Atomic Structure Flashcards

1
Q

What is the degeneracy of the p; d; f orbitals

A

p orbital = 3 fold

d orbital = 5 fold

f orbital = 7 fold

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2
Q

What are the reasons for the energy ordering

A
  1. Repulsions among electrons
  2. Relative amplitudes of the radial portions of the atomic orbital wave functions - compare the extent to which the radial portions of the various wave functions penetrate to the nucleus
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3
Q

Explain Radial penetration of the wave functions

A

An electron in an atomic orbital with electron density close to the nucleus is stabilized by close interaction with the positive charge of the nucleus.

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4
Q

Explain the stability ordering

A
  • For any n: s-orbital most electron density close to the
    nucleus, then p, d, f.
  • Order of stability: s > p > d > f
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5
Q

Aufbau principle

A
  • build up from the bottom
  • orbitals of lowest energy first
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6
Q

Hund’s rule

A
  • Where orbitals are available in degenerate sets, maximum spin multiplicity preserved (electrons are not paired until each orbital in a degenerate set is half-filled)
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7
Q

Pauli exclusion principle

A
  • No two electrons may have the
    same set of 4 quantum numbers
  • Two electrons in the same orbital
    must have opposite signs

ms = +½ and ms = −½

  • maximum 2 electrons per orbital
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8
Q

What is the orbital order

A

1s 2s. 2p. 3s. 3p. 4s. 3d 4p. 5s. 4d. 5p. 6s. 4f. 5d. 6p. 7s.

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9
Q

What electron configuration does period 3 start with

A

[ Ne ] 3s^1

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10
Q

Explain the electron configuration of each period

A
  • Period 4 started with [ Ar ] 4s, then 3d and ended with 4p
  • Period 5 starts with 5s, then 4d and ends with 5p.
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11
Q

What is the electron configuration for 24Cr

A

[Ar] 4s13d5 (not [Ar] 4s23d4)

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12
Q

What is the electron configuration for 29Cu

A

Ar] 4s13d10 (not [Ar] 4s23d9)

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13
Q

What is the electron configuration for 42Mo:

A

[Kr] 5s14d5 (not [Kr] 5s24d4)

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14
Q

What is the electron configuration for 47Ag:

A

[Kr] 5s14d10 (not [Kr] 5s24d9)

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15
Q

What is the electron configuration for 41Nb

A

[Kr] 5s14d4 (not [Kr] 5s24d3)

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16
Q

What is the electron configuration for 44Ru

A

[Kr] 5s14d7 (not [Kr] 5s24d6)

17
Q

What is the electron configuration for 45Rh

A

[Kr] 5s14d8 (not [Kr] 5s24d9)

18
Q

What is the electron configuration for 46Pd

A

[Kr] 5s04d10 (not [Kr] 5s24d8)

19
Q

What is the electron configuration for 78Pt

A

[Xe] 6s15d9 (not [Xe] 6s25d8)

20
Q

What is the electron configuration for 79Au

A

[Xe] 6s15d10 ( not [Xe] 6s25d9)

21
Q

What is the electron configuration for 64Gd

A

[Xe] 6s2 5d1 4f7 (not [Xe] 6s25d04f8)

22
Q

Explain Mendeleev

A
  • Arranged in horizontal rows
  • Related elements in vertical columns
23
Q

Explain Moseley

A
  • Proper sequence: atomic number
  • Vertical columns contain chemically similar elements and electronically similar atoms
  • Periodic arrangement of electron configurations give the same result as what Mendeleev deduced from chemical observations.
24
Q

Explain Hund’s rule fully

A
  1. Electrons make use of different orbitals as far as possible
    (within a set of degenerate orbitals)

A consequence of the charge of the electrons – electrons minimise repulsive forces by occupying different p orbitals

  1. Parallel spins (same value of ms) are used until the
    Pauli exclusion principle requires pairing of spins
    Early pairing of spins leads to less stable arrangements
25
Q

Explain Most stable electronic state

A

The state with maximum spin multiplicity (largest number of (un)paired electron spins)

26
Q

What does Hund’s rule imply

A
  1. Spreading out of electrons as wide as possible in the space surrounding the nucleus
  2. This spreading of electron density leads to extra stability
27
Q

What does the amount of nuclear effective charge felt by an electron depends on

A
  1. The type of orbital in which the electron is housed
  2. The ability of other electrons in more penetrating orbitals to screen (or shield) the electron from the
    nucleus
28
Q

When will an electron experience the greatest effective nuclear charge

A
  • An electron will experience the greatest effective nuclear charge when housed in
    an s orbital (for any given n), than p, etc. (Reason for Aufbau)
  • Geometry and orientation of the p orbitals makes them poor at shielding one
    another from the nucleus.
29
Q

Explain poor electron shielding

A

Where screening of an electron is poor, the effective nuclear charge is high

( In terms of Hund’s rule: Electrons spread out into a degenerate set of orbitals in
order to experience the maximum effective nuclear charge )

30
Q

Explain Slater’s screening constant, σ

A
  • Slater proposed an empirical constant that represents the cumulative extent to which the other electrons of an atom shield (or screen) any particular electron from the nuclear charge
  • Z* is always smaller than Z (the electron is screened or shielded from Z by an
    amount σ).
  • The value of σ for the electron in question is the cumulative total provided by
    the other electrons of the atom– calculated using Slater’s rules.
31
Q

To conclude

A

Z* increase continually from left to right across the rows of the periodic table because of imperfect shielding