4. & 14. Chemical Bonding and Structure Flashcards

1
Q

Volatility

A

the tendency of a substance to vaporize

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2
Q

Working method to deduce molecular polarity

A
  1. Determine molecular geometry
  2. For each bond present, using electronegativity differences, deduce bond polarity for each bond present and draw the dipole moments as vectors
  3. Using vector addition, sum all the dipole moments present to establish whether or not there is a net dipole moment for the molecular. If so, it is polar.
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3
Q

Resonance

A

Using multiple structures for a molecule or ion that cannot be described fully with one.

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4
Q

Delocalisation

A

electrons are shared by more than two atoms in a molecule or ion, drawn in resonance

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5
Q

Allotropes

A

difference structural modifications of the same element

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6
Q

Properties of covalent network solids

A

Atoms are held together by covalent bonds in a giant 3d lattice structure

  • High melting points
  • Poor electrical conductors (exceptions: graphite & graphene)
  • Typically insoluble in common solvents
  • Generally hard, though in graphite the layers can slide past one another
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7
Q

Graphene’s unique properties

A
  • Thinnest and strongest of known materials, first two-dimensional crystal ever discovered
  • 300 times more efficient than copper as a thermal and electrical conducter
  • When rolled up into a sphere, it becomes fullerene
  • Future applications: graphene plastic composite materials to replace metals in aerospace industry & LCD & screens
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8
Q

Coordinate covalent bonding

A

The shared pair of electrons originate from one of the two bonding atoms

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9
Q

The order of intermolecular forces

A

London forces < dipole-dipole forces < hydrogen-bonds

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10
Q

Unique properties of + what is C60 fullerene

A

Carbon allotrope, atoms arranged in closed shells (trigonal pyramidal structure). Similar shape to soccerball, buckminsterfullerene or buckyballs. C60 is composed of individual molecules with strong covalent bonds but with weak London forces between. Can be used as gene or drug carriers, “cages”.

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11
Q

What is silicon dioxide

A

SiO2. Amorphous (solid with no ordered structure) as sand. Called quartz in its crystalline form. Si-O-Si bonding in a lattice. High melting point due to strong covalent bonds

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12
Q

What are London Forces

A
Aka dispersion force or instantaneous induced dipole-induced dipole forces. At a given instant of time, a non-polar molecule might have slightly more electron density than another part. This is the instantaneous dipole and will influence adjacent molecules.
The magnitude is dependent on 
● number of electrons
● size (volume) of the electron cloud
● shapes of molecules.
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13
Q

Polarizability

A

The ease of distortion of the electron cloud of a molecular entity by an electric field.

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14
Q

How is the strength of the London force related with the atomic radii, and thus amount of electrons?

A

V ∝ 1/r^6
Where V is potential energy associated with the interactions.
Also related to size (volume) of the electron cloud and the shapes of molecules

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15
Q

Dipole-dipole moments

A

In this type of intermolecular force, there is an attraction between the positive end of one permanent dipole and the negative end of another permanent dipole on an adjacent molecule

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16
Q

Hydrogen bonding (occur with N-H, O-H & F-H)

A

he hydrogen bond is an attractive interaction between a hydrogen atom from a molecule or a molecular fragment X–H in which X is more electronegative than H, and an atom or a group of atoms in the same or a different molecule, in which there is evidence of bond formation.

17
Q

Differentiate between electronegativity values

A

0 < Δχ < 0.4 = NP
0.5 ≤ Δχ ≤ 1.8 = P
Δχ > 1.8 = ionic

18
Q

Graphite’s properties

A

Has flat layers of hexagonal carbon rings (trigonal planar) attracted by weak intermolecular forces. The london forces are weak, hence the layers can slide past each other - hence it is a lubricant.
Good electrical conductor as it has delocalised pi electrons (the carbons only have 3 bonds).

19
Q

Diamond’s properties

A

Carbons form 4 covalent bonds in tetrahedral structures. No delocalised electrons, hence not conductive. Extremely high melting point and very hard.

20
Q

Coordination number

A

Number of ligands in a transition metal complex

21
Q

Ammine

A

Any of a class of inorganic coordination compounds of ammonia and a metallic salt.

22
Q

Calculate formal charge

A

FC = (#valence electrons) - 1/2(#bonding electrons) - (#non-bonding electrons).

23
Q

Why is formal charge useful?

A

Used to determine the preferred Lewis structure

24
Q

How to decide for the most stable Lewis structure

A
  • The one with difference in formal charge closest to zero.

- The one with the negative charge closest to the most electronegative ion.

25
Q

Outline which orbitals go into sigma and pi bonds

A

Sigma:
s + s
s + px
px + px

Pi:
py+py
pz+pz

26
Q

Bond order

A

Calculated by total number of bonds / total number of resonance structures.

27
Q

What determines strength of a metallic bond

A
  • charge of cation
  • # delocalised electrons
  • radius of cation
28
Q

F = K_c * (q1*q2)/r^2

A

Force = constant * (charge 1 * charge 2)/radius^2

29
Q

In terms of CHn
sp^3
sp^2
sp

A

sp^3: CH4
sp^2: C2H4
sp: C2H2