6. Ligand substitution and precipitation reactions (reactions of different ions with NaOH and NH3) Flashcards
Cu2+(aq) with NaOH
colour change
Blue precipitate
gelatinous
Fe2+(aq) with NaOH
colour change
Pale green -> green precipitate turning a rusty brown at its surface on standing air
Fe3+(aq) with NaOH
colour change
Pale yellow -> rusty brown precipitate
Mn2+(aq) with NaOH
colour change
Brown precipitate which darkens in air as it oxidises
Cr3+(aq) with NaOH
colour change
Green precipitate
re-dissolves in excess hydroxide
Cu2+(aq) with ammonia
colour change
Blue precipitate (gelatinous) re-dissolves to a blue solution
Fe2+(aq) with ammonia
colour change
Dark green precipitate
Fe3+(aq) with ammonia
colour change
Rusty brown precipitate
Mn2+(aq) with ammonia
colour change
Brown precipitate which darkens in air as it oxidises
Cr3+(aq) with ammonia
colour change
Green precipitate
re-dissolves in excess ammonia
Fe2+(aq) with NaOH
ionic equation
Fe2+(aq) + 2OH-(aq) -> Fe(OH)2(s)
Fe3+(aq) with NaOH
ionic equation
Fe3+(aq) + 3OH-(aq) -> Fe(OH)3(s)
Mn2+ with NaOH
ionic equation
Mn(H2O)6 + 2OH-(aq) -> Mn(OH)2(H2O)4 + 2H2O
oxidation can be summarised by:
Mn(OH)2 + O2 -> 2Mn2O3 + 4H2O
Cr3+(aq) with NaOH
ionic equation
[Cr(H2O)6}3+(aq) + 3OH-(aq) -> Cr(OH)3(H2O)3 + 3H2O
Then
Cr(OH)3(H2O)3 + 3OH-(aq) -> [Cr(OH)6]3-(aq) + 3H2O