Atomic, Molecular, and Laser Physics Flashcards
Bohr equation for hydrogen
/\E =
/\ is a delta
hbar w =
Rhc( Z2/n2 - Z2/m2 )
relate wavenumber and wavelength
v = 1/lambda
Rhc =
e2/4πe0 . 1/2a0
bohr radius
a0 =
hbar2 / (e2/4πe0)me
fine structure constant
alpha = ve/c
= e2/4πe0 . 1/(hbar.c)
~1/137
energy of a magnetic dipole in a magnetic field
E =
-mu.B
mu is the magnetic dipole
Bohr magneton
muB=
e hbar/2me
TISE
{-hbar2/2me \/2 + V(r)} phi = E phi
\/ is nabla
To solve schrodiger for hydrogen atom (angular part)
- express \/2 in spherical polar also using operator l2 to contain angular terms
- separation of variables
- start with angular, separate again with constant m2
- use PHI(phi + 2π) = PHI(phi) => integer m
- apply raising operators to Y until l+Y = 0 (mmax = l )
- show Y≈ sinl(theta)eilø
- apply lowering ops to find the rest
Y0,0 =
SQRT (1/4π)
Y1,0 =
SQRT ( 3/4π ) cos(theta)
Y1,1
Y1,-1
-SQRT( 3/8π ) sin(theta) e+iø
+SQRT( 3/8π ) sin(theta) e-iø
how do we solve shrodinger eqn for a many electron atom
- ignore electron spin
- include a SUM of mutual repulsions
- invent a centrally symmetric potential V(r)
- modify H = H0 + H1
such that H0 centrally symmetric
- eqns are now separable
H0 >> H1
perturbation
central field approximation
ignore the risidual el. static interaction from multi atom Hamiltonian.
H1 = 0
Pauli Exclusion Principle. How does it lead to configurations
2 identical fermions cannot occupy the same quantum state simultaneously.
It limits the number of electrons you can put in each state. Otherwise all electrons would be in n=1 l=0
What is the quantum defect
a correction applied to the equations of a hydrogenic atom to take into account the fact that inner electrons do not entirely screen their associated charge in the nucleus.
electron configuration notation
nlx
n = shell = 1, 2, 3
l = orbital = s, p, d, = 0, 1, 2…
x = number of electrons, this has maximum 2*(2l + 1)
factor of 2 for the spin
why does a higher l correspond to higher (nearer 0) energy state
lower l electrons penetrate closer to the nucleus. Hence electrons with high l are further from the nucleus.
This means that outer electrons are more effectively screened <=> the effective charge experienced is lower.
trick for finding energies of first excited state of helium
1s12s1
first electron experiences no screening
2nd experiences perfect screening
1st has the form of hydrogen with z=2
2nd with z=1
in helium does the singlet or triplet state have higher energy and why?
singlet
can the triplet state in helium
1s12s1 3S
decay into the singlet state
1s12s1 1S
no. both states are metastable
tell me about the sequence of perturbations:
Hatom = H0 + H1 + HSO +[HHFS]
H0 is from the central field, it gives the configuration (nl)
H1 is the residual due to electron repulsion + screening, ot gives the term (2S+1L) [singlet-triplet splitting]
- together these two make the gross tructure
HSO is the fine structure due to spin orbit interaction, it gives the level (2S+1LJ) [triplet state is split into 3 levels]
Briefly outline the cause of the fine structure
The combination of the spin and orbital angular momenta.
The spin of the electron gives rise to a magnetic dipole moment, this sits in the magnetic field of the orbiting electrons. This leads to a shift in energy.
electron magnetic moment
mu =
and its energy in a magnetic field
-gs . muB/hbar . s
gs ≈ 2 = Londé factor
E = -mu . B
in the fine structure, where does the magnetic field come from? In hydrogen, is it parallel or antiparallel to the angular momentum of the electron?
the charged electrons are moving in the electric field of the nucleus and thus create a magnetic field.
NB
B = - 1/c2 v ^ E (from SR)
Parallel
Biot Savart Law
B = mu0/4π x I x int [r ^ ds / r2]
the path integral around the loop
current I =