C3 - Quantitative Chemistry Flashcards

1
Q

Compounds all have a relative formula mass. What is this?

A

The relative atomic masses of all the atoms in teh molecule formula added together

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2
Q

Which number is the relative formula mass?

A

The top number

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3
Q

Ar of Mg = 24, Ar of Cl = 35.5

Calculate the relative formula mass of MgCl2

A

95 (24 + 35.5x2)

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4
Q

What is the formula for percentage mass of an element in a compound?

A

Relative atomic mass x number of atoms in that one element
——————————————————————————x100
Relative formula mass of the total compound

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5
Q

A mixture contains 20% of iron ions by mass. What mass of iron chloride (FeCl2) would you need to provide the iron ions in 50g of the mixture?
Ar of Fe = 56, Ar of Cl = 35.5

A

1) Find the mass of iron in the mixture
-The mixture contains 20% iron by mass, so in 50g there will be 50 x 200/100 = 10g of iron
2) Calculate the percentage mass of iron in iron chloride
-Percentage mass of iron - 56/ 56+(2x35.5) = 44.09…%
3) Calculate the mass of iron chloride that contains 10g of iron
-Iron chloride contains 44.09…% iron by mass, so there will be 10g of iron in 10/ 44.09/100 = 23g
SO you need 23g of iron chloride to provide the iron in 50g of the mixture

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6
Q

How much is a mole? What is this number known as?

A

6.02 x 10^23

The Avogadro constant

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7
Q

One mole of any substance is just what?

A

An amount of that substance that contains 6.02 x 10^23 particles - these atoms could be atoms, molecules, ions or electrons

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8
Q

The mass of the number of atoms or molecules of any substance is exactly the same number of grams as the relative atomic mass (Ar) or relative formula mass (Mr) of the element or compound. True or false?

A

True - in other words, one mole of atoms or molecules of any substance will have a mass in grams equal to the Ar or Mr of that substance. Some examples:
Carbon has an Ar of 12. So one mole of carbon weighs exactly 12g
Carbon Dioxide, CO2, has an Mr of 44. So one mole of CO2 weighs exactly 44g

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9
Q

What is the formula for the amount of moles in a substance?

A

Number of moles = Mass in g (of an element or compound) / Mr (of the element or compound)

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10
Q

How many moles are there in 66g of carbon dioxide?

A

1) Calculate the Mr of CO2
- 12 + (16 x 2) = 44
2) Use the formula to find out how many moles there are
- Mass/ Mr —- 66/ 44 = 1.5 mol

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11
Q

What mass of carbon is there in 4 moles of CO2?

A

There are 4 moles of carbon in 4 moles of CO2

So the mass in 4 moles of carbon = 4 x 12 = 48g

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12
Q

In a chemical reaction, what happens to mass?

A

Mass is always conserved

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13
Q

If there is a change in mass during an experiment, what happened?

A

IF THE MASS INCREASES - Likely because one of the reactants is a gas found in air, and all the products of the reaction aren’t gaseous, so all the products are detected by the scale, including the new products from the new gas
IF THE MASS DECREASES - One of the products is a gas, so part f the mass is not weighed as it is now part of the air

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14
Q

What is the method for balancing equations using reacting masses?

A

For if you know the masses of the reactants and products in the reactions

1) Divide the mass of each substance by its relative formula mass to find the number of moles
2) Divide the number of moles of each substance by the smallest number of moles in the reaction
3) If any of the numbers aren’t whole numbers, multiply all the numbers by the same amount so that they all become whole numbers
4) Write out the balanced equation for the reaction by putting these numbers in front of the chemical formulas

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15
Q

Why will a reaction stop? What is that called

A

When one reactant is used up. That reactant is called a limiting reactant

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16
Q

If a reactant isn’t the one that is used up, what are the remaining reactants said to be?

A

In excess - they’re usually added in excess to make sure that all of the other reactant is used up

17
Q

Why would you add a reactant in excess?

A

To make sure that all of the other reactant is used up

18
Q

What does the amount of teh product depend on?

A

The limiting reactant

19
Q

How can you calculate the mass of a product formed in a reaction?

A

By using the mass of the limiting reactant and the balanced reaction equation (you could aso use this method to find the mass of a reactant needed to produce a known mass of a product)

1) Write out a balanced equation
2) Work out the Mr of the reactant and product that you want
3) Find out how many moles there are of the substance you know the mass of
4) Use the balanced equation to work out how many moles there’ll be of the other substance. In this case, that’s how many moles of product that will be made of this many moles of reactant
5) Use the number of moles to calculate the mass

20
Q

Calculate the mass of aluminium oxide formed when 135g of aluminium is burned in air

A

1) Write out the balanced equation
-4 Al + 3 O2 —> 2 Al2O3
2) Relative formula masses
-Al = 27 Al2O3 = (2 x 27) + (3 x 16) = 102
3) Calculate the number of moles of aluminium in 135g
-135/27 = 5
4) Look at the ratio of moles in the equation
-4 moles of Al react to produce 2 moles of Al2O3 - half the number of moles are produced
SO 5 moles of Al will react to produce 2.5 moles of Al2O3
5) Calculate the mass of 2.5 moles of aluminium oxide
- 2.5 x 102 = 255g

21
Q

What are the units for concentration?

A

g/dm3
cm3/dm3
mol/dm3
Units of mass/units of volume

22
Q

The more solute a substance is in a given volume…

A

(solute means the substance that’s dissolved)

The more concentrate the solution

23
Q

What is the formula for concentration?

A

Mass of solute/ volume of solvent

24
Q

What’s the concentration in g/dm3 of a solution of sodium chloride where 30g of sodium chloride is dissolved in 0.2dm3 of water?

A

30/ 0.2 = 150g/dm3

25
Q

How do you go from cm3 to dm3?

A

Divide by 1000

500cm3 —> 0.5 dm3

26
Q

What mass of salt would you need to dissolve in 0.4dm3 of water to make a solution with a concentration of 24g/dm3?

A

24 x 0.4 = 9.6g