as chemistry module 2.1 Flashcards
n = m/Mr
Moles = Mass/Mr
N= No.p/Ac
No. mol = N0. particles/Avogadro’s constant
Moles of gas
n= v /24
Moles of gas = Volume (cm3) / 24,000
moles of gas = volume (dm3) / 24
n = c x v
moles of solution= concentration x volume mol = (mol dm3) (dm3)
isotopes
atoms of the same element with different numbers of neutrons
relative isotopic mass
the mass of an atom of an isotope compared with 1/12th of the mass of an atom of carbon-12
relative atomic mass
the weighted mean mass of an atom of an element compared to 1/12th of the mass of an atom of carbon-12
relative molecular mass
the weighted mean mass of a molecule compared with 1/12th of the mass of carbon-12
relative formula mass
the weighted mean mass of a formula compared with 1/12th of the mass of carbon-12
mole
amount of any substance containing as many particles as there are carbon atoms in exactly 12g of carbon-12
empirical formula
simplest whole number ratio of atoms of each element present in a compound
molecular formula
actual number of atoms of each element in a molecule
acids
proton donors
bases
proton acceptors
alkalis
compounds that dissolve in water to make a solution with a pH greater than 7