Apricio - Lecture 7-9 Flashcards

1
Q

Isomerization of Bonds in Bases –> alter base paring capabilities

A
  • predominant form: (amino for Cytosine), (keto for Guanine)
  • altered form is frequent enough to contribute to errors during DNA replication that leads to a mutation (if not corrected)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Mutation frequently is caused by…

A

base mis-incorporation during DNA replication; not yet a full mutation since it is detected and repaired usually; DNA replication before repair (1/10E9) will stabilize the mutation in DNA

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Means to recognize newly synthesized strand - E. coli (Hemi Methylated DNA)

A

5’-GATC is methylated - DNA methylase
nascent DNA (for certain period of time) is not methylated
==> nascent and original DNA strands can be distinguished–>can keep original information

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q
Mismatch repair (Non-humans)
*MutS, MutL, MutH, ExoVII or RecJ (5'->3'), ExoVI(3'->5'), helicase II, ATP, DNA polymerase III, holoenzyme, SSB, ligase*
A
  1. MutS - Scans DNA & detects bulges in backbone (resulting from mispairing)
  2. MutL&MutH binds to hemi-methylated DNA; identify nascent(unmethylated) DNA
  3. MutH endonuclease cleave unmethylated DNA strand (nick)
  4. exonuclease remove a stretch of DNA containing mismatch
  5. DNA polymerase fills in the gap
  6. Ligase seals the nick
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Different types of Exonulcease in mismatch repair

A

Positions of methylated DNA and MutS are important

  1. 5’ to 3’ : ExoVII or RecJ
  2. 3’ to 5’ ; ExoVI
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Replication slippage - at short, tandemly repeated sequences

*neurological disease related to this mutation

A
  • hairpin (on nascent) == without repair-> mutant DNA will have longer DNA sequence (extra repeats)
  • hairpin (on template; less common) == without repair -> deletion of few repeats on synthesized strand
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

DNA base damage

A
  1. deamination of cytosine -> uracil => recognized as foreign
  2. depurination/depyrimidation -> entire loss of a base => leaves an abasic/unpaired site *DNA backbone is intact ==> block replication
  3. deamination of 5-methyl-cytosine -> thymine => not obviously foreign
  4. Various modifications of guanine; e.g. 6-methyl-G pairs with T, 8-oxo-G pairs with A
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Deamination of 5-methyl-cytosine

A

(eukaryotes) cytosine followed by guanine often methylated
deamination of 5-methyl-cytosine => thymine
if not repaired. T will pair with A creating stable mutation

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Radiation and DNA damage

A

UV radiation: double bonds in pyrimidine rings activated to react with adjacent base; crosslink between pyrimidine bases (e.g. thymine dimer; cannot be read, stops DAN polymerase)
2. Ionizing radiation (gamma-, X-ray): create dsDNA breaks, cause dleletion/insertion/chromosomal rearrangements

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Ames Test

A

Potentially mutagenic compound screened quickly in bacteria (e.g. salmonella)
reversions (reverse mutations) of mutations can be tested easily

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Mutagenic

A

compounds that are not mutagenic -> converted to mutagens in the liver
-> liver enzyme treating can test this possibility

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Photoreactivation

A

T-T sequence + UV radiation -> crosslink; pyrimidine dimer; thymine dimer -> DNA photolyase attaches to the mutation site (Dark) -> visible light activates/catalyzes the reaction

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Base excision repair

A

removal of uracil/damaged base

  1. DNA glycosylase cleaves base
  2. abasic nucleotide removed by AP endonuclease and exonucelase
  3. gap filled with DNA polymerase I and ligase
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Nucleotide Excision Repair

A

Fix: Damaged bases, pyrimidine dimers (crosslink), as well as larger adducts

  1. UvrA/UvrB: scan distortion on DNA
  2. UvrB: opens the helix by bending. recruits UvrC
  3. UvrC (endonuclease); cleave ssDNA on both ends of the lesion
  4. UvrD helicase: remove nicked NDA
  5. DNA Pol I & Ligase
  • defects in this pathway causes = Xeroderma pigmentosa
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Translesion DNA synthesis (Pol IV, PoV)

A
  • special (translesion) polymerase that can synthesize past the lesion without base pairing
  • no template used; highly error-prone
  • non-processive
  • used only when necessary; result of SOS response in bacteria or DNA checkpoint response in eukaryotes
  • can recognize error in ssDNA
  • other methods work on dsDNA
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Double strand break formation
(during DNA replication)
(potential problem in DNA replication)

A
  • damaged DNA template block DNA replication => cause dsDNA break
    1. directly
    2. fork stalling
    3. fork collapse (nick or lesion)
    4. fork regression (lesion stopping helicase) - chicken foot
17
Q

Non-Homologous End-Joining: NHEJ

A
  • predominant dsDNA break repair mechanism
  • rejoins ends with little homology and “trims” the ends
  • DNA base usually lost at joint = mutation
  • Involved in rearrangement of immunoglobuline genes to generate antibody diversity
18
Q

Homologous Recombination

A
  • Happens in dsDNA break repair in.. 1. prokaryotes, 2. single-celled eukaryotes, 3. germline of multicellular organisms
  • dsDNA break processed to make single-stranded 3’ overhangs==> carry out “strand invasion” of homologous chromosome ,(provide template) == form “D loop”
  • “invading strand”replicated
  • D-loop provide template for other 3’ end
19
Q

Holliday junctions

A

must be resolved junction between two homologous chromosomes;
may result in “cross-over” between chromosomes

20
Q

Homologous Recombination & Holliday Junction

A
  1. dsDNA break
  2. Alignment of homologs
  3. Strand invasion
  4. Branch migration: junction between molecules move; further invasion
    5.