Antennas and Feed Lines Flashcards
Feed lines: characteristic impedance and attenuation; standing wave ratio (SWR) calculation, measurement, and effects; antenna feed point matching
Which of the following factors determine the characteristic impedance of a parallel conductor feed line?
A. The distance between the centers of the conductors and the radius of the conductors
B. The distance between the centers of the conductors and the length of the line
C. The radius of the conductors and the frequency of the signal
D. The frequency of the signal and the length of the line
A. The distance between the centers of the conductors and the radius of the conductors
Neither of the following have anything to do with the characteristic impedance of a parallel conductor antenna feed line:
The length of the line
The frequency of the signal
By eliminating all the answers containing these two things, the only answer remaining is the correct one.
What is the relationship between high standing wave ratio (SWR) and transmission line loss?
A. There is no relationship between transmission line loss and SWR
B. High SWR increases loss in a lossy transmission line
C. High SWR makes it difficult to measure transmission line loss
D. High SWR reduces the relative effect of transmission line loss
B. High SWR increases loss in a lossy transmission line
Simply put, an SWR reading measures match between transmitter, feedline, and antenna. If it is high ( an inefficient impedance match ) power is attenuated by reflecting it back, and it is lost in the feedline and amp finals.
https://en.wikipedia.org/wiki/Standing_wave_ratio
https://en.wikipedia.org/wiki/Feed_line
Note that lossy is a key word in the answer. As in “line loss is the lossy-est loss to lose”
What is the nominal characteristic impedance of “window line” transmission line?
A. 50 ohms
B. 75 ohms
C. 100 ohms
D. 450 ohms
D. 450 ohms
Window line (also known as ladder line) generally has a 450 ohm impedance, however there are 300 ohm (twin lead, from older analog TV installations) and 600 ohm (open wire ladder line) variants. https://en.wikipedia.org/wiki/Twin-lead#Ladder_line
(A ladder is how you get to the highest place (pick the highest number))
What causes reflected power at an antenna’s feed point?
A. Operating an antenna at its resonant frequency
B. Using more transmitter power than the antenna can handle
C. A difference between feed line impedance and antenna feed point impedance
D. Feeding the antenna with unbalanced feed line
C. A difference between feed line impedance and antenna feed point impedance
Impedances of the feed-line and antenna feed-point should be matched to prevent power reflection as a standing wave (the greater the difference in impedance, the greater the reflected energy). Matching impedances optimizes the system for more complete signal power.
easy remember point to point in answer
How does the attenuation of coaxial cable change with increasing frequency?
A. Attenuation is independent of frequency
B. Attenuation increases
C. Attenuation decreases
D. Attenuation follows Marconi’s Law of Attenuation
B. Attenuation increases
Attenuation is another word for loss, where some of the energy is converted to heat. All cables have some amount of loss, generally measured in loss in dB per unit length (e.g. feet or meters).
The higher the frequency, the higher the attenuation and loss.
Think about how heat works: it’s molecules that are jiggling. The faster they jiggle, the higher the temperature. The higher the frequency, the more often electrons are bumping into molecules and setting them in motion.
A useful analogy is to think about people walking in a corridor. When there are few people they’re much less likely to bump into each other. The more crowded it is, the more likely people are to bump into each other.
Memory hint: Attenuation increases when frequency increases
In what units is RF feed line loss usually expressed?
A. Ohms per 1,000 feet
B. Decibels per 1,000 feet
C. Ohms per 100 feet
D. Decibels per 100 feet
D. Decibels per 100 feet
The values for RF feed line losses are usually expressed in dB per 100 ft.
The amount of signal loss through a substance is referred to as its attenuation. The attenuation of various feed lines, such as coaxial cables standardized in units of dB per 100 ft (or metric dB/meter). It is important to note that attenuation is also frequency dependant, and so the dB per 100 feet will often be expressed along with a standard frequency, such as for coax at 750 MHz.
What must be done to prevent standing waves on a feed line connected to an antenna?
A. The antenna feed point must be at DC ground potential
B. The feed line must be an odd number of electrical quarter wavelengths long
C. The feed line must be an even number of physical half wavelengths long
D. The antenna feed point impedance must be matched to the characteristic impedance of the feed line
D. The antenna feed point impedance must be matched to the characteristic impedance of the feed line
When the impedances are not matched, the standing waves may be reflected back which will raise the feed line standing wave ratio (SWR). These reflections should be eliminated by matching impedances to maximize power output and reduce the SWR.
If the SWR on an antenna feed line is 5:1, and a matching network at the transmitter end of the feed line is adjusted to present a 1:1 SWR to the transmitter, what is the resulting SWR on the feed line?
A. 1:1
B. 5:1
C. Between 1:1 and 5:1 depending on the characteristic impedance of the line
D. Between 1:1 and 5:1 depending on the reflected power at the transmitter
B. 5:1
It won’t help to adjust the transmitter end of the feed line, you need to adjust the antenna end of the line.
Sticking a matching network adjusted to 1:1 at the transmitter end of things will leave you with an unchanged standing wave ratio of 5:1.
Hint: The answer is in the question: the Standing Wave Ratio (SWR) of the feed line is 5 to 1
What standing wave ratio results from connecting a 50-ohm feed line to a 200-ohm resistive load?
A. 4:1
B. 1:4
C. 2:1
D. 1:2
A. 4:1
Remember, SWR is always 1:1 or greater. Thus, you can eliminate the distractors 1:2 and 1:4, which are both less than 1:1.
The standing wave ratio that will result from the connection of a 50-ohm feed line to a non-reactive load having a 200-ohm impedance is 4:1.
To calculate the standing wave ratio (SWR) in a case where the load is non-reactive, simply divide the greater impedance by the lesser impedance, thereby giving a value greater than one.
What standing wave ratio results from connecting a 50-ohm feed line to a 10-ohm resistive load?
A. 2:1
B. 1:2
C. 1:5
D. 5:1
D. 5:1
In cases where the load is non-reactive, the SWR may be calculated by simply dividing the greater impedance value divided by the lesser impedance value (whichever fraction will give a result greater than 1).
What is the effect of transmission line loss on SWR measured at the input to the line?
A. Higher loss reduces SWR measured at the input to the line
B. Higher loss increases SWR measured at the input to the line
C. Higher loss increases the accuracy of SWR measured at the input to the line
D. Transmission line loss does not affect the SWR measurement
A. Higher loss reduces SWR measured at the input to the line
The higher the transmission line loss, the more the SWR will read artificially low.
SWR is defined as the ratio of forward power to reflected power.
Higher transmission line losses mean a larger portion of the reflected power will be absorbed, thus leading to an artificially lower SWR reading.
What is a characteristic of a random-wire HF antenna connected directly to the transmitter?
A. It must be longer than 1 wavelength
B. Station equipment may carry significant RF current
C. It produces only vertically polarized radiation
D. It is more effective on the lower HF bands than on the higher bands
B. Station equipment may carry significant RF current
One disadvantage of a directly fed random-wire antenna is that you may experience RF burns when touching metal objects in your station.
The simple single wire length of the random-wire antenna acts as both feed line and antenna and is directly connected to the transmitter. Because of the proximity of the antenna to your equipment, RF energy can “feed back” to your equipment and create RF hot spots. Proper grounding of the antenna and equipment cases is important to reduce burn risk.
For more info see Wikipedia: Random-wire antenna
Which of the following is a common way to adjust the feed point impedance of an elevated quarter-wave ground-plane vertical antenna to be approximately 50 ohms?
A. Slope the radials upward
B. Slope the radials downward
C. Lengthen the radials beyond one wavelength
D. Coil the radials
B. Slope the radials downward
With a minimal impact to antenna performance, angling the radials downward instead of placing them horizontally can increase the feed point impedance. W5ALT states that sloping downward at approximately 45 degrees below horizontal is sufficient to obtain feed point impedance of about 50 ohms:
Silly Hint: Ground -> Down
Which of the following best describes the radiation pattern of a quarter-wave ground-plane vertical antenna?
A. Bi-directional in azimuth
B. Isotropic
C. Hemispherical
D. Omnidirectional in azimuth
D. Omnidirectional in azimuth
A quarter-wave ground plane is sort of like a vertical dipole, it radiates horizontally in all directions. So, that leaves out bi-directional.
Isotropic is a theoretical antenna, a point source that radiates in all directions. A quarter-wave ground-plane radiates very little “up” and “down” - so it’s certainly not an isotropic radiator.
Hemisperical also theoretical and would be like isotropic/spherical, but with no transmission on one side of a bisecting plane. If the bisection were horizontal, it would have equal horizontal and vertical transmission above (or below) that midline. A quarter-wave ground-plane is again disqualified because it radiates very little “up” (or “down”).
What is the radiation pattern of a dipole antenna in free space in a plane containing the conductor?
A. It is a figure-eight at right angles to the antenna
B. It is a figure-eight off both ends of the antenna
C. It is a circle (equal radiation in all directions)
D. It has a pair of lobes on one side of the antenna and a single lobe on the other side
A. It is a figure-eight at right angles to the antenna
A standard dipole antenna radiates in a doughnut pattern in 3-D, but when examined in a polar diagram will resemble a figure-8 at a right angle to the antenna axis.
“The radiation pattern of a half-wave dipole antenna [is] that the direction of maximum sensitivity or radiation is at right angles to the axis of the RF antenna.”
Dipole Radiation Pattern & Polar Diagram
Silly Hint: The correct answer is the only option containing the word “right”.
How does antenna height affect the azimuthal radiation pattern of a horizontal dipole HF antenna at elevation angles higher than about 45 degrees?
A. If the antenna is too high, the pattern becomes unpredictable
B. Antenna height has no effect on the pattern
C. If the antenna is less than 1/2 wavelength high, the azimuthal pattern is almost omnidirectional
D. If the antenna is less than 1/2 wavelength high, radiation off the ends of the wire is eliminated
C. If the antenna is less than 1/2 wavelength high, the azimuthal pattern is almost omnidirectional
When a horizontal dipole antenna is close to the ground, the signals reflected from the ground cause more of the signal to be directed back at high vertical angles. This changes the “figure 8” pattern to a more omnidirectional “doughnut”.
For more info see Wikipedia: Dipole antenna
Hint: Look for answer with Azimuthal
Where should the radial wires of a ground-mounted vertical antenna system be placed?
A. As high as possible above the ground
B. Parallel to the antenna element
C. On the surface or buried a few inches below the ground
D. At the center of the antenna
C. On the surface or buried a few inches below the ground
By placing the radial wires at or just below ground level, you can create an artificial ground screen to act as a more effective ground plane. Depending on your type of installation and the ground conductivity you may need to install 8, 16, 32 (multiples of 2) or more 1/4 wavelength or longer radial wires to form this “ground screen”.
How does the feed point impedance of a horizontal 1/2 wave dipole antenna change as the antenna height is reduced to 1/10 wavelength above ground?
A. It steadily increases
B. It steadily decreases
C. It peaks at about 1/8 wavelength above ground
D. It is unaffected by the height above ground
B. It steadily decreases
Placing the antenna at least 1/4 wave above ground is optimal for this type of antenna. In addition to decreasing the feed-point impedance of the antenna, lowering the antenna below 1/4 wavelength above the ground will also greatly alter the radiation pattern of the antenna.
Memory tip: Decreasing the height, decreases the impedance.
How does the feed point impedance of a 1/2 wave dipole change as the feed point is moved from the center toward the ends?
A. It steadily increases
B. It steadily decreases
C. It peaks at about 1/8 wavelength from the end
D. It is unaffected by the location of the feed point
A. It steadily increases
The center of a 1/2 wave dipole antenna is usually the best place to mount the feed-point. The impedance is lowest at this point at about 72 ohms, which is close to matching the feed line impedance of 75-ohm coaxial cable. By moving the feed point toward the ends of the antenna, the impedance increases steadily and can reach a level of several thousand ohms!
Silly hint: As you move from Center to Ends you move up in the alphabet.
Which of the following is an advantage of using a horizontally polarized as compared to a vertically polarized HF antenna?
A. Lower ground losses
B. Lower feed point impedance
C. Shorter radials
D. Lower radiation resistance
A. Lower ground losses
By polarizing the antenna horizontally, currents are induced along the surface of the ground, which has lower reflection losses. This horizontal polarization also has the advantage in that waves reflected from the ground will recombine with the non-reflected signal wave pattern of the antenna and form a stronger signal.
What is the approximate length for a 1/2 wave dipole antenna cut for 14.250 MHz?
A. 8 feet
B. 16 feet
C. 24 feet
D. 33 feet
D. 33 feet
What is the approximate length for a 1/2 wave dipole antenna cut for 3.550 MHz?
A. 42 feet
B. 84 feet
C. 132 feet
D. 263 feet
C. 132 feet
What is the approximate length for a 1/4 wave monopole antenna cut for 28.5 MHz?
A. 8 feet
B. 11 feet
C. 16 feet
D. 21 feet
A. 8 feet
Which of the following would increase the bandwidth of a Yagi antenna?
A. Larger-diameter elements
B. Closer element spacing
C. Loading coils in series with the element
D. Tapered-diameter elements
A. Larger-diameter elements
A Yagi or Yagi-Uda antenna is composed of a driven element and several parasitic elements (a reflector and one or more directors). Changing to a larger diameter element can increase the bandwidth and SWR of the antenna.
Hint: the fatter the antenna element, the larger bandwidth, which is true for all antennas.