Atomic structure, ions, Isotopes and formulae UNIT 2 Flashcards
Unit 2 OCR A
What is meant by the term isotopes? [1]
OCR DEFINITION:
isotopes as atoms of the same element with
different numbers of neutrons and different
masses
MARK SCHEMES:
ATOMS(S) of an element
AND
with different numbers of neutrons (and with different
masses) ✔
EXAMINERS REPORT:
This question was well answered. The one
common error made was to omit any
reference to ‘atoms’ and so answers in
terms of the same element having different
number of neutrons received no credit.
Candidates should be advised to avoid
unnecessary references to isotopes having
the same number of electrons.
A twenty pence coin contains copper and nickel.
Copper and nickel each exist as a mixture of isotopes.
State the similarities and differences between the atomic structure of isotopes of the same element [2]
Similarities:
(Same) number of protons AND electrons ✓
Differences: (Different) number of neutrons ✓
Examiner’s Comments
Most candidates identified that different
isotopes had the same number of protons
but then omitted electrons. The different
number of neutrons was usually seen
although sometimes atomic mass was
shown instead
Explain what is meant by the term relative atomic mass of an element [2]
(Weighted) mean/average mass of an atom ✓
compared with 1/12th mass of carbon-12
OR compared with mass of carbon-12 which is 12 ✓
Examiner’s Comments
Most candidates were given at least one
mark but lost the second mark due to
omitting the word “atom”, or “mean” or “one-twelfth”
A sample of strontium has a relative atomic mass of 87.73.
The sample consists of:
- 82.9% Sr-88
- 6.9% Sr-87
- one other isotope.
Determine the other isotope of strontium in the sample.[2]
Use of isotope data
Use of 87 × 6.9 AND 88 × 82.9 AND 10.2 anywhere
✓
Calculation of isotopic mass
(100x87.73)-(87x6.9)-(88x82.9)
Ans/10.2= 86 or 86.03
Examiner’s Comments
Algebra was used very well here and
allowed most candidates to obtain at least
one mark, with the majority obtaining 2
marks
This question is about atomic structure and the compounds of calcium, nitrogen and oxygen.
Most elements contain different isotopes.
State two differences between isotopes of the same element. [1]
TWO correct responses from ✓
- Different numbers of neutrons
- Different (atomic) masses/mass numbers
- Different physical properties
Physical required
Misconception
When discussing the mass of individual
isotopes, ‘mass’ or ‘mass number’ should
be used. The relative atomic mass is the
weighted average mass of all of the
isotopes of an element, and is consequently
the incorrect term to use in this context.
A sample of silicon is analysed by mass spectrometry.
The mass spectrum shows peaks with the relative abundances below.
* 28Si 92.23%
* 29Si 4.68%
* 30Si 3.09%
Calculate the relative atomic mass of silicon in the sample.
Give your answer to two decimal places. [2]
FIRST CHECK ANSWER ON THE ANSWER LINE
IF answer = 28.11 (to 2 DP) award 2 marks
OR 28.1086 OR 28.109 ✓
= 28.11 (to 2 DP) ✓
Examiner’s Comments
Almost all candidates followed a well-learnt
procedure to complete the calculation.
Despite being in the rubric to the question,
some candidates did not give an answer to
two decimal places. Others made a
rounding error in reducing 28.1086 to two
decimal places, with 28.10 and 28.12 being
common errors
One coin has a mass of 5.00 g and contains 84.0% of copper, by mass.
Calculate the number of copper atoms in one coin.
Give your answer in standard form and to three significant figures.[2]
FIRST CHECK ANSWER ON THE ANSWER LINE
If answer = 3.97 × 1022 (from 63.62) award 2 marks
If answer = 3.98 × 1022 (from 63.5) award 2 marks
____________________________
Using 63.62: correct Ar of Cu from 21(b)(i)
See bottom of answer zone
Cu atoms = 0.0660 × 6.02 × 1023 = 3.97 × 23 1022 ✓
Must be calculated in standard form AND to 3 SF
OR
Using 63.5: Ar of Cu from periodic table
Cu atoms = 0.0661 × 6.02 × 1023 = 3.98 × 1022 ✓
Must be calculated in standard form AND to 3 SF
Examiner’s Comments
This part was generally well answered with
most candidates processing the data
correctly. Candidates sometimes failed to
consider 84% or rounded incorrectly in
places.
Answer = 3.97 × 10(22) atoms
Bromine has two isotopes, Br–79 and Br–81. The relative atomic mass of bromine is 79.9.
Calculate the percentage of Br–79 atoms in a sample of bromine. [2]
55% ✔
Examiner’s Comments
Although some very good algebraic
attempts were seen in this variant of an Ar
calculation, it was clear from the working
shown that even when the right answer was
given, some candidates had not got to this
answer in a systematic way but often in a
very muddled and confused manner.
Different isotopes of antimony have the same chemical properties.
Explain why. [1]
same number of electrons in outer shell
OR
same electron configuration OR electron structure ✔
Examiner’s Comments
The key reason why isotopes show similar chemical properties (ie because they have
an identical numbers of electrons in the
outer shell) was not always understood.
Weaker candidates struggled and gave
answers referring to the number of protons
remaining the same. Even slightly improved
answers referring to the total number of
electrons remaining the same did not deliver
the required level of detail.
Define the term relative atomic mass.[3]
The (weighted) mean mass of an atom (of an
element)
OR
The (weighted) average mass of an atom (of an
element) ✔
compared with 1 / 12th (the mass) ✔
of (one atom of) carbon-12 ✔
Examiner’s Comments
This familiar recall question was well
answered by all candidates. In the past
there have been problems with weaker
candidates omitting reference to average or
mean mass, or muddling comparisons by
referring to a single atom of the element and
then a mole of carbon-12. On this occasion,
however, such errors were rare and the
answers seen were extremely strong.
A sample of antimony, Ar = 121.8, was analysed and was found to consist of 60% 121Sb
and one other isotope.
Determine the mass number of the other isotope in the sample of antimony.[1]
123 ✔
Zinc carbonate, ZnCO3, reacts with dilute hydrochloric acid.
A student reacts a sample of ZnCO3 with an excess of dilute hydrochloric acid in a test-tube.
i. Describe what the student would see during this reaction.[1]
ii. Write the equation for the reaction between ZnCO3 and dilute hydrochloric acid.[1]
i) i. Effervescence OR fizzing OR bubbling OR gas
produced
AND
The solid OR zinc carbonate would dissolve OR
disappear ✓
Examiner’s Comments
Most candidates realised that effervescence and
dissolving would be seen.
ii. ZnCO(3) + 2HCl ◊ZnCl(2) + CO(2) + H(2)O ✓
Examiner’s Comments
Nearly all candidates were able to write the
equation successfully – including those who had
omitted effervescence in (i).
Compounds of calcium have many uses.
i. Identify a compound of calcium that could be used to convert a soil pH from 5.8 to 7.5.
[1]
ii. Calcium phosphide, Ca3P2, is an ionic compound used in rat poison.
Calcium phosphide can be prepared by reacting calcium metal with phosphorus, P4.
Write the equation for the reaction of calcium with phosphorus to form calcium
phosphide.
[1]
iii. Draw a ‘dot-and-cross’ diagram to show the bonding in calcium phosphide, Ca3P2.
Show outer electrons only.
i.Ca(OH)2 OR Calcium hydroxide
OR CaO OR Calcium oxide ✓
Examiner’s Comments
The unusual equation involving P4 molecules
was answered well. Weaker candidates
assumed that phosphorus was monatomic and
consequentially lost credit.
ii 6Ca + P4 ◊ 2Ca3P2 ✓
Examiner’s Comments
This potentially difficult dot-and-cross diagram of
the ions present was done well by candidates.
iii Ca with 8 (or no) electrons AND phosphide ion with
dot-and-cross outermost octet ✓
Three Ca ions AND two phosphide ions with correct
charges ✓
Gallium, atomic number 31, is in Period 4 of the Periodic Table. Gallium is a Group 3 element.
Predict the formula of a gallium ion.[1]
Ga3+ ✓
This question is about compounds of Group 3 elements.
Aluminium will combine directly with fluorine.
Write the equation for the reaction between aluminium and fluorine[1]
2Al + 3F2 → 2AlF3 ✔
Examiner’s Comments
Although the formula of AlF3 was not given, this
question was well answered. When the mark
was not awarded it was rarely because of errors
in the formula for AlF3, but more in the ratio of
the reactants or in fluorine not being given as
diatomic. Occasionally, the symbol for fluorine
was given as Fl.