6- Chlorination of Tertiary Alcahol Flashcards
Deceive the steps in the method of chlorinating 2-methylpropan-2-ol (tertiary) - CP6
(CH3)3COH + HCl = (CH3)3CCl + H2O
Describe the steps in the purification of the ChlorAlkane produced in Core practical 6 following reaction with HCl
Describe the steps in the analysis of your product/ Chloroalkane in CP6 to prove that you have made the correct product
Forms a white precipitate of silver chloride just as in hydrolysis of Halogenoalkanes in CP4
Show what a separating funnel looks like
What is the role of Anhydrous Calcium Chloride in CP6 when it is added directly after reaction of HCl + Alcahol
Drying agent
Absorbs water produced in reaction of Alcahol + HCl = H2O + Halogenoalkane
- Also absorbs Unreacted Alcahol present in solution
Why do we discard the Aqueous layer in a separating funnel in CP6 and why does this work
Unreacted Alcahol is soluable in water due to hydrogen bonds = whereas Halogenoalkane is insoluble
Unreacted Alcahol is run off in aqueous layer + organic layer with HX is not
What is the role of Solid Sodium Hydrogen Carbonate in CP6
Neutralises any Unreacted Hydrochloric acid - HCl
HCl + NaHCO3 = NaCl + CO2 + H2O
What is the role of Anhydrous Sodium Sulphate in CP6 when it is added after running off the organic layer into a conical flask
Drying agent
Absorbs H2O/ water produced in neutralisation reaction of Unreacted HCl + NaHCO3 = NaCl + CO2 + H2O
Why is distillation used at the end of CP6 purification method
The Unreacted Alcohol has a higher BP than the Desired product of Halogenoalkane due to it being able to hydrogen bond
= therefore Halogenoalkane can be collected in distillation
What is the point of adding Nitric acid in the analysis of results part of CP6 when your trying to hydrolyse the HX to produce a silver Halide precipitate
Nitric acid reacts with any Unreacted Sodium Hydroxide/ NaOH used to hydrolyse the Halogenoalkane
