Both Flashcards
Ammonium
NH4 +
Silver
Ag +
Zinc
Zn 2+
Scandium
Sc 3+
Hydroxide
OH -
Nitrate
NO3 -
Manganate
MnO4 -
Hydrogencarbonate
HCO3 -
Hydrogensulfate
HSO4-
carbonate
CO3 2-
Sulfate VI
SO4 2-
Sulfate IV
SO3 2-
Dichromate
Cr2O7 2-
Phosphate
PO4 3-
An acid is
A proton doner
Strong acid
Completely dissociates into its ions in aqueous solution
Weak acid
Partially dissociates into it ions in aqueous solution
Base
Proton acceptor
Alkali is
A base that dissolves in water and releases 0H-ions in aqueous solution
Salt
Produced when the H+ ion of an acid is replaced by a metal ion or NH4+
Acid + ammonia
Ammonium salt
Acid + metal oxide
Salt + water
Acid + metal hydroxide
Salt + water
Acid + metal
Salt + hydrogen
Acid + carbonate
Salt + water + carbon dioxide
Atom consists of
Protons and neutrons in the nucleus
Electron which orbit the nucleus
Proton, neutron, electron
Charge and mass
Proton +1 mass 1
Neutron 0 mass 1
Electron -1 mass negligible
Atomic number
Equal to the number of protons in the nucleus of an atom
Electrons are held in place by t
Attractive forces from the nucleus
Atoms are neutral because
Same number of protons and electrons
Isotopes
Atoms of the same element with different numbers of neutrons
Mass number
Equal to the number of protons and neutrons in the nucleus
Ions are formed by
Ions are charged because
Losing or gaining electrons
Because they have different numbers of Electrons from protons
Relative isotopic mass
The mass of an atom of an isotope compared with 1/12 of the mass of an atom of carbon 12
Weighted mean mass takes into account
The percentage abundance of each isotope
The relative mass of each isotope
Relative atomic mass
The weighted mean mass of an atom of an element compared with 1/12 of the mass of an atom of carbon 12
Mole
The amount of substance containing as many particles as there are carbon atoms in exactly 12 g of carbon 12
Molar mass
The mass in grams per mole of a substance
Units gmol^-1
Mile equation solid
Mole=mass/mr
Avagadros constant
6.02x10^23
Mol équation gas
Mole= volume/molar gas volume
24(dm3)
24000(cm3)
Mol équation solution
Dm3= c x v
Cm3= c x v/1000
Mol dm3 —> gdm3
X mr