Biochemistry II lectures 1&2 Flashcards

1
Q

What are monoclonal antibodies?

A

-used as therapeutic agents
-produced from a single B-lymphocyte clone and bind the same epitope
-100 FDA approved mabs

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2
Q

What are IgG antibody chains made up of?

A
  • 1 light and 1 heavy chain (2 of each in total)
    -constant and variable sequences
    -Light Chain: VLCL
    Heavy Chain: VH3CH
    -disulfide bonds stabilize regions
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3
Q

What are the fragments of Immunoglobulin?

A

-Fab (antigen recognition binding site)
-Fc (complement; activates complement-mediated cytotoxicity)

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4
Q

How are antibodies flexible?

A

-loops between Ig domains (hypervariable)
-protease sensitive; cleaves peptides

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5
Q

describe Fab (fragment antigen binding)

A

-fragment has 4 Ig domains
-2 Ig domains in each of the 2 polypeptide chains (1 Heavy; 1 Light chain)
-produced by proteolysis of whole antibody

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6
Q

describe scFv (single-chain variable fragment)

A

-engineered
-2 variable domains (1 heavy; 1 light chain)
-domains fused together with linker region (10-25 amino acids)

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7
Q

describe a Bispecific monoclonal antibody

A

-engineered
-2 antigen binding regions that recognize and bind 2 different antigens
-ex: BiTE; fusion of 2 different scFV’s and is bi-specific with one antigen binding region selective for T-Cells

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8
Q

Describe a Trifunctional antibody

A

-engineered mab; 3 binding sites
-antigen binding site in variable domains recognize epitope (T Cell CD3; antigen from a tumor cell; Fc part of the mab designed to bind to normal Fc receptor)

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9
Q

describe molecular recognition

A

-interaction of a protein molecule with a ligand (forms stable complex)
-measured by binding affinity
-high affinity=complex is favored over free P and L
-P and L binding is due to noncovalent interactions
-induced-fit structural changes

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10
Q

What is Kd?

A

-equilibrium dissociation constant
Kd= [P][L]/[PL]
-smaller Kd value, higher affinity

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11
Q

What is Specificity?

A

-affinity for one ligand over other ligands
-can also be affinity of ligand for one protein over another

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12
Q

What does a low Km mean?

A

-high affinity for substrate binding

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13
Q

Which choice best describes competitive binding between the enzyme substrate, S, and inhibitor, I?

A

-I binds the active site
-the region where I binds partially overlaps the active site
I induces a conformational change that prevents S binding

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14
Q

What happens to the apparent Vmax and Km with no inhibitor?

A

Km and Vmax are the same

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15
Q

What happens to the apparent Vmax and Km with competitive inhibition? (inhibitor binds only free E)

A

-Km is changed (Km[1+[I]/Ki)
-Vmax is same

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16
Q

What happens to the apparent Vmax and Km with non-competitive inhibition? (inhibitor binds free E and ES complex with equal affinity)

A

-Km is unchanged
-Vmax is changed (Vmax/(1+[I]/Ki)

17
Q

What happens to the apparent Vmax and Km with uncompetitive inhibition? (inhibitor only binds to ES complex)

A

-Km is changed (Km/(1+[I]/Ki)
-Vmax is changed (Vmax/1+[I]/Ki)
-both apparent Vmax and Km change by the same amount

18
Q

What does a Ki value indicate?

A

-dissociation constant that describes the binding affinity between the inhibitor and the enzyme
-concentration of inhibitor required to produce half maximum inhibition