Biochemistry Chapter 6: Carbohydrate Structure Flashcards

1
Q

Anomeric carbon glucose

A

C1 (where the carbonyl group is)

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2
Q

Anomeric carbon fructose

A

C2 (where the carbonyl group is)

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3
Q

Enantiomers

A

are mirror images, different in orientation at every chiral carbon

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4
Q

diastereomers

A

They are molecules that have the same molecular formula and sequence of bonded atoms (constitution) but differ in the spatial arrangement of their atoms in a way that they are not mirror images of each other.

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5
Q

Epimers

A

Diastereomers thats differ at 1 chiral center

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6
Q

Carbons numbered starting from the

A

Terminal C=O or the end closest to it

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7
Q
A

Hemiacetal

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8
Q
A

Hemiketal

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9
Q

Pentoses and hexoses can form cyclic forms featuring what kind of group?

A

Hemiacetal or hemiketal

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10
Q

Which carbons connect to form a pyranose?

A

C1 and C5

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11
Q

Which carbons join to form a furanose?

A

C1 and C4

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12
Q

OH groups points _____ in alpha-anomers

A

DOWN

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13
Q

OH groups points _____ in beta anomers

A

UP

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14
Q

An anomer

A

is a type of stereoisomer that arises from the formation of cyclic structures in sugars. Specifically, anomers differ in the configuration at the anomeric carbon, which is the carbon derived from the carbonyl group (aldehyde or ketone) during the cyclization of a sugar.

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15
Q

Glycosidic bond creates what?

A

Ketal/Acetal

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16
Q

Sucrose is made up of what monosaccarides?

A

glucose + fructose, α1→β2 glycosidic bond.

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17
Q

Lactose is made up of what monosaccarides?

A

galactose + glucose, β(1→4) glycosidic bond.

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18
Q

Maltose is made up of what monosaccarides?

A

glucose + glucose, α(1→4) glycosidic bond.

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19
Q

Amylose

A

linear glucose chain with α(1→4) bonds.

20
Q

Polysaccarides

A

long linear chains of glucose

21
Q

Amylopectin

A

like amylose, but with α(1→6) branches every 24–30 units.

22
Q

Starch (in foods) is made of what

A

20%–30% amylose + 70%–80% amylopectin.

23
Q

Glycogen

A

Polysaccaride. (energy storage in humans): α(1→4) bonds with α(1→6) branches every 8–12 units.

24
Q

Cellulose

A

indigestible fiber in plants; connected by β(1→4) bonds.

25
Q

Most common carb stereochemistry system

A

D/L system, based on orientation of D-glyceraldehyde — in a linear Fischer projection, a D-carbohydrate is one with the bottom-most -OH group pointing to the right.

26
Q

Virtually all biological carbohydrates are (D or L)?

27
Q

How to find number of stereoisomers

A

2^X = number of stereoisomers where X = number of chiral centers

28
Q

Each hexose will have how many enatiomers, epimers and diastereomers?

A

one enantiomer (differing by D vs. L).
four epimers (one epimer for each stereocenter).
14 diastereomers.

29
Q

Reducing sugars

A

terminal C=O in aldoses can easily be oxidized to carboxylic acids. Aldoses are reducing agents/sugars. Reducing sugars = reducing agents

30
Q

disaccharides where an element can be converted into a linear aldose are

A

reducing sugars

31
Q

Are Ketose monosaccharides reducing sugars?

A

Yes because they can tautomerize to aldoses

32
Q

Is sucrose a reducing sugar?

33
Q

Are starch and polymers reducing sugars?

A

No because only one end of the sugar gets reduced

34
Q

Why sucrose alpha1 - beta2 glycosidic bond?

A

The glucose (C1) is in the α-configuration (OH group on the anomeric carbon is trans to the CH₂OH group).
The fructose (C2) is in the β-configuration (OH group on the anomeric carbon is cis to the CH₂OH group).

35
Q

Anomeric Carbon

A

An anomeric carbon is a carbon atom in a sugar molecule that forms a stereocenter when the sugar cyclizes

In the open-chain form of a sugar, the anomeric carbon is the carbonyl carbon of the aldehyde or ketone functional group.
In the cyclic form of a sugar, the anomeric carbon is the carbon atom bonded to the ring oxygen and a hydroxyl group.

36
Q

The stereochemical designators α and β distinguish between:

A

epimers at anomeric carbon

37
Q

Difference between AMP and cAMP

A

AMP = standard nucleotide with 1 phosphate group
cAMP = A modified form of AMP where the phosphate group forms a cyclic bond with both the 3’ and 5’ carbons of the ribose, creating a ring-like structure.

AMP = Plays a role in energy metabolism and nucleotide synthesis.

cAMP = second messenger
t is synthesized from ATP by the enzyme adenylyl cyclase in response to signals like hormones (e.g., epinephrine, glucagon) and activates protein kinase A (PKA), leading to various cellular responses.

38
Q

α (Alpha) anomer → The OH on the anomeric carbon (C1) is

A

opposite (trans) to the CH₂OH group (C6).

39
Q

β (Beta) anomer → The OH on the anomeric carbon (C1) is on the

A

same side (cis) as the CH₂OH group (C6).

40
Q

Fischer projection: L Glucose

A

The D- or L- configuration is determined by the position of the OH group on the highest-numbered chiral carbon (which is C5 in glucose).

L-glucose → OH on C5 is on the left.

41
Q

Fischer projection: D Glucose

A

The D- or L- configuration is determined by the position of the OH group on the highest-numbered chiral carbon (which is C5 in glucose).

D-glucose → OH on C5 is on the Right.

42
Q

Hawthorn projection: L Glucose

A

In the Haworth projection, cyclization changes the orientation of the CH₂OH (C6) group

L-glucose → CH₂OH (C6) is below the ring.

43
Q

Hawthorn projection: D Glucose

A

In the Haworth projection, cyclization changes the orientation of the CH₂OH (C6) group

D-glucose → CH₂OH (C6) is above the ring.

44
Q

Difference between L, D and alpha beta for naming monosaccarides

A

The D- or L- configuration is determined by the position of the OH group on the highest-numbered chiral carbon (which is C5 in glucose).

Alpha (α) and Beta (β) anomers are determined by the orientation of the OH group on the anomeric carbon (C1) when the sugar cyclizes into a ring form.

45
Q

bond that links monosaccharides together in an oligosaccharide is a special type of acetal linkage known as a

A

glycoside bond