bio final part B Flashcards

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1
Q

stages in mitosis

A

prophase:
1. chromatin condense to chromosome
2. nuclear envelop and nucleolus disappear
3. centrosome separate and form spindle fibre

metaphase:
1. each centrosome reach a pole
2. chromosome line up across the metaphase plate(equator)
3. spindle fibre attached to chromosome

anaphase
1. chromosome separate become 2 chromatid
2. chromatid move to opposite end of the cell

telophase
1. chromatid unfold back to chromatin
2. new nuclear envelope formed

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2
Q

centriole in animal vs plant cells

A

centriole are found in animal cell, absent in almost all plant cell (found in some lower plant cell)
-centriole contain 2 cylindrical structure
-used for spindle fiber formation (plant cell have spindle fibre outside the nuclear envelope so no need centriole during cell division)

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3
Q

role of mitosis

A
  1. growth of multicellular organism
  2. replacement of cell and repair of tissues
  3. asexual reproduction
  4. immune respond
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4
Q

effect of drug in treating cancer

A

chemotherapy
-kill fast growing cell (involving cancer cell and healthy white blood cell) by damage the gene inside the nucleus of cell
-fewer normal white blood cell to fight pathogens (will get infection easily)
-permanent damage to heart, lungs, liver,….

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5
Q

features in prophase, metaphase and interphase

A

interphase:
G1 : cell make RNA, enzyme and other protein needed for growth
S: signal for another cell division received, DNA replication occur
G2: cell continue to growth, new DNA checked, repair error and increase production of tubulin

prophase:
1. chromatin condense to chromosome
2. nuclear envelop and nucleolus disappear
3. centrosome separate and form spindle fibre

metaphase:
1. each centrosome reach a pole
2. chromosome line up across the metaphase plate(equator)
3. spindle fibre attached to chromosome

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6
Q

protein related to DNA

A
  1. protein histone - bind to DNA, give chromosome shape and control the activity of gene
  2. DNA control protein synthesis (transcription: transcribing a piece of dna into rna) (translation: convert mrna code into amino acid sequence within a protein)
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7
Q

function of spindle fibre in mitosis

A

-spindle fibre attach to chromosome during metaphase
-separate chromosome and pulls the chromatid towards opposite poles during anaphase
-allow 2 daugther cell to be completely identical

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8
Q

importance of cell cycle and effect of failed cell cycle

A

importance:
1. dna duplication and produce 2 genetically identical daughter cell
2. maintain normal metabolic function
3. gamete formation
4. repair and regenerate damaged cell

effect of failed cell cycle:
1. uncontrolled mitosis (cancer)
2. mutation - early cell death
3. not passing genetic information
4. no cell growth/reproduction
5. not able to replace damaged cell

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9
Q

stages on protein synthesis

A

transcription:
1. transcribing a piece of DNA into RNA

translation:
1. synthesis of protein from mRNA template
2. convert mRNA code into an amino acid sequence within a protein

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10
Q

process of transcription

A

site of transcription=nucleus
1. part of DNA unwind
2. mRNA use a single strand as template
3. 3 RNA nucleotide base joined together by enzyme RNA polymerase
4. enzyme RNA polymerase continuously add nucleotide to the growing mRNA strand
5. at stop codon, the H-bond that hold the DNA-RNA sequence are broken
6. double stranded DNA reform
7. mRNA leave the nucleus via nuclear pore

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11
Q

structure of tRNA and its function in translation

A

L-shape structure
single stranded
contain 1 amino acid attachment, D-loop, T-loop, anticodon loop(triplet of bases)

function:
1. carry specific amino acid to the ribosome to build protein
2. acts as link between the genetic code in mRNA and the amino acid that make up protein

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12
Q

mRNA vs DNA

A

mRNA and DNA
nucleotide as monomer
posses 4 nitrogenous bases
exhibit a phosphate backbone

mRNA
has ribose
single stranded structure
has uracil as nitrogen base
carries information from DNA to ribosome

DNA
has deoxyribose
double stranded structure
has thymine as nitrogen base
holds genetic information for the protein

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13
Q

state purine bases

A

adenine (pair with thymine/uracil)
guanine (pair with cytosine)
#pair with pyrimidines

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14
Q

anticodon on tRNA

A

adenine, guanine, uracil, cytosine

located at one end of tRNA molecule
trinucleotide sequence
complementary to codon
has uracil replacing thymine in DNA

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15
Q

hydrogen bond between mRNA and tRNA anticodon

A

(between codon and anticodon)
breaks when reach stop codon

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16
Q

calculate percentage of bases in DNA

A

Chargaff’s rule
A=T, G=C
A+T+G+C=100%

17
Q

bonding between amino acid in translated polypeptide

A

peptide bond

18
Q

identify dominant allele

A

always expressed in phenotype in both heterozygous and homozygous
written as uppercase letter

19
Q

codominance

A

both allele can be expressed in the phenotype at the same time
exp. blood type

20
Q

genetic diagram of codominance

A

parents phenotype : A B
parents genotype: IAIO IBIO
gamete genotype: (IA) (IO) (IB) (IO)
offspring genotype IAIB IOIB IAIO IOIO

21
Q

compare haploid and diploid cell

A
  1. haploid contain 1 complete set of chromosome(n) while diploid contain 2 complete set of chromosomes(2n)
  2. haloid cell has 23 chromosome in nucleus while diploid cell has 46 chromosome
  3. haploid cell involved in sexual reproduction while diploid contain DNA necessary for protein synthesis and cell function
  4. example of haploid cell is gamete such as sperm and egg while diploid cell is somatic cells such as nerve and muscle
22
Q

type of isolation

A

pre-zygotic (temporal, ecological, behavioral, mechanical)
–prevent gamete of 2 individual from fusing to form a zygote

post-zygotic (hybrid inviability, hybrid infertility, hybrid breakdown)
–prevent development of a fertile individual from a zygote

23
Q

process of isolation

A

temporal – 2 species mate at different times of year. exp. breed during summer/spring

ecological – 2 species occupy different habitat. exp. lion and tigers

behavioral – 2 species have different courtship behaviors. exp. certain group of bird only respond to species-specific mating calls

mechanical – physical different prevent copulation/pollination. exp. certain breed of dog morphologically incapable of mating due to size

hybrid inviability – hybrid produced but fail to develop to reproductive maturity. exp. certain type of frog from hybrid tadpoles die before the become a frog

hybrid infertility – hybrid fail to produce functional gametes. exp. mules are sterile hybrid resulting from mating between horse and donkey

hybrid breakdown – F1 hybrid fertile but F2 generation does not develop properly. exp. offspring of hybrid copecods have less potential for survival and reproduction.

24
Q

importance of natural selection

A
  1. lead to speciation (1 species give rise to a new and distinctly different species)
  2. increase the chance of survival
  3. adapt to the environment
25
Q

advantage using mtDNA in studying closeness in between species

A
  1. no crossing over
  2. faster mutation
  3. constant mutation
  4. smaller/fewer gene in mtDNA
26
Q

why length is identified as continuous variation

A
  1. length is quantitative variable
  2. no distinct categories
  3. within a range between 2 extreme
  4. may cause by gene and environment
27
Q

how natural selection occurred in choosing longer/shorter feature

A

environment—dense forest: shorter; open grassland: longer limb for running

reproductive success— longer: more attractive

28
Q

calculate percentage of heterozygous population(2pq) using Hardy-Weinberg equation

A

p+q=1

p= frequency of dominant allele
q= frequency of recessive allele

p2+2pq+q2=1

p2=chance of being homozygous dominant
q2=chance of being homozygous recessive
2pq=chance of being heterozygous