Alkanes Flashcards

1
Q

How can crude oil be separated and what property allows this to happen?

A

Fractional distillation

Boiling points of the different hydrocarbon chains

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2
Q

What process can break long alkane chains and what is formed?

A

Cracking

Shorter alkanes and alkenes are made

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3
Q

How does the size of an alkane chain effect the boiling point?

A

The larger the chain the larger the surface area, meaning more points of contact between chains and therefore more intermolecular London forces. This means they have a higher boiling point.

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4
Q

How does branching effect the boiling points of alkanes?

A

Branched alkanes cannot get as close therefore have fewer points of contact so weaker London forces so therefore a lower boiling point.

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5
Q

Why are alkanes non- polar?

A

C-H only have a small electronegative difference therefore there is hardly any bond polarity.
Totally symmetrical alkanes such as methane are completely non polar.

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6
Q

What shape is around a C atom and why and what is the angle?

A

Tetrahedral arrangement of single covalent bonds due to equal amount of repulsion between the 4 bonding pairs of electrons.
109.5

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7
Q

Describe a sigma bond:

A
  1. When either 2 s orbitals or 2 p orbitals or 1 s and 1 p orbital overlap head on and the bonded atoms are free to rotate around the sigma bond
  2. Sigma bonds are very strong and have a high bond enthalpy
  3. They have strong electrostatic attraction due to the high electron density between nuclei
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8
Q

Why do alkanes have a low reactivity?

A

Non polar

Strong sigma bonds with high bond enthalpies

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9
Q

What products are formed during complete combustion?

A

Carbon dioxide and water

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10
Q

What products are formed when oxygen is in limited supply?

A

Carbon monoxide and water

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11
Q

What happens if oxygen is in really short supply?

A

The carbon is not oxidised leaving Carbon and water as products

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12
Q

What is the overall reaction equation of the chlorination of methane? And what are the conditions?

A

CH4+ Cl2= CH3Cl + HCl

Ultra violet light and excess methane

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13
Q

Describe the mechanism of the chlorination of methane:

A
  1. Initiation Cl2= 2Cl.
    UV light provides the energy to break the bond homolytically.
  2. Propagation
    A) CH4 + Cl. = .CH3 + HCl
    B) .CH3 + Cl2 = CH3Cl + Cl.
    Chain reaction
  3. Termination
    .CH3 + Cl. = CH3Cl (major)
    .CH3 + .CH3 = CH3CH3 (minor)
    Cl. + Cl. = Cl2
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14
Q

What happens if the halogen is in excess?

A

Further substitution is favoured

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