Calibrations/Equations

Question 1

% Deviation of sprayer nozzles =

Answer 1

((average nozzle output - individual nozzle output) / average nozzle output) x 100

Question 2

Surface Acres =

Answer 2

(length in ft x width in ft) / 43,560 sq ft per acre

Question 3

Acreage of a rectangular area =

Answer 3

(length x width) / 43,560

Question 4

Acreage of a circular area =

Answer 4

(3.14 x radius^2) / 43,560

Question 5

Acreage of a triangular area =

Answer 5

(1/2 x base x height) / 43,560

Question 6

Area of an irregularly shaped water body, using the graph paper method (Area of lake =)

Answer 6

area of rectangle x fraction occupied by lake

Question 7

Effective swath width =

Answer 7

boom width x 2

Question 8

Herbicide needed to treat a given area =

Answer 8

treatment rate x acres to be treated

Question 9

Average depth=

Answer 9

sum of all measurements / number of all measurements

Question 10

Volume =

Answer 10

average depth in ft x surface area in acres
OR
(l x w x d) / 43,560 cubic feet per acre-foot

Question 11

Pounds ai needed =

Answer 11

ppm x water volume (acre-feet) x 2.7

Question 12

ppm (for a given amount of ai) =

Answer 12

lbs ai / (water volume x 2.7)

Question 13

Converting ai and product in dry formulations

Answer 13

amount ai = product ai x % ai
OR
amount product = amount ai / % ai

Question 14

Converting ai and product in liquid formulations:

Answer 14

lbs ai = gallons product x lbs ai per gallon
OR
Gallons product = lbs ai / lbs ai per gallon

Question 15

Converting recommended proportions to available tank size (pesticide per tank =)

Answer 15

(volume of spray tank x given herbicide amount) / spray mix amount given.

Question 16

PPA =

Answer 16

43,560 sq ft x (weight of collected material / (swath width x course length))

Question 17

GPA (boom-type sprayers) =

Answer 17

(GPM x 5940) / (MPH x nozzle spacing in inches)

Question 18

GPA (boom-less sprayers) =

Answer 18

(GPM x 495) / swath width in feet

Question 19

APM =

Answer 19

(swath width x distance traveled x 60) / (43,560 x time to cover distance)

Question 20

MPH =

Answer 20

(distance in feet x 60 minutes per hour) / (43,560 x time to cover distance)

Question 21

Course length =

Answer 21

43,560 / swath width

Question 22

amount of adjuvant=

Answer 22

% concentration x tank volume

Question 23

Sprayer output =

Answer 23

Treatment duration (ECT) x Application rate (GPM)

Question 24

Amount of KMnO4 neutralizer to add (Grams KMnO4 =)

Answer 24

ounces of piscicide used x multiplier value

Question 25

Multiplier values:
Clear
Turbid
Muddy

Answer 25

Clarity:
1.00
1.25
1.50

Question 26

Multiplier values:
Hot (>30C)
Warm (24-29C)
Cold (18-23C)

Answer 26

Water Temperature Values:
1.00
1.25
1.50

Question 27

Multiplier value =

Answer 27

clarity value + water temperature value

Question 28

ml product per minute =

Answer 28

discharge rate (CFS) x 1.7 x ppm

Question 29

Total ml product =

Answer 29

ml product per minute x ECT