3.3.10 Aromatic chemistry Flashcards

1
Q

Describe the structure of benzene and why it has these properties

A
  • planar molecule
  • 6 carbon atoms each with 4 talent electrons (2 of which bond to adjacent carbons , 1 bonded to hydrogen and 1 moving freely in the p-orbital above and below the planar ring

-lone electrons in p-orbital combine to form DELOCALISED RING OF ELECTRONS

  • all length soo c-c bonds are same due to delocalised electrons

-bond length of c-c bond is between single bond (154pm) and double bond (134pm) so it is 139pm

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2
Q

Describe the difference in skeletal formula of kekules structure and the typical benzene structure

A
  • kekules shows double bonds as he thought there was alternating double and single bonds

but as we know electrons are delocalised so

-typical benzene structure has a ring of delocalised electrons within the carbon ring

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2
Q

Describe the difference in skeletal formula of kekules structure and the typical benzene structure

A
  • kekules shows double bonds as he thought there was alternating double and single bonds

but as we know electrons are delocalised so

-typical benzene structure has a ring of delocalised electrons within the carbon ring

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3
Q

explain how benzene is discovered to be more stable than kekules structure

A

enthalpy change of hydrogenation across a double bond is predicted to be -180KJmol-1 so overall in the kekules structure the enthalpy change of hydrogenation across all 3 double bonds should be -360KJmol-1

BUT

the experimental enthalpy of hydrogenation of benzene was found to be -208KJ mol-1 which mean that the enthalpy change of hydrogenation across the double bonds is actually greater and so the benzene is more stable than the theoretical cyclohexane-1,3,5-triene with 3 double bonds. (more energy required to break bonds)

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4
Q

What allows the benzene structure to be more stable than the kekules theoretical structure?

A

due to benezens delocalised ring of electrons

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5
Q

What are arenes?

A

aromatic compounds that contain a benzene ring

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6
Q

What are the 2 different ways to name arenas and when can you tell the difference

A

if it has anything BESIDES OH, NH2 attached to the benzene ring, then it is named with benzene at the end e.g bromobenzene

if there is OH or NH2 attached to the benzene ring then you name it phenyl (as if phenyl is a functional group) e.g Phenol, phenylamine

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7
Q

What type of mechanism do areas undergo?

A

electrophilic substitution

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8
Q

Why are areas unable to undergo electrophilic addition?

A

because the benzene ring does not actually have double bonds (c=c) it has a ring of delocalised electrons

and the benzene is stable so electrophilic addition would disrupt the stable ring of electrons

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9
Q

Why are arenas able to undergo electrophilic substitution”?

A

the benzene has a HIGH ELECTRON DENSITY from ring of delocalised electrons

this is attractive to electrophiles

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10
Q

what are the 2 electrophilic substitution reactions that arenes can undergo?

A
  1. friedel-crafts acylation
  2. nitration reaction
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10
Q

what are the 2 electrophilic substitution reactions that arenes can undergo?

A
  1. friedel-crafts acylation
  2. nitration reaction
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11
Q

in freidel-crafts acylation what must we react to create a strongly positive electrophile and how does this work

A

acyl chloride with AlCl3 (halogen carrier)

  • AlCl3 accepts a pair of electrons away from the acyl group
  • carbocation of acyl group is formed (this is the strong electrophile)
  • AlCl4- is also formed
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12
Q

Describe or draw out the mechanism for the reaction of benzene with strong electrophile and AlCl4-

A
  • delocalised electrons attracted to carbocation
  • 2 electrons move to form bond and break electron ring and positive charge develops
  • negative AlCl4- is attracted to positively charged ring and on of the chlorine atoms breaks away to form bond with hydrogen

-electrons in c-h bond move to neutralise positive charge and reform delocalised electron ring

  • AlCl3 catalyst is reformed
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13
Q

What does freidel-crafts acylation produce?

A

Phenylketone
HCL
AlCl3(reform)

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14
Q

What is nitrating benzenes useful for?

A

to make dyes for clothing and explosives

15
Q

How do we form nitrobenzene?

A

react benzene with CONCENTRATED NITIRIC ACID and SULFURIC ACID

16
Q

Before electrophilic substitution occurs to make a nitrobenzene, a strong electrophile needs to be made, how?

A

react the sulfuric acid with nitric acid to form H2NO3+ and HSO4-

H2NO3+ decomposes to from NO2+ (strong electrophile) and H20

17
Q

draw/explain mechanism of forming nitrobenzene

A
  • NO2+ attacked by benzene ring forming unstable positively charged ring
  • electrons in C-H bond move to reform the delocalised electron ring
  • nitrobenzene forms and H+ forms which reacts with H204- to reform H2SO4

(H2S04 is a catalyst)

18
Q

Why is a specific temperature required for forming nitrobenzene, what is this temp?

A

55 degrees or below
- this ensures only a single NO2 substitution
- above this results in multiple substitutions which could become very explosive