19.2.6 Electrochemicamical Determinants of Equilibria Flashcards
Electrochemical Determinants of Equilibria
- At equilibrium, the Nernst equation reduces to E ̊ cell = (R · T) / (n · F) · lnK eq .
- This relationship can be used to calculate equilibrium constants (K eq ) based on electrochemical data.
note
- At equilibrium, there is no driving force for a redox reaction to proceed in either direction, so the cell voltage (E cell ) is zero. This can be used to simplify the Nernst equation to E ̊ cell – (R · T) / (n · F) · lnQ. Since Q = K eq at equilibrium, this equation can be used to calculate K eq , given E ̊ cell .
- One application of this is in determining the solubility product constant (K sp ) of a compound.
- First, E ̊ cell must be calculated by breaking the reaction into half-reactions. Once this calculation has been made, finding K sp is simply a matter of plugging the numbers into the formula.
Which would best determine the equilibrium constant inside the cells of a car battery?
[H + ] and [HSO4− ]
Which best describes the reaction that occurs when a car battery discharges?
Oxidation-reduction
Which of the following is the oxidation half-reaction when a battery is discharging?
Pb(s) + HSO4− (aq) → PbSO4(s) + H + (aq) + 2e−
Which type of reaction occurs inside the cells of a car battery?
Oxidation
When does equilibrium occur in a battery?
Ecell = 0
Which best describes the relationship between the reaction quotient and the voltage of a car battery?
↓ Q: ↑ battery potential
Which of the following types of data have a triangular relationship?
Composition, electrochemical, and calorimetric
Which best represents an oxidation half-reaction?
Ag → Ag+ + e−
Which trends best describes what happens when a car battery discharges?
↓[H+] and ↓[HSO4-]
↑Q:↓ battery potential
How many half-reactions occur when a car battery discharges?
Two
Calculate the equilibrium constant for the following reaction at 25°C, given that
E°cell = +0.99 V
3Cu(s) + Cr2O72-(aq) + 14H+(aq) –> 3Cu2+(aq) + 2Cr3+(aq) + 7H2O(l)
2.18 × 10^100