Basics Flashcards
- Ultimate test of any theory?
Ability to predict real world events.
- All economic models incorporate three common elements. What are they?
- the ceteris paribus assumption
- supposition that economic decision makers seek to optimize something.
- careful distinction between “positive” and “normative” questions.
- Inputs into economic models are ______ variables. Basic examples?
Exogenous variables.
Households: Prices of goods.
Firms: Prices of inputs and output.
- Output of economic models are _________ variables. Examples?
Endogenous variables.
Households: Quantities bought.
Firms: Output produced, inputs hired.
- Formula for elasticity?
– e(y,x) = (dy/dx)(x/y)
e(y,x) = elasticity of y given x.
– If y is linear function of x: y = a + bx, then e(y,x) = b * (x/y)
– If functional relationship between x and y is exponential: y = a*x^b, then elasticity is a constant: b
- Necessary and sufficient conditions for a maximum.
Necessary (first order condition): f’(q) = 0 (slope = 0)
f’(q) is df/dq. All partial derivatives = 0.
Sufficient condition (second-order condition): f''(q) < 0. f''(q) is d^2f/dq^2 (second order partial derivative).
- What is the importance of “own” 2nd partial derivative [f(ii)]?
Shows how marginal influence of x(i) on y changes as the value of x(i) increases.
A negative value for f(ii) indicates mathematically the idea of diminishing effectiveness. Provides info about curvature of the function.
- What is Young’s Theorem?
The order in which 2nd order partial derivation is conducted doesn’t matter: f(ij) = f(ji).
Visual: Gain hiker experiences on a mountain depends on the direction and distance, but not on the order in which these occur.
- What is the implicit function and what is an example of the implicit function?
Value of function is held constant to examine the implicit relationship among independent variables. An example is the “envelope function.”
e.g. of implicit function: y = f(x1, x2) –> hold y constant yields x2 = g(x1). Derivative of g(x1) is related to partial derivative of original funtion f. Derives explicit expression for trade-offs between x1 and x2.
OC (of PPF) = dx(2)/dx(1) = -f(1)/f(2) –> Change in x(2) resultant from a change in x(1) is equal to the negative of the partial deriv. w.r.t. x(1) divided by the partial deriv. w.r.t. x(2).
- With respect to the Production Possility Fronter (PPF), what does dx(2)/dx(1) = -f(1)/f(2) demonstrate?
Concavity of PPF –> As output of x(1), i.e. “x”, increases have to give up increasingly more units of x(2), i.e. “y.”
Resources better suited for x are used up and resources better suited for y are marginal for x so, need more y resources in the propduction of x.
- Define the envelope theorem.
It is a mathematical result. The change in max. value of a function brought about by a change in a parameter can be found by partially differentiating the function w.r.t. the parameter in question (when all other variables take on their optimal values).
- Envelope shortcut –> one variable case.
If y = -x^2 + ax , where a = constant.
Optimal value of x for any a = dy/dx –> x* = a/2
dy/da = ∂ y/∂ a [at x = x(a)] = ∂(-x^2 + ax) / ∂ (a)
= x*(a) = a/2
- Envelope theorem –> many variable case.
y = f(x1, x2, … , x(n), a) , where a is a parameter
Assuming SOC are met, implicit function theorem applies and ensures solution of each x(i) as a function of parameter a, e.g. x(1) = x(1) (a).
y = f[x1(a), x2(a), … , x(n)(a), a] –> Differentiate w.r.t. a yields:
dy/da = (⍺f/⍺x1 * dx1/da) + (⍺f/⍺x2 * dx2/da) + … + ⍺f/⍺a
…but because of FOC, all of the above terms except the last are zero.
–> dy*/da = ⍺f/⍺a at optimal values for all x.
- Solving constrained maximization with the lagrange multiplier (LM) results in what two properties?
- x’s obey the constraint ‘cuz ⍺L/⍺λ imposes that condition.
- Among all values of x’s that satisfy the constraint, the partial differentiation equations will make L (and hence f) as large as possible (assuming SOC are met).
- Interpret the Lagrange Multiplier LM.
λ provides an implicit value or “shadow price” to the constraint, i.e. provides measure of how an overall relaxation of constraint will impact value of y.
λ = [MB of x(i)] / [MC of x(i)].
– High λ indicates y could be increased by relaxing the constraint (high MB/MC ratio).
– Low λ indicates not much gained by relaxing constraint.
– λ = 0 indicates constraint isn’t binding.