atomic structure Flashcards
State two differences between the ‘plum pudding’ model and the model of atomic structure used today.
Assume current model unless otherwise stated.
Statement about the nucleus:
(Central) nucleus contains protons and neutrons.
Statement about electrons
Electrons are now arranged in energy levels/shells/orbitals
why is na smaller than F in NaF
Both Na+ and F– same electron arrangement (1s22s22p6) or isoelectronic
Sodium (ion) has more protons so attracts (outer) electrons closer / Sodium (ion) has more protons so stronger attractions for (outer) electrons
Explain how ions are detected and relative abundance is measured in a TOF mass spectrometer.
ion hits the detector / negative plate and gains an electron
Not positive plate
(relative) abundance is proportional to (the size of) the current
Explain why the second ionisation energy of calcium is lower than the second ionisation energy of potassium
m1. n Ca(+) (outer) electron(s) is further from nucleus Or Ca(+) loses electron from a higher (energy) orbital Or Ca(+) loses electron from a 4(s) orbital or 4th energy level or 4th energy shell and K(+) loses electron from a 3(p) orbital or 3rd energy level or 3rd energy shell
m2 More shielding (in Ca+)
This question is about s-block metals.
(a) Give the full electron configuration for the calcium ion, Ca2+
1s2 2s2 2p6 3s2 3p6 (4s0)
In the early twentieth century the apparatus shown in the diagram was used to investigate atomic structure. When He2+ particles were fired at a thin sheet of gold, most of the particles were detected at point P.
What conclusion can be drawn from the detection of He2+ particles at point P?
A
Gold atoms contain electrons.
B
Gold atoms contain protons.
C
Gold atoms contain neutrons.
D
Gold atoms are mainly empty space.
D
When He2+ particles were fired at a thin sheet of gold, about 1 in 8000 of the particles were detected at point Q.
What conclusion can be drawn from the detection of He2+ particles at point Q?
A
Gold atoms have a small, positive nucleus.
B
Gold atoms have electrons in orbitals.
C
Gold consists of ions in a sea of delocalised electrons.
D
Gold atoms have more protons than He2+ particles.
A
Write an equation, including state symbols, to represent the process that occurs when the third ionisation energy of manganese is measured.
Mn2+ (g) ⟶ Mn3+ (g) + e−
State which of the elements magnesium and aluminium has the lower first ionisation energy.
Explain your answer.
Al
Mg then CE = 0
(Outer) electron in (3)p sublevel / orbital
Not just level or shell
Higher in energy / further from the nucleus
so easier to remove OWTTE