AAMC Sample Full Length 1 Review ?s Flashcards
CP5 Which way should electric field lines flow when depicting an axon against its extracellular fluid?
Electric field lines should exit from positive and enter negative charges. The axon itself is negatively charged. The extracellular solution has zero potential. So the field lines will start in the fluid and put inward to membrane
CP7: Atomic Properties: Channel X transmits only the smallest substances dissolved in the extracellular fluid through the axon membrane. What does Channel X transmit? A: proteins B: Na+ ions C: K+ ions D: Cl- ions
-ANS is B Sodium Ions, b/c they are the smallest. Ionic size increases left to right, and top to bottom.
Q9: Electrics: What info about an axon is required to calculate the current assosciated with an NCV pulse?
ANS is potential, resistance per unit length, and length. This is obtained by manipulating V=IR to I = V/R. We need V(potential), and to determine R, we can use resistance per unit length and the tota length.
_Q11 Takewa_y: How would a weak acid conduct electricity vs. a strong acid?
A weak acid will only partially disassociate into ions, whereas a strong acid will fully disassociate. With more ions in the solution, the strong acid will better conduct electricity.
Q14: What is squalene(ring-like structures with lots of double bonds) a precursor of? A:Triacyl glycerols B: Peptide hormones C: Steroid hormones D: Prostaglandins
ANS is C. It looks like cholesterol!
Q16: When will a disaccharide react with Ag2O in NH3(aq) and form a precipitate?
If it is a reducing sugar -> it has a hemiacetal group. It will not react if it has an acetal group!
Q17: What is the net charge of the peptide Arg-Ala-Phe-Leu at pH 8? -1, 0, +1, or +2?
ANS is +1. Arg is the only charged amino acid at that pH-> it has a charge of +1. The N-terminus itself has a charge of +1, and the C-terminus has a charge of -1. Taken all together, this equals +1.
In Reverse Phase HPLC( there is a polar mobile phase and a non polar stationary phase), will a polar compound elute first or non polar?
In Reverse-phase, polar compounds will elute first. Then non-polar compounds will
In _normal phase HPLC(_stationary polar phase and non polar mobile phase), will a polar compound elute first or a non polar?
In normal phase, a non polar solvent will elute first.
IR Frequency Identities:
I: 1580-1610 cm-1
II: 1700-1750 cm-1
III: 3200-3500 cm-1
I is an aromatic or conjugated system
II is a C=0
III is an OH group
How would you use a lens to correct for myopia or near-sightedness?
Use a diverging lens.
This works b/c in myopia the lens incorrectly focuses light on a point before the retina. Using a diverging lens would spread out light, and cause it to hit further back on the retina!
Q46: The density of a human body can be calculated form its weight in air, Wair, and its weight while subsmered in water ,Ww. The density of a human body is proportional to:
A: Wair/(Wair-Ww)
B: (Wair-Ww)/Wair
C: (Wair-Ww)/Ww
D:Ww/(Wair-Ww)
-ANS is A: Wair/(Wair-Ww).
Archimedes’ Principle, the ra_tio of density of an object to the density of fluid_ it is submersed in is e_qual to the ratio of weight of the object in air to the difference in submersed weight and weight in air._
What is the un_it 1 Watt equivalent to?_
1 Joule /second
During glycolysis. Pyruvate(CH3C(=O)CO2 is reduced to lactate CH3CH(OH)CO2- by nicotinamide adenine dinucleodide (NADH). What is the balanced reaction for this conversion?
A: CH3C(=O)CO2- + 2 NADH -> CH3CH(OH)CO2- + 2NAD+
B: CH3C(=O)CO2- + 2 NADH + 2H+ -> CH3CH(OH)CO2- + 2NAD+
C: CH3C(=O)CO2- + NADH + 2H+ -> CH3CH(OH)CO2- + NAD+
D: CH3C(=O)CO2- + NADH + H+ -> CH3CH(OH)CO2- + NAD+
-ANS is D: CH3C(=O)CO2- + NADH + H+ -> CH3CH(OH)CO2- + NAD+.
This can only be arrived at by knowing the reduction of pyruvate is CH3(=O)CO2- + 2H+ + 2e- -> CH3CH(OH)CO2-. Balance is attained by first balancing hydrogen with H+(adding two H+s to the reactant side ) and then the charge with e-(adding two to the reactant side). The oxidation half reaction is NADH -> NAD+ + H+ + 2e-. Adding these together, the e- cancel out.
Hydrolysis of the gamma phosphate of GTP bound to Arf1(or most substrates in general) results in:
A: denaturation
B: activation
C: inactivation
D: membrane assosciation
ANS is C inactivation. Hy_drolysis of GTP_ would result in formation of GDP in the pocket.