2nd Year Closed/Open Systems Flashcards
Closed System:
Work =
Integral (P) dv
First Law
Energy Can only be conserved:
Q - W = ΔU + ΔKE + ΔPE
ΔU =
Cv m ΔT
ΔH =
Cp m ΔT
Perfect Gas laws:
PV = mRT Pv = RT PV^y = const R = Cp - Cv
Constant Volume
Closed
ISOMETRIC
W=0
Q=m Cv ΔT
Constant Pressure
Closed
ISOBARIC
W = PΔV
Q= m Cp ΔT
Constant Temp
Closed
ISOTHERMAL
W = Q
ΔU = 0
W = P2V2Ln(V2/V1) = mRTln(V2/V1)
Constant Entorpy
ISENTROPIC
Q=0
W = (P2V2 - P1V1)/1-y
POLYTROPIC is the same but not with gamma.
Open System
SFEE
Q - W = ΔH + ΔKE + ΔPE
Open System
Work =
-integral (V) dp
mas flow rate =
density * Area* Velocity
When isothermal, work requirement for compression is…
LOWEST!
When isothermal, work output for expansion is…
LARGEST!
Nozzles:
Velocity increased
Pressure Decreased
Diffusers
Velocity decreases
Pressure Increases
Nozzle and diffuser assumptions:
Q= 0
W=O
ΔPE=0
(SFEE = ΔH + ΔEK = 0)
Compressors: (work?)
ON fluid
Turbines (work?)
BY fluid (on shaft)
work and compressor assumptions:
Q=0
ΔKE=0
ΔPE=0
SFEE = -W=ΔH (+ΔKE if given in question)
W=-∫P dv= - (myRT1)/(y-1)*((P2/P1)^((y-1)/y) - 1)
Mixing Process:
m(in) = m(out)
SFEE ΔH=0 = m Cp ΔT =0
Heat Exchangers
Depending on how system is defined…
SFEE = ΔH=0
or Q= ΔH (if taken across boundries)
Throttling Valve
SFEE ΔH=0