[21.1] buffer solutions Flashcards

1
Q

what is a buffer?

A

a system that minimises pH changes when small amounts of an acid or a base are added

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2
Q

what 2 components of buffers mean pH changes are minimised?

A
  • weak acid, HA, removes added alkali
  • conjugate base, A-, removes added acid
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3
Q

what 2 ways can buffers be prepared?

A
  • mixture of weak acid and its salt
  • mixture of an excess of WA and strong base (partial neutralisation of WA)
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4
Q

how can buffers be prepared from a weak acid and its salt? (based on ethanoic acid)

A
  • when ethanoic acid is added to water, the acid partially dissociates and the amount of ethanoate ions in solution is very small
  • when salts of weak acids are added to water, it completely dissolves
  • ethanoic acid = source of weak acid component
  • salts of weak acids = source of conjugate base

CH₃COOH (aq) ⇌ H⁺(aq) + CH₃COO⁻ (aq)
CH₃COONa (s) + aq -> CH₃COO⁻ (aq) + Na⁺ (aq)

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5
Q

how can control of pH be explained in terms of shifts in the equilibrium positions using le chatelier’s principle when alkali is added?

A

HA (aq) ⇌ H+ (aq) + A- (aq)
1. [OH-] increases
2. small conc of H+ ions react with OH- ions: H⁺ + OH⁻ -> H₂O
3. HA dissociates
4. POE shifts to right to restore most of H+ ions

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5
Q

how can control of pH be explained in terms of shifts in the equilibrium positions using le chatelier’s principle when acid is added?

A

HA (aq) ⇌ H+ (aq) + A- (aq)
1. [H+] increases
2. H+ ions react with conjugate base, A-
3. equilibrium position shifts to the left, removing most of the H+ ions

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5
Q

when is a buffer most effective at removing either added acid or alkali?

A

when there are equal concentrations of the weak acid and its conjugate base

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5
Q

how can buffers be prepared by partial neutralisation of the weak acid (ethanoic acid)?

A
  • aqueous solution of an alkali + excess of weak acid
  • weak acid is partially neutralised by alkali, forming the conjugate base
  • resulting solution contains a mixture of salt of WA and any unreacted WA
  • CH₃COOH and CH₃COO⁻ act as two resevoirs that are able to remove added acid and alkali by shifting the buffer’s equilibrium

CH₃COOH (aq) ⇌ H⁺ (aq) + CH₃COO⁻ (aq)

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6
Q

why is a buffer most effective when [HA] = [A-]?

A
  • pH of buffer solution is same as pKa value of HaA
  • operating pH is around 2 pH units, centred at pH of pKa value
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7
Q

how do you calculate the pH of a buffer solution?

A

[H+] = Ka × ([HA] / [A-])

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8
Q

how do you calculate the pH of a buffer solution when [HA] = [A-]?

A
  • Ka = [H+]
  • pKa = pH
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