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let's get physical! > 7. they'd say I played the field before I found someone to commit to [NTF] > Flashcards

7. they'd say I played the field before I found someone to commit to [NTF] Flashcards

electric and magnetic fields

1
Q

Magnetic Fields

A

A region surrounding a magnet or current carrying wire which acts upon any other magnet or current carrying wire placed within the field

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2
Q

Electric Field

A

A region of space in which a (small, positively) charged particle feels a force

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3
Q

Electric Field Strength

A

force per unit charge, E = F/Q

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4
Q

what do field lines show

A

Strength and direction

closer together lines shows a stronger field

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5
Q

Uniform fields

A

Same strength at any point in the field

- evenly spaced lines, arrows from + to -

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6
Q

Radial fields

A

strength decreases as distance from the point charge increases
- all equal angles, arrows from + to -

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7
Q

field line drawing rules

A

lines can never cross

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8
Q

Electric neutral/ null point

A

where there are no fields lines: the forces from the field is balanced.

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9
Q

electric field strength of a uniform field

A

E = v/d

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10
Q

charging

A

electrons are transferred from one material to another

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11
Q

inducing a charge in an object without touching the object

A
  • A negatively charged strip is bought close to 2 touching metal spheres.
  • Electrons from sphere A are repelled to sphere B.
  • The spheres are separated with the strip nearby
  • the strip is removed and the charged spreads out so it is distributed evenly
  • B is now negatively charged and A is positively charged
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12
Q

coulomb meter

A

measures charge

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13
Q

force between two charges

A
  • directly proportional to each of the charges Q1 and Q2

- inversely proportional to the square of their separation

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14
Q

Coulombs law

A

F = kQ1Q2 / r^2

F can be repulsive or attractive

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15
Q

electric potential

A

the potential energy that each coulomb of positive charge would have if placed at that point in the field.

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16
Q

potential difference

A

the energy transferred when one coulomb of charge passes from one point to another point
W = VQ

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17
Q

Equipotentials

A

positions within a field with zero potential difference between them.
They are perpendicular to field lines

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18
Q

Equipotentials between parallel plates

A

even spaced perpendicular to field lines

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19
Q

Equipotentials for a point charge

A

concentric circles, closer together near the point charge

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20
Q

charge moving along equipotential

A

no work is done because the potential energy does not change

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21
Q

Capacitor

A

an electrical component that stores and releases charge (and therefore energy)

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22
Q

Capacitor uses

A

Defibrillators & Camera Flashes

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23
Q

charging up a capacitor

A
  • when the switch is closed, electrons flow from the negative terminal of the battery onto the first plate of the capacitor, this becomes negatively charged
  • electrons are repelled from the second plate around the circuit
  • there is a force of attraction between the plates
  • this charging process continues until the pd. across the capacitor is equal to the pd. of the supply
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24
Q

discharging a capacitor

A
  • disconnect the battery
  • Initially there is a large current due to the large potential difference across the plates. The current drops as pd drops
  • current flows opposite way round the circuit when discharging
  • the charge drops quickly at first then more slowly
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25
Q

Capacitance

A

the ability to store charge on the plates of a capacitor. The charge stored per unit of pd. across it.
Q = VC

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26
Q

Capacitance Unit

A

Farads

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27
Q

energy stored in a charged capacitor

A

1/2 QV
(proof is VQ graph, area under graph = area of triangle)
(also can sub in Q = CV, V = C/Q to m=have a different form)

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28
Q

Capacitors in paralell

A

C = C1 + C2 ….

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29
Q

Capacitors in paralell proof

A 
Q = Q1 + Q1 ... 
Q = CV
CV = C1V2 + C2V2 ...
V is constant in parallel 
C = C1 + C2...
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30
Q

capacitors in series

A

1/C = 1/C1 + 1/C2 ….

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31
Q

Capacitors in series proof

A 
V = V1 + V2
V = Q/C
Q/C = Q1/C1 + Q2/C2
Q is constant in series
1/C = 1/C1 + 1/C2
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32
Q

The greater the capacitance

A

The greater the charge stored

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33
Q

As the pd. falls during the discharge of a capacitor the time…

A

for the pd to drop takes longer and longer

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34
Q

time constant

A

the time it takes for the charge to drop to 37% (1/e) of the original value (=RC)

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35
Q

RC / time constant unit proof

A

RxC = V/I*Q/V = Q/I = Q * t/Q = t

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36
Q

capacitance discharging graph (Qt, It, Vt)

A

exponential decay

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37
Q

capacitance charging graph (Qt, It, Vt)

A

current asymptotically reaches 0 (gradient decreases as it goes up)

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38
Q

exponential

A

same fractional change in y for each interval change in x

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39
Q

to plot a linear graph from discharge equations

A

take logs from both sides and follow log rules

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40
Q

magnetic field lines

A

lines of flux (always from N pole to S pole)

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41
Q

Magnetic Flux Density, B

A

the flux per unit area ( an indication of the strength of the magnetic field).

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42
Q

Magnetic Flux Density Unit

A

Tesla, T

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43
Q

Magnetic Neutral point

A

the point between two north poles where the magnetic field cancels and the resultant field strength is zero.

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44
Q

Flux Φ

A

the flux passing through an area A perpendicular to the magnetic field B is defined as Φ=BA

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45
Q

Flux Linkage

A

the product of magnetic flux and the number of turns on the coil NΦ = BAN

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46
Q

Flux/Flux Linkage Unit

A

Weber, W (sometimes Flux linkage is Weber Turns)

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47
Q

right hand rule

A

always a magnetic field around a current carrying wire

48
Q

Flemings left hand rule fingers

A

Thumb - Force
Index (First Finger) - Field
Middle (Second Finger) - Current

49
Q

Flemings Left hand rule

A

the conductive wire cuts lines of flux

A force acts perpendicular to both current and magnetic field

50
Q

If the current is parallel to the lines of flux

A

no force acts

51
Q

The force due to flemings left hand rule is greatest when

A

the wire and field are perpendicular otherwise only a component of the field strength is acting

52
Q

The force due flemings left hand rule depends on

A
  • size of current
  • magnetic field strength
  • length of wire
  • angle of wire to magnetic field
53
Q

Force on current carrying wire equation

A

F = BILsinθ

54
Q

Force on single moving charged particle in a magnetic field

+equations needed for proof

A

F = BQvsinθ

from F = BIL L=vt and I = Q/t

55
Q

shape of the path of charged particle in a magnetic field

A

Circular

56
Q

Why is the path of a charged particle in a magnetic field circular?

A

by fleming left hand rule the force on amoving charge is always perpendicular to its direction of travel, this the condition for circular motion

57
Q

EMF Induction

A
  • movement of a conductor in a B-Field
  • cuts lines of flux/ change in flux linkage
  • an emf is induced
    (- if part of a complete circuit an induced current flows)
58
Q

Faraday’s Law

A

the induced emf is directly proportional to the rate of change on flux linkage
Ɛ = d(NΦ)/dt

59
Q

Lenz’s Law

A

The induced emf is always in such a direction to oppose the change that caused it
Ɛ = - d(NΦ)/dt

60
Q

Why is Lenz’s Law good

A

It agrees with the principle of conservation of energy

61
Q

Factors effecting the emf induced in a coil

A
  • Angle between the coil and the field
  • Number of turns on the coil
  • Area of coil
  • Magnetic Field Strength
  • Angular Speed of Coil
  • magnitude/ frequency current in the wire
  • add an iron core
62
Q

Factor: angle between coil and field reasoning (emf induction)

A

smaller angle = less lines of flux cuts = lower emf

63
Q

Factor: Number of turns on the coil reasoning (emf induction)

A

more turns = more points which cut each flux line = higher emf

64
Q

Factor: Area of the coil reasoning (emf induction)

A

larger area = more lines of flux pass through = higher emf

65
Q

Factor: Magnetic Field Strength reasoning (emf induction)

A

higher flux density = more lines of flux per unit area = coil cuts more lines of flux = higher emf

66
Q

Factor: Angular Speed of Coil reasoning (emf induction)

A

increased angular speed = increased number lines of flux cut in a certain time = higher emf

67
Q

Using Lenz’s law to predict direction of induced emf

A

fleming left hand rule… force is opposite direction to motion, B field as told then current shows direction of induced emf

68
Q

EMF induction using two coils

A
  • one coil has an AC current passed through producing a changing magnetic field
  • second stationary coil then cuts lines of flux
  • induces an emf in the second coil
69
Q

Eddy Currents

A

if the conductor is large enough small rings of induced currents form. These will grow depending on the size of the conductor. These lose energy as heat.
if a conductor is moving through a B-field and the induced eddy currents are big enough it will stop the motion as all the KE s transferred to Heat.

70
Q

conductor with cracks moving through B-field

A

the motion will not be stopped / slowed as much because the cracks stop large Eddy currents from forming.

71
Q

relation between electric field and electric potential

A

electric potential is a property of electric fields

72
Q

Where is there always a magnetic field?

A

around a current carrying wire

73
Q

x

A

into the page

74
Q

.

A

out of the page

75
Q

solenoid

A

a long coil with many turns

76
Q

magnetic field of a solenoid

A

lines through the centre looping around to the opposite end of the solenoid

77
Q

flux density in the centre of a solenoid

A

constant

78
Q

Why is the magnetic field of a solenoid greatly increases when a magnetic material is placed inside it

A

The atomic magnets of the core line up along the lines of flux inside the solenoid so the core is magnetised

79
Q

what factors effect the force of a charged particle in a B field?

A
  • the magnetic flux density
  • charge on the particle
  • the velocity of the particle
80
Q

time period

A

is the time for one complete cycle

81
Q

frequency

A

the number of cycles in one second

82
Q

peak values

A

are the largest voltages or current an AC supply produces

83
Q

root-mean-square value

A

when you square all the values, take the mean then square root the values.

84
Q

other method of finding the rms value

A

divide by √2

85
Q

what type of current does a transformer change?

A

AC

86
Q

how does a transformer work?

A

an alternating current flows in the primary coil. This produces an alternating magnetic field in the soft iron core. This means the flux linkage of the second coil is constantly changing so an alternating voltage is induced across it.

87
Q

transformer equation

A

Vs/Vp = Ns/Np

88
Q

step-up transformer

A

increases the ac voltage (more turns on secondary coil)

89
Q

step-down transformer

A

decreases the ac voltage (less turns on secondary coil)

90
Q

where is energy lost of transformers?

A

eddy currents are induced in the soft iron core

91
Q

how i energy los reduced in transformers?

A

the core is made of laminated iron sheets

92
Q

is the time taken for a capacitor to loose half its energy greater or less than the time taken to lose half its charge?

A

W = QV/2
Q and V both increase over time
W will decrease faster so it takes LESS time to half in value

93
Q

advantage of data loggers which isn’t about reaction time

A
  • take multiple readings at the same time

- more readings can be taken in a shorter time / higher sample rate

94
Q

how does pd vary with charge for a capacitor

A

pd is directly proportional to charge

95
Q

exponential decay curve

A

x decreases by proportional fractions in equal time intervals. decreases very rapidly then more slowly.

96
Q

when asked to work out the resistance of a capacitor circuit

A

RC = time constant

time constant is the time it takes for I/V/C to drop to 37% of the original value

97
Q

frequency in capacitor circuits

A 
f = 1/t 
t = RC
98
Q

arrows on a uniform electric field

A

positive to negative

99
Q

electric field stength

A

force per unit charge acting on a small positive charge

100
Q

faradays law of em induction

A

The induced e m.f. is proportional to the rate of change of magnetic flux linkage

101
Q

what do to a DC current carrying wire to induce an emf in a coil

A
  • make it AC
  • move either coil
  • turn the power on/off
102
Q

what does an iron core do in emf induction

A

it becomes magnetised and increases the magnetic field

103
Q

why is there a minus sign

A
  • lenzs law/conservation of energy

- induced emf opposes the change that caused it

104
Q

capacitance

A

the ability to store charge

105
Q

AC root mean square

A

square root of the arithmetic mean of the squares

106
Q

what energy transfers occur in the motor effect?

A

electrical to kinetic

107
Q

electric potential , V =

A

V = kQ/r

108
Q

difference between EM induction and motor effect

A

EM is when a conductor moves in a B field

Motor effect is when a current carrying wire in a B field feels a force

109
Q

Motor effect

A

If two magnetic fields combine (i.e. a current carrying wire in a B-field) then a force is exerted (depending on fleming left hand rule.

110
Q

size of force in motor effect is effected by

A
  • increasing the magnetic field strength
  • increasing he length of the wire in the field
  • increasing the current in the wire
111
Q

how to show an electric field in the lab

A

set up two parallel plates with a pd. across them. Put charged oil drop in the region between the two plates to show the force acting on the droplet.

112
Q

what happens to a capacitor circuit when the switch changed to the power supply

A

Capacitor charges up so that the pd across the capacitor equals the pd of the supply. It has opposite charge on both plates.

113
Q

As a capacitor charges…

A

current drops to zero

114
Q

what happens to a capacitor circuit when the switch changed to the resistor circuit

A

Discharges over a period of time

115
Q

why may a diode be used when inducing an emf

A

so the current is not discharged by alternating emf from AC supply

116
Q

discharging a capacitor

A
  • Electrons/charge transferred from negatively charged plate to positively charge plate through the resistor
  • Hence the charge on capacitor decreases
  • Until the charge on the capacitor equals 0

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