C4 + 1.2 Chemical Equations Flashcards

1
Q

What state symbol is used for solids

A

s

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2
Q

What state symbol is used for gases

A

g

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3
Q

What state symbol is used for liquids

A

l

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4
Q

What state symbol is used for aqueous solutions

A

aq

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5
Q
Match the reactants to the products
CH^4 + 2O^2.              2CO^2 + 3H^2O
C^2H^5OH + 3O^2.      CO^2
C^3H^8 + 5O^2.            CO^2 + 2H^2O
C + O^2.                      3CO^2 + 4H^2O
A

CH^4 + 2O^2 = CO^2 + 2H^2O
C^2H^5OH + 3O2 = 2CO^2 + 3H^2O
C^3H^8 + 5O^2. = 3CO^2 + 4H^2O
C + O^2. = CO^2

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6
Q

Whats the word equation for water

A

Hydrogen + oxygen -> water

(Reactants). (Products)

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7
Q

What the symbol equation for water

A

H^2 (g) + O^2(g) -> H^2O(l) - unbalanced

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8
Q

What do chemical equations show

A

The reactants (substances you start with) and the products (new substances made) in a reaction

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9
Q

When balancing a chemical equation …

A

You can NEVER change a chemical formula e.g
H^2(g) +O^2(g) -> H^2O(l) Unbalanced

2H^2(g) + O^2(g) -> 2H^2O(l) Balanced

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10
Q

Why is it important that equations are balanced

A

Because atoms cannot be created or destroyed in a chemical reaction. This is the law of conservation of mass:

The total mass of products formed in a reaction is equal to the total mass of the reactants

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11
Q

How are the masses of atoms compared

A

By measuring them relative to atoms of carbon-12

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12
Q

How can you work out the relative formula mass of a compound

A

By adding up the relative atomic masses (top number on periodic table) of the elements in it, in the ratio shown by it’s formula

e.g h^2SO^4 = (1x2) +32 +(16x4) = 2 + 32 +64 =98

Al^2(SO^4)^3 = (27x2) +(32 x 3) + (16x12) =342

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13
Q

What is a mole

A

One mole of any substance is its relative formula mass, in grams

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14
Q

What is avogadro constant

A

The number of atoms, molecules, or ions in a mole. This is always the same: 6.02 x10^23 per mole

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15
Q

How do you calculate moles

A

Number of moles = mass (g) / Mr (relative atomic mass)
OR rearanged
mass(g) = number of moles x Mr

e.g number of moles in 19.6g of H^2SO^4
= 19.6/98 = 0.20mol.

Mass of 7.5x10^-3 moles of Al^2(SO^4)^3
= (7.5 x 10^-3) x 342 = 2.6g(2sf)

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16
Q

How do you calculate the percentage by mass of each element in a compound

A

e.g CO^2
Relative formula mass = 12+(2x16)=44
Percentage mass of C in CO^2 = 12/44 x 100 = 27.3%

17
Q

Add number in front of these compunds to make these equations balanced:
NH^3 + O^2 -> NO + H^2O
HNO^3 -> NO^2 + H^2O + O^2

A

4NH^3 + 5O^2 -> 4NO + 6H^2O

4HNO^3 -> 4NO^2 + 2H^2O + O^2

18
Q

What is the reactant that gets used up first in a reaction called?

A

Limiting reactant. This is the reactant which is NOT in excess

19
Q

What does the limiting reactant limit

A

The amount of product formed

20
Q

What mass of carbon dioxide is formed when 7.41 g of copper(II) carbonate decomposes on heating?
CuCO^3 -> CuO + CO^2

A

Moles CuCO^3 = 0.060mol

Mass CO^2 = 44x0.060 = 2.64g

21
Q

Hydrazine (N^2H^4) can be made by reacting ammonia with hydrogen peroxide. What mass of ammonia is needed to make 148g of hydrazine?

A

Moles N^2H^4 = 4.625 mol
Moles NH^3 = 2x4.625 = 9.25 mol
Mass NH^3 = 17 x 9.26 = 157g

22
Q

4.8g of Mg (24 Mr) reacting with 7.3 g of HCl (H=1Mr Cl = 35.5 Mr). Which is the limiting reactant
Mg(s) + 2HCl (aq) -> MgCl^2(aq) + H^2(g)

A

Find moles:
4.8/24 = 0.2mol. 7.3/(1+35.5) = 0.2mol

In reaction it is 2HCl so 0.2 x2 = 0.4 moles are needed.
HCl is the limiting reactant

23
Q
What is the equivalent measurement of:
1dm 
10dm
1dm^2 
1dm^3
A

1dm = 1/10m = 10cm
10dm=1m
1dm^2 =100cm^2
1dm^3 = 1000cm^3

24
Q

How to you calculate concentration (g/dm^3)

A

Amount of solute (g) / volume of solution (dm^3)

25
Q

How can you increase the concentration of an aqueous solution (2 ways)

A

Adding more solute and dissolving it in the same volume of its solution
OR / AND
evaporating off some of the water from the solution so you have the same mass of solute in a smaller volume of solution

26
Q

Why are some solutions more concentrated

A

A more concentrated solution has more solute in the same volume of solution than a less concentrated solution