22-GLYCOGEN METABOLISM – Dr. Venk Flashcards

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1
Q

What is the advantage of glycogen breakdown by phosphorolysis compared to hydrolysis?

A

Phosphorolysis will yield glucose-1-phosphate without using any ATP.

This is important when energy needs are very short in supply. Also, the body’s concentration of P_i is high enough to drive the reaction towards the right direction towards glycogen breakdown. One glucose molecule is broken off at a time to give glucose-1-phosphate, which can be readily converted to glucose-6-phosphate.

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2
Q

Describe the significance of glycogenolysis in liver versus muscle.

A

In muscle glycogenolysis is used to breakdown glycogen, convert glucose-1-phosphate to glucose-6-phosphate and directly channel it into glycolysis for the muscle’s ATP needs. In muscle, glucose-6-phosphatase is ABSENT to insure that glucose directly enters glycolysis and not another pathway after glycogenolysis.
In the liver, glucose-6-phosphatase will use the end product of glycogenolysis and cleave off the phosphate to release free glucose in the blood for the body’s needs.

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3
Q

Describe how glucose-1-phosphate is converted to glucose-6-phoshphate.

A

Phosphoglucomutase converts G-1-Phosphate to G-6-Phosphate. The enzyme contains a phosphorylated Serine in the active site. G-1-Phosphate binds to the active site and the enzyme’s phosphate is attached to C-6. A transient intermediate, G-1,6-bisphosphate is generated and stays in the active site. The enzyme will then remove the phosphate on C-1, regenerating the phosphoenzyme. G-6-Phosphate is released from the active site.

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4
Q

Describe the phosphorylation mediated regulation of enzyme activity.

A

Phosphorylation of many enzymes is a simple way of avoiding the futile cycle of having synthesis and breakdown occurring at the same time.

Phorphorylation of PKA will lead to activation and breakdown of glycogen. But, phosphorylation of Glycogen Synthase will lead to its inactivation, preventing synthesis in the middle of breakdown.

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5
Q

Name the two hormones that are involved in triggering glycogenolysis and describe their specificity.

A

Epinephrine will bind to alpha-adrenergic receptors and activate the Phospholipase C pathway. G-proteins will activate PLC which will hydrolize PIP2 to IP3 and DAG. IP3 will bind to the endoplasmic reticulum and release Ca2+. Ca2+ will in turn bind to calmodulin-like subunit of Phosphrylase Kinase. At the same time, DAG will active Protein Kinase C, which will phosphorylate glycogen synthase, making it inactive (eliminating synthesis and breakdown at the same time).
Glucagon, released by beta cells of the pancrease will bind to the G-protein receptor of hepatic cells. This activates adenylate cyclase to release the second messenger cAMP. CAMP will bind to the regulatory subunit of Protein Kinase A to activate it. Once PKA is activated it will phosphorylate phosphorylase kinase.

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6
Q

Describe the mechanism by which PKA is activated.

A

Glucagon binds the G-protein receptor of hepatic cells. This activates adenylate cyclase to release the second messenger cAMP. cAMP will bind to the regulatory (R) subunit of Protein Kinase A, causing the R subunit to separate from the catalytic (C) subunit, which is now an active enzyme. Once PKA is activated it will phosphorylate phosphorylase kinase.

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7
Q

Describe the glycogenolysis cascade, and discuss the kinases that are involved in the pathway.

A

Glycogenolysis regulation is done through a complex cascade of phosphorylations. Alpha cells of the pancreas sense low blood glucose and will release glucagon. Glucagon will bind to the G-protein receptor of hepatic cells. This activates adenylate cyclase to release the second messenger cAMP. CAMP will bind to the regulatory subunit of Protein Kinase A to activate it. Once PKA is activated it will phosphorylate phosphorylase kinase. The phosphorylated Phosphorylase kinase will further phosphorylate Phosphorylase-b to Phosphorylase-a. Phosphorylase-b can generate G-1-phosphate under resting conditions. But, Phosphorylase-a can have a larger increase in glycogen breakdown under higher energy demands.

Glycogenolysis is stopped by the enzyme Phosphoprotein Phosphatase-1 (PP-1). It will remove the phosphate from Phosphorylase Kinase, so that it can no longer activate Phosphorylase-b to Phosphorylase-a. And it will also remove the phosphate from Phosphorylase-a, making it the less active Phosphorylase-b. The actions of PP-1 are regulated by Phosphoprotein Phosphatase Inhibitor (PPI). PPI will inhibit PP-1 by binding to it. PPI will only bind to PP-1 when phosphorylated by PKA. By doing this, the cells can insure that the phosphate attached by PKA to Phosphorylase Kinase and Phosphorylase-a are not immediately removed by PP-1.

To summarize,:
PKA will phosphorylate Phosphorylase Kinase to make it active
Phosphorylase Kinase will phosphorylate phosphorylase-b to phosphorylase-a
PKA will also phosphorylate PPI, which will inhibit PP-1 (PP-1 removes phosphates from phosphorylase-a and Phosphorylase Kinase)

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8
Q

Describe the role of calcium in glycogenolysis, especially with reference to the neuromuscular stimulus.

A

When the muscle is stimulated, Ca2+ is released to initiate muscular contractions. In addition to stimulating muscle cells, Ca2+ can bind to a calmodulin-like subunit of Phosphorylase Kinase and activate it. This way, the muscles are stimulated and Phosphorylase Kinase is activated to initiate glycogen breakdown for the muscles’ energy needs.

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9
Q

Describe the activation of the alpha-adrenergic receptor and the associated cascade of biochemical events.

A

Epinephrine will bind to alpha-adrenergic receptors and activate the Phospholipase C pathway. G-proteins will activate PLC which will hydrolyze PIP_2 to IP3 and DAG. IP_3 will bind to the endoplasmic reticulum and release Ca2+. Ca2+ will in turn bind to calmodulin-like subunits of Phosphrylase Kinase. At the same time, DAG will activate Protein Kinase C, which will phosphorylate glycogen synthase, making it inactive (eliminating synthesis and breakdown at the same time).

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10
Q

Describe the role of protein phosphatase inhibitor (PPI) during glycogenolysis.

A

Glycogenolysis is stopped by the enzyme Phosphoprotein Phosphatase-1 (PP-1). It will remove the phosphate from Phosphorylase Kinase, so that it can no longer activate Phosphorylase-b to Phosphorylase-a. And it will also remove the phosphate from Phosphorylase-a, making it the less active Phosphorylase-b. The actions of PP-1 are regulated by Phosphoprotein Phosphatase Inhibitor (PPI). PPI will inhibit PP-1 by binding to it. PPI will only bind to PP-1 when phosphorylated by PKA. By doing this, the cells can insure that the phosphate attached by PKA to Phosphorylase Kinase and Phosphorylase-a are not immediately removed by PP-1.

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11
Q

Describe the fight of flight response.

A

Epinephrine is a hormone released from the adrenal medulla under stressful conditions. It will prep the body for a burst of high activity. The hormone will bind to alpha-adrenergic receptors and start the glycogenolysis cascade to provide the necessary ATP and it will shut off glycogen synthesis.

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12
Q

Describe the role of AMP and Calcium in muscle.

A

AMP is the “spent energy” of muscles. AMP is a positive effector for glycogen phosphorylase. AMP stabilizes glycogen phosphorylase in the Relaxed conformation, allowing it to cleave glycogen for more ATP synthesis.

Calcium binds to phosphorylase kinase and activates it and continues glycolgenolysis. Ca2+ also directly activates protein Kinase C, similar to DAG, which also starts the glycogenolysis cascade.

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13
Q

Describe how UDP-glucose is formed.

A

Before glucose is incorporated into glycogen, it must be activated into UDP-glucose. Uridylyl trasferase will join G-1-Phosphate and UTP into UDP-glucose. Now, glycogen synthase can use it to produce glycogen.

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14
Q

How are alpha 1-6 branches in glycogen formed?

A

Glucan transferase/branching enzyme will transfer a 6-7 glucose fragment from the end of the growing glycogen polymer (at least 11 glucose long) and relocate it to an internal glucose reside at the C-6 position.

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15
Q

What is glycogenin?

A

Glycogenin has a tyrosine reside that can attach to the C-1 of UDP-glucose. This acts as a primer for glycogen synthase. All glucose residues will added from this first glucose on the primer.

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16
Q

Describe the three major allosteric effectors and its effect on glycogen synthase-b.

A

Glycogen synthase-b is the phosphorylated form of glycogen synthase. Glycogen synthase will have:
Decreased affinity for UDP-glucose (substrate)
Increased dependency on glycogen synthase for allosteric activator G-6-Phosphate
Increased affinity for ATP and Pi

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17
Q

Describe the properties and role of glucose-6-phosphatase in glycogen metabolism.

A

Glucose-6-Phosphatase is located on the cisternal surface of the ER. In order for the ER to package glucose for excretion, G-6-P must transverse the ER membrane by a translocase. Then, the G-6-Phosphatase can cleave the phosphate off of G-6-P and yield free glucose which enters the bloodstream. OR, in muscle, where G-6-Phosphatase is absent, G-6-P can be directly channeled into glycolysis for ATP production.

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18
Q

Describe how a futile cycle of glycogenolysis and glycogen synthesis (i.e. operating at the same time) is prevented.

A

Phosphorylation of many enzymes is a simple way of avoiding the futile cycle of having synthesis and breakdown occuring at the same time. Phorphorylation of PKA will lead to activation and breakdown of glycogen. But, phosphorylation of Glycogen Synthase will lead to its inactivation, preventing synthesis in the middle of breakdown.

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19
Q

Describe very briefly the mode of action of alpha-andrenergic and beta-andrenergic hormones.

A

The action of the hormones at alpha-adrenergic receptors are coupled through G-proteins that activate phospholipase C (PLC), leading to the hydrolysis of PIP2 into IP3 and DAG.

IP3 releases DAG and Ca2+ activates PKC, which phosphorylates and Inactivates glycogen synthase, either directly or via Ca-Calmodulin.

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20
Q

What are heterotrimeric G proteins?

A

Proteins that are made up of three different subunits (alpha, beta, gamma)

21
Q

Briefly describe how protein kinase A (PKA) is activated.

A

Inactive Protein Kinase A (PKA) has a regulatory (R) subunit and a catalytic (C) subunit. 2 cAMP bind to the R2 subunit that detaches from the C subunit making the C subunit an active PKA enzyme.

22
Q

What are the products that are formed by the action of phospholipase C?

A

Phospholipase C results in an increase of PIP2 hydrolysis which produces IP3 and DAG.

23
Q

Describe the control of blood glucose level by hormones.

A

The role of insulin is to increase the uptake of glucose from the blood (anabolic/synthesis inducing), whereas glucagons and epinephrine induce degradative events (catabolic/degradative).

24
Q

Name the enzyme(s) or protein(s) that are affected in the following diseases:

Pompe’s disease 
Cori’s disease
McArdle's disease
Aderson's disease
Von Gierke's disease
Hers disease
A

Pompe’s disease – lysosomal alpha-glucosidase deficiency
Cori’s disease – defect in debranching enzyme
McArdle’s disease – skeletal muscle phosphorylase deficiency
Anderson’s disease – defect in branching enzyme
Von Gierke’s disease – lack of glucose-6-phosphatase
Hers disease - liver phosphorylase deficiency

25
Q

Explain the reason why liver phosphorylase enzyme would not be prone to Allosteric regulation by glucose-6-phosphate as opposed to muscle glycogen phosphorylase.

A

In the liver, glucose-6-phosphate is immediately converted to glucose via glucose-6-phosphatase, thus there is no G-6-P to act as a negative Allosteric factor on liver’s glycogen phosphorylase.

Whereas, in muscle, there is no glucose-6-phosphatase to act on G-6-P, and G-6-P is available as a negative Allosteric factor for muscle’s glycogen phosphorylase.

26
Q

Can you explain why glycogen phosphorylase is phosphorylates by only one kinase to be activated, whereas glycogen synthase is inactivated progressively by many kinases?

A

Glycogen phosphorylase is a homodimeric enzyme with only one site of activation.

Glycogen synthase is inactivated by many kinases because it has four identical subunits, each with Serine residues that can be phosphorylated.

27
Q

Can Von Gierke’s patients carry out gluconeogenesis normally? If not, explain why.

A

No. Von Geirke’s patients lack glucose-6-phosphatase, thus are unable to produce glucose from G-6-P in the liver. This causes a buildup of G-6-P in the liver that then acts as a negative Allosteric factor for phosphorylase b (aka. glycogen phosphorylase), stopping gluconeogenesis.

28
Q

Which of the tissues, muscle or liver, would contain more glycogen per gram of tissue?

A

Muscle!

Muscle has ~400g of glycogen
Liver has ~100g of glycogen

29
Q

What are the physiological advantages of having branched glycogen as opposed to linear glycogen in mammals?

A

Branching allows for multiple phosphorylases to cleave the branched glycogen simultaneously since only one phosphorylase can act on a branch at any give point via its non-reducing end

30
Q

Can we conceive how much liver glycogen serves for it’s own metabolism (aside from the glucose that is pumped into the blood)?

A

..?

31
Q

Describe the relationship of glucose/glycogen metabolism to Type I and Type II diabetes.

A

Type 1 diabetes: insulin is not produced at all or enough, which results in high blood sugar. There is a very low [insulin]/[glucagon] ratio. Therefore, glucagon levels are high and glycogen metabolism is high, whereas glucose metabolism is low.

Type 2 diabetes: insulin levels are fine but cannot bind properly to receptors. Therefore, glycogen metabolism is high or normal, while glucose metabolism is low.

32
Q

True or false: Type 1 diabetes can better be controlled by insulin administration.

A

True

33
Q

What is a hypothesis as to why Type II diabetics are obese?

A

Because insulin cannot bind properly, type II diabetics have high blood glucose levels, but the body cannot sense it, since the tissues are not receiving it. Therefore, the body causes glycogen to break down and produce more glucose into the system, and sends signals to the brain that there is insufficient food/nutrients. This will cause people to be hungry and eat more.

34
Q

Describe the chemical basis of retinopathy.

A

Excess blood glucose sugar (due to diabetes type I or type II) is converted to Glucitol (sorbitol) by non-specific dehydrogenase and result on osmotic balances in tissues like the eye lens and causes Cataracts due to high viscosity of sorbitol. The osmotic imbalance also causes retinopathy and the excess glucose by-products can cause various metabolic diseases, like diabetic retinopathy.

35
Q

Describe the production of Glucitol/Sorbitol.

A

Excess glucose in blood (from type I diabetes) is converted into Glucitol/sorbitol by nonspecific dehydrogenases in tissues like the retina and kidney.

36
Q

What is glycation?

A

Glycation (sometimes called non-enzymatic glycosylation) is the result of typically covalent bonding of a protein or lipid molecule with a sugar molecule, such as fructose or glucose, without the controlling action of an enzyme

37
Q

Describe then biochemical basis of nephropathy.

A

In type I diabetes, blood sugar levels are high, as the insulin/glucagon ratio is very low. Excess blood glucose is converted to sorbitol/Glucitol, which is highly osmotic. This osmotic imbalance disrupts tissue in the kidney causing nephropathy.

38
Q

Explain the biochemical/physiological basis of diabetes being a cardiovascular problem.

A

Diabetes is a disease caused by high blood glucose levels. When there is excess blood glucose, Glucitol/sorbitol is generated, which increases the viscosity. This causes an increase strain on your cardiovascular system as it attempts to pump the fluid.

39
Q

Hemoglobin A1c levels are used as an indicator to assess the severity of diabetes. Explain this in biochemical terms.

A

Hemoglobin A1c is produced as a metabolic defect of excess glucose in the blood. Therefore, elevated levels indicate the person possibly having diabetes

40
Q

Explain the biochemical basis of hypoglycemia

A

Hypoglycemia (low blood sugar) arises from the overproduction of insulin, meaning insulin/glucagon ratio is very high. This leads to over uptake of glucose in cells resulting in low blood glucose levels.

41
Q

What are GLUTs?

A

A tissue specific transport protein that uptake/transport glucose in to cells from the blood

42
Q

What is the normal fasting level of glucose in the blood? (Explain in percent and mM concentrations)

A

80-120 mg/dL (~4.5-7mMol/liter) : 4-6 percent

43
Q

Muscle can respond to insulin, but doesn’t respond to glucagon. Explain and rationalize why evolution made it this way? What is so special about muscle compared to liver?

A

Muscle’s sole purpose is for motion, thus it has no need to store glucose, simply create it and use it. That is why it has receptors for insulin and not glucagon.

44
Q

Describe the major connecting point between glycogen and gluconeogensis metabolism.

A

Both use or produce inorganic phosphate. Synthesis of glycogen produces two phosphates and gluconeogensis use phosphate (phosphorolysis) to produce glucose-1-phosphate from glycogen.

45
Q

Why are proteins more prone to non enzymatic glycation?

A

Proteins have amino terminal residues or lysines that can react with the aldehyde of glucose

46
Q

Explain in biochemical/biophysical terms why glucose molecule in excess concentrations is a big problem maker on tissues and organs.

A

The excess of glucose molecule is a big problem maker because:

1) it reacts with proteins (glycation) which artificially damages many protein/enzyme activities
2) it can be converted to Glucitol/sorbitol that causes an osmotic imbalance due to Glucitol/sorbitol’s high viscosity
3) glucoses’ byproduct can also cause metabolic defects that may impact tissue and organs

47
Q

The laboratory values of a patient exhibited the following conditions: low blood glucose levels, normal blood urea BUN levels, abnormal levels of glucose-6-phosphate in ER. This could be due to?

A

glucose-6-phosphatase associated Von Gierke’s disease

48
Q

What does glycogen phosphorylase do?

A

cleaves alpha 1,4 links via phosphorolysis