7.1 Flashcards

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1
Q

series of experiments to prove that DNA was the genetic material

A

Alfred Hershey and Martha Chase in 1952

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2
Q

Viruses (T2 bacteriophage) were grown in one of two isotopic mediums in order to radioactively label a specific viral component

A
  • Viruses grown in radioactive sulfur (35S) had radiolabelled proteins (sulfur is present in proteins but not DNA)
  • Viruses grown in radioactive phosphorus (32P) had radiolabeled DNA (phosphorus is present in DNA but not proteins)
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3
Q

virus and bacteria were…

A

The viruses were then allowed to infect a bacterium (E. coli) and then the virus and bacteria were separated via centrifugation
- The larger bacteria formed a solid pellet while the smaller viruses remained in the supernatant

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4
Q

Hershey and Chase demonstrated that

A

he bacterial pellet was found to be radioactive when infected by the 32P–viruses (DNA) but not the 35S–viruses (protein)
- This demonstrated that DNA, not protein, was the genetic material because DNA was transferred to the bacteria

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5
Q

Rosalind Franklin and Maurice Wilkins used a method of X-ray diffraction to investigate the structure of DNA

A
  • DNA was purified and then fibres were stretched in a thin glass tube (to make most of the strands parallel)
  • The DNA was targeted by a X-ray beam, which was diffracted when it contacted an atom
  • The scattering pattern of the X-ray was recorded on a film and used to elucidate details of molecular structure
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6
Q

From the scattering pattern produced by a DNA molecule, certain inferences could be made about its structure

A
  • Composition: DNA is a double stranded molecule
  • Orientation: Nitrogenous bases are closely packed together on the inside and phosphates form an outer backbone
  • Shape: The DNA molecule twists at regular intervals (every 34 Angstrom) to form a helix (two strands = double helix)
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7
Q

Franklin’s x-ray diffraction experiments demonstrated that…

A

DNA helix is both tightly packed and regular in structure

- Phosphates (and sugars) form an outer backbone and nitrogenous bases are packaged within the interior

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8
Q

Chargaff had also demonstrated that DNA is composed of…

A

an equal number of purines (A + G) and pyrimidines (C + T)

  • This indicates that these nitrogenous bases are paired (purine + pyrimidine) within the double helix
  • In order for this pairing between purines and pyrimidines to occur, the two strands must run in antiparallel directions
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9
Q

When Watson & Crick were developing their DNA model, they discovered that…

A

an A–T bond was the same length as a G–C bond

  • Adenine and thymine paired via two hydrogen bonds, whereas guanine and cytosine paired via three hydrogen bonds
  • If the bases were always paired this way, then this would describe the regular structure of the DNA helix (shown by Franklin)
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10
Q

Consequently, DNA structure suggests two mechanisms for DNA replication:

A
  • Replication occurs via complementary base pairing (adenine pairs with thymine, guanine pairs with cytosine)
  • Replication is bi-directional (proceeds in opposite directions on the two strands) due to the antiparallel nature of the strands
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11
Q

Helicase

A
  • Helicase unwinds and separates the double-stranded DNA by breaking the hydrogen bonds between base pairs
  • This occurs at specific regions (origins of replication), creating a replication fork of two strands running in antiparallel directions
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12
Q

DNA Gyrase

A
  • DNA gyrase reduces the torsional strain created by the unwinding of DNA by helicase
  • It does this by relaxing positive supercoils (via negative supercoiling) that would otherwise form during the unwinding of DNA
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13
Q

Single Stranded Binding (SSB) Proteins

A
  • SSB proteins bind to the DNA strands after they have been separated and prevent the strands from re-annealing
  • These proteins also help to prevent the single stranded DNA from being digested by nucleases
  • SSB proteins will be dislodged from the strand when a new complementary strand is synthesised by DNA polymerase III
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14
Q

DNA Primase

A
  • DNA primase generates a short RNA primer (~10–15 nucleotides) on each of the template strands
  • The RNA primer provides an initiation point for DNA polymerase III, which can extend a nucleotide chain but not start one
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15
Q

DNA Polymerase III

A
  • Free nucleotides align opposite their complementary base partners (A = T ; G = C)
  • DNA pol III attaches to the 3’-end of the primer and covalently joins the free nucleotides together in a 5’ → 3’ direction
  • As DNA strands are antiparallel, DNA pol III moves in opposite directions on the two strands
    -On the leading strand, DNA pol III is moving towards
    the replication fork and can synthesise continuously
    - On the lagging strand, DNA pol III is moving away
    from the replication fork and synthesises in pieces
    (Okazaki fragments)
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16
Q

DNA Polymerase I

A
  • As the lagging strand is synthesised in a series of short fragments, it has multiple RNA primers along its length
  • DNA pol I removes the RNA primers from the lagging strand and replaces them with DNA nucleotides
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17
Q

DNA Ligase

A
  • DNA ligase joins the Okazaki fragments together to form a continuous strand
  • It does this by covalently joining the sugar-phosphate backbones together with a phosphodiester bond
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18
Q

DNA polymerase cannot…

A

Initiate replication, it can only add new nucleotides to an existing strand

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19
Q

for DNA replication to occur…

A

an RNA primer must first be synthesised to provide an attachment point for DNA polymerase

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20
Q

DNA polyermase occurs…

A

nucleotides to the 3’ end of a primer, extending the new chain in a 5’ → 3’ direction

  • Free nucleotides exist as deoxynucleoside triphosphates (dNTPs) – they have 3 phosphate groups
  • DNA polymerase cleaves the two additional phosphates and uses the energy released to form a phosphodiester bond with the 3’ end of a nucleotide chain
21
Q

Leading versus Lagging Strands

A

Because double-stranded DNA is antiparallel, DNA polymerase must move in opposite directions on the two strands

22
Q

On the leading strand…

A

DNA polymerase is moving towards the replication fork and so can copy continuously

23
Q

On the lagging strand…

A

DNA polymerase is moving away from the replication fork, meaning copying is discontinuous

24
Q

As DNA polymerase is moving away from helicase…

A

it must constantly return to copy newly separated stretches of DNA

25
Q

the lagging strand is…

A

copied as a series of short fragments (Okazaki fragments), each preceded by a primer

26
Q

the primers are replaced with…

A

DNA bases and the fragments joined together by a combination of DNA pol I and DNA ligase

27
Q

DNA sequencing refers to…

A

the process by which the base order of a nucleotide sequence is elucidated

28
Q

The most widely used method for DNA sequencing involved the use of…

A

chain-terminating dideoxynucleotides

29
Q

dideoxynucleotides

A
  • Dideoxynucleotides (ddNTPs) lack the 3’-hydroxyl group necessary for forming a phosphodiester bond
  • Consequently, ddNTPs prevent further elongation of a nucleotide chain and effectively terminate replication
  • The resulting length of a DNA sequence will reflect the specific nucleotide position at which the ddNTP was incorporated
    • For example, if a ddGTP terminates a sequence after
      8 nucleotides, then the 8th nucleotide in the
      sequence is a cytosine
30
Q

Sequencing

A

Dideoxynucleotides can be used to determine DNA sequence using the Sanger method

31
Q

Sanger Sequencing method

A
  • Four PCR mixes are set up, each containing stocks of normal nucleotides plus one dideoxynucleotide (ddA, ddT, ddC or ddG)
  • As a typical PCR will generate over 1 billion DNA molecules, each PCR mix should generate all the possible terminating fragments for that particular base
  • When the fragments are separated using gel electrophoresis, the base sequence can be determined by ordering fragments according to length
  • If a distinct radioactive or fluorescently labelled primer is included in each mix, the fragments can be detected by automated sequencing machines
  • If the Sanger method is conducted on the coding strand (non-template strand), the resulting sequence elucidated will be identical to the template strand
32
Q

The vast majority of the human genome is comprised of…

A

non-coding DNA (genes only account for ~ 1.5% of the total sequence)

33
Q

non-coding DNA was historically referred to as

A

‘junk DNA’, these non-coding regions are now recognised to serve other important functions

34
Q

examples of ‘junk DNA’

A

satellite DNA, telomeres, introns, ncRNA genes and gene regulatory sequences

35
Q

DNA profiling is a technique by which…

A

individuals can be identified and compared via their respective DNA profiles

36
Q

short tandem repeats (STRs)

A

Within the non-coding regions of an individual’s genome there exists satellite DNA – long stretches of DNA made up of repeating elements

37
Q

Tandem repeats can be excised using

A

restriction enzymes and then separated with gel electrophoresis for comparison

38
Q

As individuals will likely have different numbers of repeats at a given satellite DNA locus, they will generate

A

unique DNA profiles

39
Q

Longer repeats will generate…

A

longer fragments (and vice versa)

40
Q

in eukaryotic organisms, the DNA is packaged with…

A

histone proteins to create a compacted structure called a nucleosome

41
Q

Nucleosomes help to…

A

supercoil the DNA, resulting in a greatly compacted structure that allows for more efficient storage

42
Q

Supercoiling helps to…

A

protect the DNA from damage and also allows chromosomes to be mobile during mitosis and meiosis

43
Q

nucleosome

A

The DNA is complexed with eight histone proteins (an octamer) to form a complex

44
Q

chromatosomes

A

Nucleosomes are linked by an additional histone protein (H1 histone) to form a string of

45
Q

30 nm fibre

A

These then coil to form a solenoid structure (~6 chromatosomes per turn) which is condensed to form a

46
Q

chromatin

A

These fibres then form loops, which are compressed and folded around a protein scaffold to form

47
Q

chromosomes

A

Chromatin will then supercoil during cell division to form chromosomes that are visible (when stained) under microscope

48
Q

A nucleosome consists of…

A

a molecule of DNA wrapped around a core of eight histone proteins (an octamer)

49
Q

nucleosome

A
  • The negatively charged DNA associates with positively charged amino acids on the surface of the histone proteins
  • The histone proteins have N-terminal tails which extrude outwards from the nucleosome
  • During chromosomal condensation, tails from adjacent histone octamers link up and draw the nucleosomes closer together