18: pH Flashcards

1
Q

What the basicity of an acid

A

The number of H† ions that can be released from 1 molecule of the acid

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2
Q

Give an example of a monobasic acid

A

HCl

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3
Q

Give an example of a dibasic acid

A

H₂SO₄

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4
Q

What is the equation to work out pH when you have [H†]

A

pH = -log[H†]

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5
Q

How to work out [H†], given pH

A

[H†] = 10^-pH

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6
Q

What is [H†] equal to for a strong acid

A

The concentration of the acid

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7
Q

What is the equation for Kw

A

Kw = [H†][OH¯]

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8
Q

How to work out the pH of pure water

A

[H†]=[OH¯]

So Kw = [H†]²

[H†] = (1.00x10¯¹⁴)^½

-log[H†] = 7.00

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9
Q

How to work out the pH of strong alkalis

A

The [OH¯] = conc. of base

Rearrange Kw for H†

[H†] = Kw / [OH¯]

pH = -log[H†]

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10
Q

What is the general Ka equation

A

[H†][A¯] / [HA]

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11
Q

What does the value of Ka tell you about the strength of an acid

A

The larger the value of the Ka, the higher the H† conc., so the stronger the acid

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12
Q

What is the equation for working out pKa from Ka

A

pKa = -logKa

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13
Q

How to find Ka from pKa

A

Ka = 10^-pKa

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14
Q

What assumptions are made when calculating the pH of a weak acid

A

-Assume [H†] = [A¯]
So Ka ≈ [H†]² /[HA]

-Assume that the undissociated acid concentration [HA], is equal to the total concentration of the acid, including those molecules that have dissociated

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15
Q

What is the rearrangement of
Ka = [H†][A¯] / [HA]

For [H†] given some assumptions about weak acids

A

[H†] ≈ (Ka[HA]) ^½

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16
Q

What are the limitations of assuming that [H†] = [A¯] when calculating pH of a weak acid

A

It ignores the H† ions formed by ionisation of the water solvent. This is reasonable provided that the number of H† from ionisation of the acid is much higher than the number that come from the water

17
Q

What are the limitations of assuming that [HA] = total conc. of the acid
When calculating pH of a weak acid

A

Ignores the fact that as some of the HA has broken up into H† and A¯, the actual concentration of the undissociated HA is less than the overall acid concentration

18
Q

What is a buffer solution

A

A system that minimises pH changes on addition of small amounts of acid or base

19
Q

What does a buffer solution contain

A

A mixture of a weak acid and its conjugate base

20
Q

What happens in a ethanoic acid buffer solution when a small amount of acid is added

A

CH₃COOH ⇌ CH₃COO¯ + H†

The increase in [H†] is opposed by the equilibrium shifting to the left, removing [H†] and forming CH₃COOH.

So [H†] doesn’t actually increase by much, and the pH is only slightly changed

21
Q

What happens in a ethanoic acid buffer solution when a small amount of alkali is added

A

It will react with the H† in the solution
(H† +OH¯ → H₂O)

The equilibrium:

CH₃COOH ⇌ CH₃COO¯ + H†

Will shift to the right to oppose the decrease in [H†]

Overall therefore, the [H†] doesn’t decrease by much and so the pH only increases very slightly

22
Q

2 methods of preparing buffer solutions

A

1) . Make a solution with a mixture of the weak acid and a salt of the acid
2) . Take a solution of the weak acid and partially neutralise it by adding an alkali, but not enough alkali to neutralise all of it.

23
Q

How to work out the pH of a buffer solution

A

Write the Ka expression for the the acid

Eg. Ka = [H†][CH₃COO¯]/[CH₃COOH]

Rearrange for [H†]

Plug in values

pH = -log[H†]

24
Q

General rearrangement for [H†] for a buffer based on a weak acid

A

[H†] = Ka x [HA]/[A¯]

25
Q

When is a buffer solution most effective

A

When it’s pKa is close to the pH

26
Q

What range of pH is a buffer solution useful for

A

About 1 pH unit either side of pKa

27
Q

What is in a basic buffer

A

A weak base and it’s conjugate acid

28
Q

What is the buffer solution that is in blood

A

H₂CO₃ and HCO₃¯

29
Q

How is H2CO3 formed in the body

A

When CO₂ dissolves in water

H₂O + CO₂ → H₂CO₃