Biochemistry II lectures 1&2 Flashcards
What are monoclonal antibodies?
-used as therapeutic agents
-produced from a single B-lymphocyte clone and bind the same epitope
-100 FDA approved mabs
What are IgG antibody chains made up of?
- 1 light and 1 heavy chain (2 of each in total)
-constant and variable sequences
-Light Chain: VLCL
Heavy Chain: VH3CH
-disulfide bonds stabilize regions
What are the fragments of Immunoglobulin?
-Fab (antigen recognition binding site)
-Fc (complement; activates complement-mediated cytotoxicity)
How are antibodies flexible?
-loops between Ig domains (hypervariable)
-protease sensitive; cleaves peptides
describe Fab (fragment antigen binding)
-fragment has 4 Ig domains
-2 Ig domains in each of the 2 polypeptide chains (1 Heavy; 1 Light chain)
-produced by proteolysis of whole antibody
describe scFv (single-chain variable fragment)
-engineered
-2 variable domains (1 heavy; 1 light chain)
-domains fused together with linker region (10-25 amino acids)
describe a Bispecific monoclonal antibody
-engineered
-2 antigen binding regions that recognize and bind 2 different antigens
-ex: BiTE; fusion of 2 different scFV’s and is bi-specific with one antigen binding region selective for T-Cells
Describe a Trifunctional antibody
-engineered mab; 3 binding sites
-antigen binding site in variable domains recognize epitope (T Cell CD3; antigen from a tumor cell; Fc part of the mab designed to bind to normal Fc receptor)
describe molecular recognition
-interaction of a protein molecule with a ligand (forms stable complex)
-measured by binding affinity
-high affinity=complex is favored over free P and L
-P and L binding is due to noncovalent interactions
-induced-fit structural changes
What is Kd?
-equilibrium dissociation constant
Kd= [P][L]/[PL]
-smaller Kd value, higher affinity
What is Specificity?
-affinity for one ligand over other ligands
-can also be affinity of ligand for one protein over another
What does a low Km mean?
-high affinity for substrate binding
Which choice best describes competitive binding between the enzyme substrate, S, and inhibitor, I?
-I binds the active site
-the region where I binds partially overlaps the active site
I induces a conformational change that prevents S binding
What happens to the apparent Vmax and Km with no inhibitor?
Km and Vmax are the same
What happens to the apparent Vmax and Km with competitive inhibition? (inhibitor binds only free E)
-Km is changed (Km[1+[I]/Ki)
-Vmax is same