2.1.3 Amount of substance Flashcards

1
Q

define the term amount of substance

A
  • a quantity to count number of particles in substance
  • measured in unit called mole (mol)
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2
Q

define the term mole

A
  • the unit for amount of substance
  • 1 mole is the amount of substance that contains 6.02 x 10*23 particles
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3
Q

define the term Avogadro constant

A
  • N
  • the number of particles per mole
  • 6.02 x 10*23
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4
Q

define the term molar mass

A
  • M
  • links moles with mass
    > it’s the mass per mole of a substance
  • units are gmol-1
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5
Q

give the formula for calculating molar mass

A

moles = mass / mr
- mr = mass / moles

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6
Q

define the term molar gas volume

A
  • the volume per mole of a gas
  • units are dm3mol-1
  • at room temp + pressure the vol is approx 24.9 dm3mol-1
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7
Q

give the formula to calculate the molar gas equation at room temp + pressure

A

volume (dm3) = amount of gas (moles) x 24

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8
Q

what is an empirical formula

A
  • the simplest whole number ratio of atoms of each element present in a compound
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9
Q

describe the steps needed to calculate the empirical formulae of a compound

A
  • divide the amount (g) of each element by molar mass - gives you molar ratio
  • divide the answer of each element by smallest number
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10
Q

what is molecular formula

A
  • the number and type of atoms of each element in a molecule
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11
Q

how would you calculate the molecular formula of a compound

A
  • you would divide the relative molecular / formula mass (given) by the empirical formula mass (total mr) to give the number of units of that compound in a molecule
  • you would multiply that number by the compound to get the molecular formula
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12
Q

define the terms anhydrous + hydrated

A
  • anhydrous = without water
  • hydrated = with water
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13
Q

what is water of crystallisation

A
  • many crystals are hydrated meaning they contain water molecules as part of their crystalline structure
  • the water is known as the water of crystallisation
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14
Q

what are hydrated salts

A
  • salt crystals containing waters of crystallisation
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15
Q

every hydrated salt contains ……. of water molecules

A
  • a specific number
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16
Q

what are the assumptions of water of crystallisation

A
  • how accurate is an experimental formula / how pure is it
  • all the water has been evaporated
  • no further decomposition
17
Q

what is the formula for working out concentration of solution

A
  • concentration = moles / volume
18
Q

how can you change concentration from moldm-3 to gdm-3

A
  • multiply your concentration by your mr to get gdm-3
19
Q

what is molar solutions in relation to concentration

A
  • ‘M’ means molar and refers to a solution with a concentration in moles per cubic decimeter moldm-3
  • example:
    2 moldm-3 = 2M
20
Q

what is the formula for the ideal gas equation (give units)

A

pV = nRT
- p = pressure (Pa)
- V = volume (m3)
- n = amount of gas molecules (mol)
- R = ideal gas constant = 8.31 Jmol-1K-1
- T = temperature (K)

21
Q

what is the theoretical yield

A
  • maximum possible amount of product
22
Q

why is it difficult to achieve 100% in a percentage yield

A
  • reaction may not have gone to completion
  • side reactions may occur, leading to by-products
  • reactants may may not be pure
  • some of reactants / products may be left behind in the apparatus
  • separation + purification may result in loss of some product
23
Q

what is the formula for percentage yield

A
  • percentage yield = (actual yield / theoretical yield) x 100
24
Q

what is atom economy

A
  • a measure of how well atoms have been utilised
    > describes the efficiency of a reaction in terms of all atoms involved (takes into account all products including waste products)
25
Q

what is the formula to work out atom economy

A

atom economy = (mr of desired product / mr of all products) x 100

26
Q

how can atom economy benefit society

A
  • using processes with higher atom economy companies can reduce amount of waste product
  • high atom economy make processes more sustainable as they can be maintained at a productive level without completely using up resources