[23.2] manganate (VII) redox titrations Flashcards
what are the half equations for the reaction of manganate (VII) ions with iron (II) ions?
- reduction: MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ -> Mn²⁺ (aq) + 4H₂O (l)
- oxidation: Fe²⁺ (aq) -> Fe³⁺ (aq) + e⁻
what is the overall equation for the oxidation of Fe²⁺ ions by manganate (VII)?
MnO₄⁻ (aq) + 8H⁺ (aq) + 5Fe²⁺ (aq) -> Mn²⁺ (aq) + Fe³⁺ (aq) + 4H₂O (l)
what is the colour change for manganate (VII) redox titrations?
- MnO₄⁻ (aq) = purple
- Mn²⁺ (aq) = almost colourless
- end point is first permanent pink colour
how are redox titrations different from acid-base titrations?
- redox titrations involve transfer of electrons, rather than neutralisation as in acid-base titrations
- redox titrations are self-indicating
what are the problems using potassium manganate (VII) solution? (4)
- can’t be used in titrations with chloride or bromide ions as it oxidises these. this is why the solution is acidified with sulfuric acid, not HCl
- isn’t a primary standard ie. can’t be made up to give a stable solution of accurately known concentration. it is too strongly coloured to see when all of the crystals you have used have dissolved
- over a period of time, it oxidises the water it is dissolved in to oxygen, leaving a brown suspension of manganese (IV) oxide, so the concentration is not guaranteed
- difficult to read meniscus as the colour is so dark
how can you analyse iron if it is in the element Fe (0)?
react it with sulfuric acid to oxidise it to Fe²⁺ ready for analysis
how can you analyse iron if it is Fe (+3)?
- react with Zn to reduce it to Fe²⁺ ready for analysis
- remaining zinc must be removed first to stop it reducing Fe³⁺ formed in the titration back to Fe²⁺
what are the half equations for the reaction of manganate (VII) ions with ethanedioic acid, (COOH)₂ (aq)?
- reduction: MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ -> Mn²⁺ (aq) + 4H₂O (l)
- oxidation: (COOH)₂ (aq) -> 2CO₂ (g) + 2H⁺ (aq) + 2e⁻
what is the overall equation for the reaction of ethanedioic acid with acidified manganate (VII) ions?
2MnO₄⁻ (aq) + 6H⁺ (aq) + 5(COOH)₂ (aq) -> 2Mn²⁺ (aq) + 10CO₂ (g)+ 8H₂O (l)
what is the overall equation for the reaction of ethandioate ions (C₂O₄²⁻) with acidified potassium manganate (VII)?
5C₂O₄²⁻ + 2MnO₄⁻ + 16H⁺ -> 10CO₂ + 2Mn²⁺ + 8H₂O