2013 Chains, Energy and Resources Flashcards
The branched-chain isomer B has a lower boiling point than the straight chain alkane A
• B has less surface (area of) contact
• B has fewer van der Waals’ forces OR B has weaker
van der Waals’ forces
• So less energy needed to break the intermolecular forces in B
When cracking takes place, a large number of products is formed
Suggest why a large number of products are formed
• Any carbon–carbon bond (in the chain) can
break
Explain the term homologous series
- A series of organic compounds
- With the same functional group
- But with each successive group differing by CH2
What is meant by the term stereisomers
• Same structural formula
• Different arrangement (of atoms) in space OR different
spatial arrangement
What is meant by the term enthalpy change of combustion
- Enthalpy change that occurs when one mole of substance
* Completely combusts OR reacts fully with oxygen
Describe the mechanism of the reaction that forms iodomethane and hydrogen bromide
• Radical substitution Initiation • IBr -> Br + I • Homolytic fission Propagation • Br + CH4 -> HBr + CH3 • Br + CH4 -> HBr + CH3 Termination • I + I -> I2
Describe and explain, using equations, how the concentration of ozone in the stratosphere is maintained
- O3 -> O2 + O
- O + O2 -> O3
- Rate of ozone decomposition (almost) equals rate of ozone formation
Give an everyday use for infrared spectroscopy
- Monitor air pollution
* Breathalysers
State one type of a biodegradable alternative to CFCs
• HCFCs OR hydrocarbons OR HFCs
Why does the petroleum industry process straight-chain alkanes into cyclic hydrocarbons
• Cyclic hydrocarbons promote efficient combustion
Compound I is a alkene. It is shaken with aqueous bromine. What colour change will you see
• Orange to colourless
Why is the reaction of 1-bromobutane with hot KOH(aq) slower than the reaction of 1-iodobutane with hot KOH(aq)
- C−I bond is weaker than C−Br bond
* C−I bond is easier to break than C−Br bond
C3H6(g) + NH3(g) 0.5O2 -> CH2CHCN(g) + 3H2O(g)
∆H = -540
Using le Chateliers principle describe the effect on the position of the equilibrium.
A temperature of 450oC
A pressure above 2.5
No catalyst
• (As temperature rises) position of equilibrium changes to minimise effect of temperature rise by absorbing energy
• As temperature rises the position of equilibrium shifts to the left AND increase in pressure shifts the equilibrium to the left
• Relates change with temperature to the
(forward) reaction being exothermic
• Change with pressure because there are fewer moles of reactants
• Removing the catalyst does not change the position of
equilibrium
Using Boltzmann diagrams explain the effect on the rate of a reaction of:
- Increasing the temperature
- Adding a catalyst
• Axes labelled
(number of) molecules on y-axis and energy on x-axis
• Idea that activation energy is lowered with a catalyst
Collision theory
• Reaction is faster with catalyst AND when temperature is increased
• Greater proportion of molecules with energy above
activation energy
• More effective collisions OR more successful collisions