome (containing ADC);
- Lysozymes breakdown/digest the antibody/ADC to release the drug;
(b) Some of the antigens found on the surface of tumour cells are also found
on the surface of healthy human cells.
Use this information to explain why treatment with an ADC often causes
side effects.
- ADC will bind to non-tumour/healthy cells;
- Cause death/damage of non-tumour/healthy cells
Suggest and explain two further investigations that should be done before
this ADC is tested on human breast cancer patients.
- Tested on other mammals to check for safety/side effects;
- Tested on (healthy) humans to check for safety/side effects;
Describe how the human immunodeficiency virus (HIV) is replicated once inside helper T cells (TH cells).
- RNA converted into DNA using reverse transcriptase;
- DNA incorporated/inserted into (helper T cell)
DNA/chromosome/genome/nucleus; - DNA transcribed into (HIV m)RNA;
- (HIV mRNA) translated into (new) HIV/viral proteins (for assembly into viral particles);
Use the information given to evaluate the use of BSCT to treat HIV infections.
For
1. (There appears to be) no virus/ HIV(-1)/RNA/DNA, so could be a cure/effective;
2. No CCR5/receptor, so not get HIV(-1) in the future 3. Only one transplant/BSCT needed (shown by patient Q)
Against
1. Don’t know if chemotherapy/radiotherapy is needed
2. Do not know if BSCT alone would be effective;
Do not know which ones having an effect.
3.Could be due to chemotherapy/radiotherapy;