22 - Enthalpy and entropy Flashcards
What is lattice enthalpy?
enthalpy change when one mole of an ionic compound is formed from its gaseous ions under standard conditions
K+(g) + CL-(g) -> KCl(s)
is lattice enthalpy endothermic or exothermic?
it involves bond formation from separate gaseous ions, so it is exothermic, and the value of enthalpy change is always negative
What is a Born-Haber cycle?
the indirect determination of lattice enthalpy
-> lattice enthalpy cant be directly measured
Routes of a Born-Haber cycle
Route 1
-> formation of gaseous atoms (Endothermic)
-> formation of gaseous ions (Endothermic)
-> lattice formation (Exothermic)
Route 2
-> converts elements in their standard states directly into the ionic lattice, the enthalpy change of formation (Exothermic)
standard enthalpy change of formation ΔfH°
enthalpy change when one mole of a compound is formed from its elements under standard conditions
Na(g) + 0.5Cl2(g) -> Nacl(s) =-711klmol-1
standard enthalpy change of atomisation ΔatH°
enthalpy change when one mole of gaseous atoms is formed from its elements under standard conditions
Na(s) -> Na (g) = +107 kjmol-1
0.5Cl2 -> Cl(g) = + 121 kjmol-1
is ΔatH° endothermic or exothermic?
endothermic as bonds are broken to form gaseuos atoms.
for a gas, ΔatH° refers to the enthalpy of the bond being broken
Cl2(g) -> 2Cl(g)
First ionisation energy ΔieH°
enthalpy change required to remove one electron from each atom in one mole of gaseous atom, to form one mole of gaseous 1+ ions, under standard conditions and states
Na(g) -> Na+(g) + e-
Are ΔieH° endothermic or exothermic?
Endothermic as energy is required to overcome the attraction between the negative electron and the positive nucleus
First electron affinity
what does feasibility mean
- describes if a reaction can happen and is energetically feasible
what is free energy
the overall change in energy during a chemical reaction
made up of the enthalpy change ΔH (heat transfer between surroundings and chemical surroundings) and the entropy change at the temperature TΔS
gibbs equation
- units of each value
ΔG = ΔH - TΔS
T= kelvin (+273)
ΔH= kJmol-1
ΔS= kJK-1mol-1
when is a reaction feasible
ΔG < 0
limitations of predictions made for feasibility
a very large activation energy results in a slow rate. so it may seem feasible but ΔG doesnt cond=sider the kinetics or rate of reaction