Alcohols and some of their reactions Flashcards
alcohols are
a homologous series of compounds with the general formula CnH2n+1OH
alcohols can be the product of what type of reaction involving a halogenoalkane and water?
hydrolysis
the simplified formula for alcohols is
ROH
R represents
an alkyl group
when naming alcohols, we insert the functional group number
in the name, not at the beginning (propan-2-ol not 2-propanol)
when two or more OH groups groups are present in a compound, we add the term
di- or tri- before the -ol bit of the naming
a primary alcohol is when
the C atom to which the OH group is attached is bonded to only one carbon atom
a secondary alcohol is when
the C atom to which the OH group is attached is bonded to two other carbon atoms
a tertiary alcohol is when
the carbon atom to which the OH group is attached is bonded to three other carbon atoms
methanol would be classified as
a primary alcohol
the equation for the complete combustion of ethanol is
C2H5OH + 3O2 = 2CO2 + 3H2O
alcohols can be converted back into
halogenoalkanes
alcohols can be converted into halogenoalkanes by
removing the OH group and replacing it with a halogen atom
a hydroxyl group is
an OH group
an OH is
a hydroxyl group
chlorination is carried out
using phosphorus(V) chloride
chlorination results in the formation of
two inorganic products
the two inorganic products formed in chlorination using phosphorus(V) chloride is
phosphorus oxychloride and hydrogen chloride
the reaction between phosphorus(V) chloride and an alcohol is (in terms of vigority)
very vigorous
as chlorination reactions are very vigorous, they do not require
heating during the reaction
tertiary alcohols do not require the same method of chlorination as for
primary and secondary alcohols
tertiary alcohols are chlorinated using
concentrated hydrochloric acid
primary and secondary alcohols are chlorinated using
phosphorus(V) chloride
the formula of phosphorus(V) chloride is
PCl5
the chlorination reaction between propan-1-ol is (word equation)
propan-1-ol + phosphorus(V) chloride = 1-chloropropane + phosphorus oxychloride + hydrogen chloride
the symbol equation for the chlorination of propan-1-ol is
CH3CH2CH2OH + PCl5 = CH3CH2CH2Cl + POCl3 + HCl
the formula of 2-methylpropan-2-ol is
(CH3)3COH
bromination is carried out using
a mixture of potassium bromide and about 50% concentrated sulfuric acid
bromination reactions have to be
heated with the alcohol
when writing equations for bromination reactions
we write two separate equations, as the two reagents can react to make hydrogen bromide
the two equations with for the bromination reaction (just the two reagents of the mixture)
KBr + H2SO4 = KHSO4 + HBr
or
2KBr + H2SO4 = K2SO4 + 2HBr
(hydrogen bromide is formed in both reactions)
the other inorganic product (not HBr) formed in the reaction mixture in the reagents for bromination is
either potassium hydrogensulfate or potassium sulfate
the symbol equation for the bromination of butan-1-ol is
CH3CH2CH2CH2OH + HBr = CH3CH2CH2CH2Br + H2O
iodination is carried out using
a mixture of red phosphorus and iodine
the reaction mixture for iodination is (conditions)
heated under reflux
when writing equations for iodination reactions,
we write two equations for the inorganic reagents in the mixture as they first react to produce phosphorus(III) iodide
the two inorganic reagents in the iodination reaction first react to form
phosphorus(III) iodide
the equation for the reaction of the two inorganic reagents in iodination reactions (red phosphorous and iodine) is
2P + 3I2 = 2PI3
the equation for the iodination of ethanol is
3CH3CH2OH + PI3 = 3CH3CH2I + H3PO3
the compound H3PO3 is called and also known as
called phosphonic acid and is known as phosphorous acid
alcohols can be……… to form alkenes
dehydrated
dehydration of alcohols is done by
heating the alcohol with concentrated phosphoric acid
dehydration reactions of alcohols are similar to
elimination reactions of halogenoalkanes
dehydration reactions of alcohols are similar to elimination reactions of halogenoalkanes because
in both the OH group and a H atom from an adjacent carbon atom is removed and a double C=C bond formed
a halogenation reaction results
in the displacement of the hydroxyl group in an alcohol molecule by a halogen atom
a dehydration reaction results
in the removal of the hydroxyl group in an alcohol molecule, together with a hydrogen atom from an adjacent carbon atom, forming a C=C double bond
the dehydration of butan-2-ol can produce two products (apart from water):
but-1-ene and but-2-ene and both produce water
the two equations for the dehydration of but-2-ol are
CH2CH(OH)CH2CH3 = H2C=CHCH2CH3 + H2O and CH2CH(OH)CH2CH3 = CH2HC=CHCH3 + H2O
but-2-ene exists as
two E-Z isomers, so when but-2-ol is dehydrated, it is correct that there are three possible products, but-1-ene and the two forms of but-2-ene
in dehydration reactions of alcohols, we do not show…….in the equation because it………….
the phosphoric acid as this is just diluted by the water produced