Atomic Structure Flashcards
Identify and describe protons, neutrons and electrons in terms of their relative charges and relative masses
Mass, charge
Proton- 1, +1
Neutron- 1, 0
Electron- 1/1840 (negligible), -1
Deduce the behaviour of beams of protons, neutrons and electrons in an electric field
Angle of deflection is proportional to charge/mass
Define isotopes
Atoms of the same element with same number of protons but different number of neutrons
Write the electronic configuration for 14Si
1s2 2s2 2p6 3s2 3p2
Write the electronic configuration for 35Br+
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4
Write the electronic configuration for 16S2-
1s2 2s2 2p6 3s2 3p6
Write the electronic configuration for 29Cu
1s2 2s2 2p6 3s2 3p6 3d10 4s1
Write the electronic configuration for 24Cr
1s2 2s2 2p6 3s2 3p6 3d5 4s1
Draw the shape of d(xy) orbital
Two lobed orbitals, both cutting origin along xy plane
Draw the shape of d(x^2-y^2)
Two lobed orbitals, one lying on x-axis other lying on y axis
Draw the shape of d(z^2)
One lobed orbital on z axis with a donut orbital round the middle
First ionisation energy ____ down the Group, because ____
First ionisation energies GENERALLY decrease down the Group
The number of electron shells increases, increasing shielding experienced by the valence electrons and the distance between the nucleus and valence electrons.
Despite increasing nuclear charge, electrostatic forces of attraction between the nucleus and valence electrons decreases hence it requires less energy to remove a valence electron down the Group.
First ionisation energy ____ across the Period, because ____
First ionisation energies GENERALLY increase across the Period
The number of electron shells remains the same while the number of protons increases, hence shielding experienced by valence electrons is the same. Due to increasing effective nuclear charge, electrostatic attraction between nucleus and valence electrons increases and more energy is required to remove a valence electron across the Period.
Why is the first ionisation energy of B lower than Be?
B: 1s2 2s2 2p1
Be: 1s2 2s2
The 2p removed from B is from a higher energy subshell than the 2s electron removed from Be. Hence it required less energy to remove the electron from B.
Which first ionisation energy is higher: N or O?
Why?
N: 1s2 2s2 2p3 (11)(11) (1)(1)(1)
O: 1s2 2s2 2p4 (11)(11) (11)(1)(1)
The electron removed from O was a paired electron while the electron removed from N was an unpaired electron. Hence the electron removed from O experienced inter-electronic repulsion and required less energy to remove.