15. Bootcamp Qs Flashcards

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1
Q

All of the following statements are part of modern cell theory EXCEPT one. Which one is the EXCEPTION?

A. An organism’s activity is dependent on the activity of its independent cells.
B. Metabolism and biochemistry occur within cells.
C. Hereditary information is stored in cells and is shared between cells during cell division.
D. All cells contain a nucleus for the storage of genetic material.
E. All cells in organisms of similar species have similar chemical compositions.

A

D. All cells contain a nucleus for the storage of genetic material.
Prokaryotic cells do not have a centralized nucleus and do not have many of the other cell organelles that eukaryotic cells have with the exception of ribosomes

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2
Q

Turner Syndrome

A

Turner syndrome is an aneuploidy (specifically a monosomy) that is the result of a missing X chromosome due to nondisjunction in gamete formation during meiosis. Rather than having the expected sex genotype of XX, a female with Turner Syndrome would be XO, indicating the absence of an X chromosome.

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3
Q

A scientist wants to detach a peripheral membrane protein from the exterior of a cell membrane. Which is the best method to do so?

A. Change the salt concentrations.
B. Perform a light centrifuge.
C. Add a detergent.
D. Change the temperature of the solution.
E. Run a small current through the solution.

A

A. Change the salt concentrations.
Peripheral membrane proteins are held in place by electrostatic interactions and hydrogen bonding. They are generally hydrophilic. Changing the salt concentration (a “salt wash”) or the pH would disrupt both of these types of bonds and release the peripheral membrane protein from the cell membrane. Adding a detergent is a method used to extract integral proteins because they are more hydrophobic in nature. The hydrophobic detergent will destroy the membrane and expose the hydrophobic integral protein. Changing the temperature will denature the protein. Running a current through the cell isn’t a common or viable method. Running a small current through the solution – a technique known as electroporation – is used to create temporary holes in the plasma membrane. This does not detach peripheral membrane proteins from the external surface; therefore the answer choice is incorrect. Electroporation is often used on bacterial cells to introduce foreign DNA. 


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4
Q

Facilitated Diffusion

A
  • passive transport of particles down their conc. gradient.

- ex. quaporins, a channel protein that allows for water to flow more rapidly than simple diffusion

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5
Q

A toxin is released into the body that promotes the degeneration of microfilaments. Which of these structures is most likely to be directly affected?

  A. Spindle fibers radiating from centrioles
  B. Lysosomes
  C. The extracellular matrix
  D. Chromosomes
  E. Muscle cells
A

E. Muscle cells

Our muscles are made of long chains of cytoskeleton comprised of two filaments – actin and myosin. Of these, actin is a microfilament, while myosin is a motor protein. If actin degenerates, then our muscles would not contract, thus, our answer is E. The spindle fibers radiating from the centrioles are microtubules. A lysosome is an organelle that is involved in phagocytosis. The extracellular matrix consists of protein fibers and glycosaminoglycans. Chromosomes are made of nucleic acids. Microfilaments are primarily made of actin filaments and are primarily involved in motility. Substantial amounts can be found in skeletal muscle (where microfilaments are a key component of the sliding filament model of contraction), the pseudopod of amoeba (used for cell motility), and the cleavage furrow during animal cell division (actin and myosin microfilaments shorten and pull the plasma membrane towards the center of the cell); therefore the answer choice is correct.

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6
Q

Competitive Inhibition

A

A competitive inhibitor is one that binds directly to the active site and prevents the reactant from binding. Competitive inhibition results in a higher Km (the Michaelis constant that represents the substrate concentration at which the rate is half of Vmax – the higher the Km, the lower the binding affinity between enzyme and substrate) but since competitive inhibition can be overcome by increasing the substrate concentration, there is no change in Vmax (the maximum reaction rate).

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7
Q

What is the name of the structure that allows bacteria to stick to a surface?


  A. Flagella
  B. Clathrin
  C. Nucleoid region
  D. Teichoic acids
  E. Pili
A

E. Pili

Pili are small short “hairs” called fimbriae on the surface of bacteria that can be used in the exchange of genetic material between bacteria and in cell adhesion. Bacterial flagellum is a long “tail” made of flagellin that provides locomotion to a bacterial cell. In eukaryotes, flagellum is made of microtubules. Clathrin is a receptor protein on the surface of a cell. A nucleoid region is where the DNA exists in a bacterial cell as it does not have a nucleus. Teichoic acids are found only on gram-positive bacteria and help keep the cell wall rigid. Clathrin is a protein that coats vesicles and plays a critical role in their formation, as well as their incorporation into the cell membrane during exocytosis and endocytosis.

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8
Q

Flagella in Eukaryotes vs. Prokaryotes

A
  • eukaryotes: microtubules

- prokaryotes: flagellin

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9
Q

Which of the following best defines a notochord?

A. A component that eventually develops into the spinal cord.
B. A length of cartilage extending along the body, which will become part of the spinal discs.
C. That which will become the pharynx, gills, or other feeding system in the animal.
D. A muscular tail extending behind the anus.
E. A groove located in the underside of the pharynx that produces mucus in filter-feeding species.

A

B. A length of cartilage extending along the body, which will become part of the spinal discs.

The notochord is the feature that will eventually develop into a part of the spinal discs. The spinal cord begins as the dorsal neural tube. Pharyngeal slits are present in all chordates at some point during their development. For fish they will become gills, in other animals it will evolve into the pharynx, and in urochordates they are part of the filter-feeding system. The muscular tail that extends behind the anus is known at the post-anal tail. The endostyle is what produces mucus for filter feeders.

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10
Q

Four main features shared by chordates during development

A
  1. Notochord
  2. Dorsal hollow nerve cord
  3. Pharyngeal gill slits
  4. Muscular post-anal tail
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11
Q

All of the following phyla have a complete digestive system EXCEPT for one. Which of the following is the EXCEPTION?

  A. Nematoda
  B. Annelida
  C. Mollusca
  D. Echinodermata
  E. Platyhelminthes
A

E. Platyhelminthes

Platyhelminthes do not have a complete digestive system, so the answer choice is correct (it is important to know that Cnidaria also lack a complete digestive system – both Cnidaria and Platyhelminthes instead have a gastrovascular cavity in which two way digestion takes place, rather than the one way digestion through an alimentary canal seen in other classes with digestive systems). Platyhelminthes are triploblasts with bilateral symmetry, and are acoelomate. Examples include flatworms, tapeworms, and flukes.

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12
Q

There are many shared traits between fungi and the other four kingdoms. Of the five statements below, which one is unique to fungi?

A. Some fungi are bioluminescent.
B. Fungi have a cell wall, vacuoles, use sexual and asexual means of reproduction and produce spores.
C. Fungi undergo an alternation of generations.
D. Fungi cell walls are made of glucans and chitin.
E. Fungi are heterotrophic, lack chloroplasts and are reliant on organic compounds for energy sources.

A

D. Fungi cell walls are made of glucans and chitin.

Plants have cell walls, vacuoles, and use different means of reproduction to produce spores. Animals are heterotrophic, lack chloroplasts, and are reliant on organic compounds for energy sources. Plant cell walls are known to contain glucans, and some animal exoskeletons contain chitin. However, fungi are the only organism known to use both, making this feature unique to fungi only.

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13
Q

What type of immunity is defined by the transfer of antibodies from one person to another, most commonly illustrated when a woman breastfeeds her newborn infant?

  A. Active immunity
  B. Passive immunity
  C. Natural immunity
  D. Artificial immunity
  E. Permanent immunity
A

B. Passive Immunity

Passive immunity, although not a permanent form of immunity, occurs when one organism can pass along their antibodies to another organism to prevent infection. With newborn infants, they lack the immunity needed to combat most illnesses, however a nursing woman can pass along her antibodies through the colostrum, the precursor to breast milk. Active immunity is brought about when an organism is infected or exposed to a virus/bacterium that then causes an internal initiation of the immune system. With this type of immunity, the organism makes its own memory cells to be ready for a later infection.

Natural immunity refers to when an immune response is generated by natural means (as opposed to an artificial method, such as the use of a vaccine).

Artificial immunity refers to when an immune response is generated by artificial means, such as in vaccination where antigenic material is intentionally introduced to cause an immune response.

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14
Q

Oligodendrocytes are best associated with:

  A. Beta cells of the pancreas
  B. G cells of the stomach
  C. Nerves in the peripheral nervous system
  D. White matter of the brain
  E. Spermatogonia of the testes
A

D. White matter of the brain

Oligodendrocytes are responsible for laying down the myelin sheath surrounding neurons in the central nervous system, so choices [A], [B] and [E] can be eliminated. Remember, the central nervous system includes the brain and the spinal cord. Schwann cells perform the same function in the peripheral nervous system (PNS).

Myelination insulates the neurons (like the plastic around an electrical wire) and allows the neurons to transmit electrical impulses more quickly and efficiently. Without myelination, your neurons will not be able to properly communicate together, resulting in a variety of diseases, such as multiple sclerosis.

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15
Q

The main extracellular buffer system in humans consists of:

  A. amphipathic proteins
  B. phosphate
  C. sulfate
  D. bicarbonate
  E. histamines
A

D. Bicarbonate

The main extracellular buffer is bicarbonate. This is how CO2 is transported throughout the body. The body uses pH sensors to determine how much we have to breathe. If we are exercising vigorously then our cells will produce large amounts of CO2, which will lower our extracellular pH (make it more acidic due to the CO2), which will make us breathe more to expel the excess CO2.

Phosphate and other proteins are used as the main intracellular buffer inside cells.

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16
Q

All of the following hormones are derived from cholesterol EXCEPT one. Which one is the EXCEPTION?

  A. Aldosterone
  B. Cortisol
  C. Epinephrine
  D. Testosterone
  E. Progesterone
A

C. Epinephrine

Cholesterol is characterized by 4 rings and is the precursor to many steroid hormones. Aldosterone, testosterone, and progesterone all sound very similar, and these are all steroids that are derived from cholesterol. Cortisol is another steroid that is released by the adrenal cortex and involved in stress adaptation.

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17
Q

Which of the following is a method marine fish use to maintain homeostasis?

  A. Swim towards freshwater.
  B. Rarely drink water.
  C. Absorb salts through gills.
  D. Constantly urinate.
  E. Constantly drink water.
A

E. Constantly drink water.

A marine fish is hypoosmostic to its environment, meaning that it is less salty than the concentrated saltwater surrounding it. Therefore, it will constantly lose water to the environment. To make up for this, the marine fish must constantly drink water. It also rarely urinates to not waste any water, and it secretes the salts it acquires from constantly drinking.

In contrast, freshwater fish are hyperosmotic, or saltier than their environment. Therefore, water will constantly flow into the fish. The fish must constantly urinate to get rid of the excess water. It also rarely drinks, and absorbs salt through its gills to maintain homeostasis.

SUMMARY
Fish in freshwater environments:

Are hyperosmotic relative to their environment
Drink very little water
Salt enters the gills via active transport
Produce large volume of urine
In contrast, fish in saltwater environments (i.e. marine fish):

Are hypoosmotic relative to their environment
Constantly drink
Salt leaves the gills via active transport
Produce low volume of urine

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18
Q

In mammals, which of the following structures aides the embryo in gas exchange and the disposal of liquid waste?

  A. Yolk
  B. Amnion
  C. Allantois
  D. Chorionic Villi
  E. Yolk Sac
A

C. Allantois

In mammals, the chorionic villi eventually form the placenta, but the villi are finger-like sections that burrow into the wall of the uterus near the mother’s blood vessels. The allantois disposes of wastes, and forms part of the umbilical cord to carry waste away from the embryo and towards the mother’s blood vessels. The amnion is a thin sac that surrounds the embryo and produces amniotic fluid to provide cushion for the growing embryo. Mammals do not have yolk, and the yolk sac contains only fluid to cushion the growing embryo and has blood vessels in it that give rise to the vascular system of the embryo. In birds, the yolk sac serves to nourish the embryo throughout its development.

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19
Q

Nondisjunction occurring during meiosis II, followed by fertilization, would result in a zygote with which of the following chromosomal descriptions?

A. Aneuploid
B. Haploid
C. Diploid
D. Tetraploid

A

A. Aneuploid

In meiosis II, the individual chromosomes line up on the metaphase plate and are separated by spindle fibers. Each resulting cell should have one of each chromosome. When non-disjunction occurs during meiosis II the chromosome is not separated and instead one of the resulting cells produced will have two copies of the same chromosome and one cell will be missing a chromosome. This is referred to as aneuploidy, or the occurrence of having an abnormal amount of chromosomes, either more or less than 23. A normally dividing cell will begin meiosis as a diploid cell, with two copies of each chromosome, equaling 46 chromosomes (23 pairs) total. After meiosis I, the cells produced are haploid, containing one copy of each chromosome, totaling 23 chromosomes total.

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20
Q

Which of the following are best characterized by brackish water?

  A. A river emptying into an inland lake.
  B. A mangrove leading to an estuary.
  C. A stream in a tropical forest.
  D. A freshwater marsh and lake.
  E. Seawater washing onto a beach.
A

B. A mangrove leading to an estuary.

Brackish water means a mix between salt and fresh water, which would be found in an estuary. An estuary is a specific area where freshwater meets seawater. A mangrove swamp often grows near an estuary and is characterized by a mix of salt and freshwater. Some marshes can be brackish, but D specifically stated that this marsh was freshwater, and thus not characterized by brackish water.

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21
Q

A species of desert plant secretes a chemical into the surrounding soil that kills seeds from any other species of plant that attempts to germinate in that area. What is this an example of?

  A. Commensalism
  B. Allelopathy
  C. Exploitation competition
  D. Apparent competition
  E. Intraspecific competition
A

B. Allelopathy

Allelopathy is type of interference competition, where the establishment of other individuals who would compete for a mutual resource is prevented, in this case using a toxic chemical. Intraspecific competition (E) occurs when competition occurs within the same species; in this case the plant is competing with all the other species of plants in the area.

In commensalism, a form of symbiosis, one of the two organisms benefits while the other remains unaffected.

Exploitation competition is a type of competition that occurs indirectly through depletion of a common resource. For example, lions and cheetahs face exploitation competition in Africa as both hunt for a common resource: the gazelle. If cheetahs were more successful and ate all the gazelles, lions would suffer from depletion of the food resource.

Apparent competition is a type of competition that occurs between two species preyed upon by the same predator. For example, say a species of spider and a species of beetle are both hunted by owls and the amount of spiders suddenly increased. This would lead to survival of more owls (due to the increased food resource of spiders), which would in turn hunt more of the beetles, ultimately decreasing their overall number.

Intraspecific competition is a type of competition that occurs between members of the same species.

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22
Q

Which biome is characterized as the largest biome on Earth with long harsh, snowy winters, short rainy and humid summers and with a landscape dominated by conifers?

  A. Deciduous forest
  B. Savanna
  C. Tundra
  D. Taiga
  E. Chaparra
A

D. Taiga

Deciduous forests do have winters, but they are not characterized as harsh or very snowy and this biome is known for having 4 distinct seasons each year. The savanna biome has small grasses, small shrubs, scattered trees, and have both dry and rainy seasons. The tundra biomes are best defined as regions that have short growing season, cold temperatures all year round and have a layer of permafrost over the soil. The taiga biome has long, cold winters and very short rainy seasons. Taiga does have vegetation with most of the tree covering being provided by conifers like spruce, fir and pine trees. Tropical deserts are characterized as having extremely high temperatures with sporadic rainfall.

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23
Q

What is the original source of energy used to drive the light independent reactions of photosynthesis?

  A. Substrate level phosphorylation
  B. The breakdown of glucose
  C. Photolysis of water to release electrons
  D. ATP produced by mitochondria
  E. Photons absorbed by chlorophyll
A

E. Photons absorbed by chlorophyll

When light (photons) is present, the light-absorbing pigments absorb energy. This energy excites electrons, which become unstable and re-emit the absorbed energy, which is then absorbed and re-emitted by electrons of nearby pigment molecules until this energy is absorbed by chlorophyll molecules. This process allows for noncyclic photophosphorylation to occur, which in turn provides the ATP molecules used for energy in the light independent reactions of photosynthesis

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24
Q

If 2n=8, how many chromosomes are present during anaphase?

  A. 2
  B. 4
  C. 8
  D. 16
  E. 32
A

D. 16

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25
Q

An animal cell was lysed, placed in a test tube, and centrifuged. Which organelle would pellet from the centrifuge first?

  A. Ribosome
  B. Lysosome
  C. Mitochondria
  D. Golgi complex
  E. Nucleus
A

E. Nucleus

  • The nucleus is the largest and most dense organelle in the cell and will pellet first.
  • ribosomes would be expected to pellet out last due to their small density and size
  • Lysosome would be expected to pellet out after the nucleus, but before the smaller and less dense ribosomes.
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26
Q

A scientist wishes to create bacterial colonies on an agar plate for observation of growth. Unfortunately, directly adding bacteria from the original culture results in too many bacterial colonies to count. In order to create a solution of proper bacterial concentration for observation, the scientist performs a three-step 1:100 serial dilution of the original bacterial culture. What is the dilution factor of the final solution?

  A. 10^-9
  B. 10^-3
  C. 3.0
  D. 10^3
  E. 10^6
A

E. 10^6

  • In this problem, the scientist performed a three-step 1:100 dilution, meaning they diluted the original concentration first to 10^-2, then to 10^-4, and finally to 10^-6. The question asks for the dilution factor, which is the final volume divided by the original volume (or the inverse of the concentration)
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27
Q

What is the purpose of SDS (sodium dodecyl sulfate) in protein analysis?

A. Denature non-covalent bonds in a protein
B. Decrease the surface area of the protein
C. Impart a positive charge on the protein
D. To cut the protein at specific sequences
E. Dye the proteins to track their run

A

A. Denature non-covalent bonds in a protein

  • Sodium dodecyl sulfate is a very strong anionic detergent that is used in gel electrophoresis to separate proteins based on their electrophoretic mobility (a function of the length of a protein and its charge). SDS is used to denature and linearize proteins and to impart a negative charge to the proteins. You could deduce it would impart a negative charge and not a positive one because sulfate is very negative and anionic. With this method, only the protein’s size and charge will be compared. Generally, all gel electrophoresis will denature a protein to compare its size
  • SDS (sodium dodecyl sulfate) has three primary effects on protein:

Denatures the protein
Linearizes the protein
Adds negative charge to the protein
The SDS-PAGE (polyacrylamide gel electrophoresis) is used to separate proteins on the basis of size (molecular weight). Smaller proteins will travel further than large proteins from the negative cathode to the positive anode.

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28
Q

All of the following directly use an electrochemical gradient EXCEPT one. Which one is the EXCEPTION?

  A. Flagella rotation
  B. Mitochondria
  C. Chloroplasts
  D. Aquaporins
  E. Neurons
A

D. Aquaporins

  • Aquaporins are protein structures in the membrane that help water passively flow into or out of the cell, a process known as facilitated diffusion.
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29
Q

In the alternation of generations, what do spores directly give rise to?

  A. Gametes
  B. Zygotes
  C. Gametophyte
  D. Sporophyte
  E. Seeds
A

C. Gametophyte

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30
Q

Which of the following lack a true coelom?

  A. Flatworms
  B. Annelids
  C. Echinoderms
  D. Chordates
  E. Mollusks
A

A. Flatworms

  • A coelom is a cavity lined by an epithelium derived from mesoderm. Mollusks have a reduced, but still true, coelom. A flatworm(also known as planarian) is an acoelomate because it does not have a coelom within its mesoderm layer.
  • Acoelomate: flatworms
  • Pseudocoelomate: roundworms
  • True coelomate: molluscs, annelids, arthropods, echinoderms, chordates
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31
Q

Bacteria Appearance

A
Diplo-: pairs
Strep-: chain
Staph-: grape-like clusters
-coccus: spherical
-bacillus: rod-like
Spirilla/spirochetes: spirals
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32
Q

Digestive Enzyme Summary

A

Mouth: salivary amylase (carbohydrates)

Stomach: Pepsin (proteins)

Pancreas: pancreatic amylase (carbohydrates), pancreatic trypsin and chymotrypsin (proteins), carboxypeptidase (proteins), nucleases (DNA, RNA), lipase (fats) [Note: these digestive enzymes are secreted by the pancreas but carry out their function in the small intestine]

Small Intestine: Disaccharidases (carbohydrates), dipeptidases and aminopeptidases (proteins), nucleotidases (nucleotides), nucleosidases (nucleosides)

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33
Q

Anterior Pituitary Hormones

A
  • FSH Follicle stimulating hormone Regulate development, growth, and reproduction. FSH helps develop a primary follicle. It acts synergistically with LH.
  • LH Luteinizing Hormone Regulate development, growth, and reproduction. Acute increase in LH triggers ovulation and develops corpus luteum. In males it stimulates Leydig cells to produce testosterone. It acts synergistically with FSH.
  • ACTH Adrenocorticotropic Hormone Stimulates adrenal cortex
  • TSH Thyroid-stimulating hormone Stimulates the thyroid
  • HGH Human growth hormone Regulates protein synthesis and cell division
  • Prolactin Prolactin Production of milk in mammary glands
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34
Q

An increase in calcitonin would lead to which of the following?

A. Increase calcium concentration in blood
B. Decrease calcium reabsorption in bones
C. Stimulate osteoblast activity
D. Stimulate osteoclast activity
E. An increase in muscle contractions

A

C. Stimulate osteoblast activity

  • Two hormones regulate calcium levels in blood: calcitonin (produced by the thyroid), and parathyroid hormone (produced by the parathyroid). Calcitonin serves to lower calcium levels in blood. It does this by stimulating osteoblast activity, which builds up bone, which requires using calcium in the blood. Parathyroid hormone is the opposite, if calcium levels are too low in the blood, it will stimulate osteoclast activity to release calcium from the bones to the blood.
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35
Q

Which of the following components of the immune system responds to specific antigens?

  A. B cells
  B. Interferons
  C. Phagocytes
  D. Cilia
  E. Lysozyme
A

A. B cells
- There are two parts to the immune system: specific and nonspecific defense. Specific defense responds to antigens, such as the toxin from an insect sting, or a molecule on the plasma membrane of a pathogen. Nonspecific defense is not specialized for a particular pathogen; it defends against all pathogens in general. Examples of nonspecific defenses include: skin, interferons, phagocytes, cilia, and lysozyme. Interferons are molecules secreted by cells invaded by viruses that stimulate other cells to help defend against viruses. Phagocytes are white blood cells that engulf pathogens. Cilia line the lungs and help sweep pathogens out of the lungs. Lysozyme is a protein that breaks down cell walls in bacteria.

  • The distinguishing characteristic of B cells is that they all possess a B cell receptor (BCR), which binds to specific antigens, making this answer correct. Formed in the bone marrow, B cells are important because they can differentiate into memory B cells, which can produce antibodies for pathogens that have already been encountered.
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36
Q

After ejaculation, what process must sperm undergo before they are competent to fertilize an oocyte?

  A. Acrosome reaction
  B. Oogenesis
  C. Metamorphosis
  D. Sperm meiosis
  E. Capacitation
A

E. Capacitation

  • Capacitation refers to the increased flagella motility and destabilization of the acrosomal membrane seen in ejaculated sperm. Capacitation is a necessary step for a sperm to be able to penetrate an oocyte’s zona pellucida and fertilize the egg, so this answer is correct.
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37
Q

Three Germ Layers

A
  • Ectoderm: Epidermis of skin, hair, nails, nervous system, lens of eye, enamel of teeth
  • Mesoderm: Dermis of skin, muscle, skeleton, circulatory system, gonads, kidneys, respiratory tracts, notochord
  • Endoderm: Lining of digestive and layer of respiratory tracts, liver, pancreas
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38
Q

Sickle-cell disease is caused by a defective hemoglobin gene, resulting in several phenotypic outcomes. Which of the following describes sickle-cell disease?

  A. Dominant
  B. Polygenic inheritance
  C. Pleiotropy
  D. Epistasis
  E. Linked genes
A

C. Pleiotropy

  • Pleiotropy occurs when a single gene has multiple phenotypic outcomes. In sickle-cell disease, a single mutation produces abnormal hemoglobin molecules. This results in damage to many organs and also results in several disorders. In contrast, polygenic inheritance is when many genes contribute to one phenotypic outcome. A great example is the height of humans, which is controlled by many genes and results in one phenotype. Epistasis occurs when one gene affects the expression of the second gene.
  • Epistasis describes when one gene affects the phenotypic expression of a second gene
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39
Q

Which part of the brain monitors the body’s temperature?

    A. Hypothalamus
    B. Pons
    C. Medulla
    D. Cerebral cortex
    E. Cerebellum
A

A. Hypothalamus

The hypothalamus controls the body’s temperature, hunger, thirst, sleep, and circadian cycles. One of its most important functions is that it links the nervous system to the endocrine system through the pituitary gland. The pons relays signals from the forebrain to the cerebellum. The medulla controls autonomic functions, such as respiration, digestion, and the pumping of the heart. The cerebral cortex is a complex portion of the brain that is involved in higher-level thinking and sensory perception. Lastly, the cerebellum is involved in motor control, such as balance and coordination.

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40
Q

The diastole phase of circulation is associated with the:

    A. contraction of the ventricles.
    B. closing of the AV valves.
    C. opening of the semilunar valves.
    D. closing of semilunar valves.
    E. relaxation of the atriums.
A

D. closing of semilunar valves.

When the heart contracts, the ventricles force blood through the semilunar valves and into our arteries. Also during this time, the AV valves are shut to prevent the blood from being forced back into the atriums. When the ventricles relax, the semilunar valves are shut to prevent backflow from the blood they just forced into the arteries, and the AV valves are reopened; this is called the diastole phase. The opening and closing of the AV valves and semilunar valves causes the “lub-dup” sounds in the heart.

The ventricles contract during the systole phase of circulation, not the diastole phase; therefore the answer choice is incorrect. When the ventricles contract, the AV valves snap shut to prevent backflow of blood – this is responsible for the “lub” part of the “lub dub” sound in heart beats.

When the ventricles contract, the AV valves snap shut to prevent backflow. The contraction of the ventricles is associated with the systole phase of circulation, not the diastole phase

The aortic and pulmonary semilunar valves snap shut when the ventricles relax, to prevent backflow from the pulmonary artery and aorta. The relaxation of the ventricles is associated with the diastole phase of circulation, so the answer choice is correct. The closing of the semilunar valves is responsible for the “dub” part of the “lub dub” sound in heart beats.

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41
Q

All of the following can be found in the filtrate from the Bowman’s capsule EXCEPT for one. Which one is the exception?

    A. Glucose
    B. Salts
    C. Vitamins
    D. Nitrogen wastes
    E. Proteins
A

E. Proteins

In the kidney system, blood enters from an afferent arteriole into the glomerulus, where pressure forces water and solutes through the capillary walls into the Bowman’s capsule, like a sieve. Small particles can be pushed through the capillary walls, but red blood cells and proteins cannot pass through and remain in the blood. The filtrate in the Bowman’s capsule will then travel through the nephron, where the majority of salts, water, and glucose will be reabsorbed.

Proteins are not able to filter through the fenestrations in the glomerulus into the Bowman’s capsule, so the answer choice is correct. The Bowman’s capsule and the glomerulus are both components of the renal corpuscle, which together with the renal tubule forms a nephron. Hydrostatic pressures force blood plasma through the fenestrations of the glomerulus – these fenestrations screen out blood cells and large proteins to prevent them from entering the Bowman’s capsule. Additionally, podocytes (cells in the Bowman’s capsule) further filter blood to prevent large molecules like protein from passing through, but allow smaller ones (including sugar, water, salts, vitamin, and nitrogen wastes).

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42
Q

Which of the following pairs of structures target the same organ with different hormones?

    A. Pancreas and thyroid
    B. Testes and posterior pituitary
    C. Posterior pituitary and adrenal cortex
    D. Adrenal medulla and parathyroid
    E. Adrenal cortex and thyroid
A

C. Posterior pituitary and adrenal cortex

The posterior pituitary releases ADH, which allows the kidneys to reabsorb more water. The adrenal cortex releases mineralocorticoids, such as aldosterone, which affects the kidney to increase salt reabsorption (which in turn increases water absorption as well due to changes in osmolarity).

The pancreas releases glucagon (increase blood glucose) from alpha cells and insulin (decrease blood glucose) from beta cells. The thyroid controls general metabolism and releases calcitonin, which lowers blood calcium. The parathyroid releases PTH (parathyroid hormone), which increases blood calcium. The anterior pituitary releases FSH, LH, ACTH, TSH, prolactin, and growth hormone. The testes produce testosterone.

The testes produce testosterone (that affect the testes themselves and have general effects on secondary sexual characteristics). The posterior pituitary stores antidiuretic hormone (ADH) and oxytocin produced by the hypothalamus; ADH targets the kidney, while oxytocin targets the mammary glands and uterus. These structures do not produce hormones that target the same organ

The posterior pituitary stores antidiuretic hormone (ADH) and oxytocin produced by the hypothalamus; ADH targets the kidney, while oxytocin targets the mammary glands and uterus. The adrenal cortex produces glucocorticoids (such as cortisol) that affect the body on a general level to increase blood glucose, and mineralocorticoids (such as aldosterone) that target the kidney. Since the posterior pituitary produces ADH that targets the kidney, and the adrenal cortex produces a different hormone (aldosterone) that targets the kidney, the answer choice is correct. ADH increases reabsorption of water, while aldosterone increases reabsorption of Na+ and excretion of K+.

The adrenal cortex produces glucocorticoids (such as cortisol) that affect the body on a general level to increase blood glucose, and mineralocorticoids (such as aldosterone) that target the kidney. The thyroid produces thyroxine (T4) and triiodothyronine (T3) which target the general metabolic rate of the body, and calcitonin which targets the bones.

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43
Q

The ingestion of which of the following would stimulate the release of cholecystokinin?

    A. Carbohydrates
    B. Fats
    C. Nucleic acids
    D. Cellulose
    E. Inorganic compounds
A

B. Fats

Cholecystokinin is a hormone produced by the small intestine in response to fats. It stimulates the gallbladder to release bile, which helps in the emulsification of fats, and stimulates the pancreas to release lipases. Gastrin is produced once the nervous system sees or smells food, which stimulates the stomach to produce gastric juices. Secretin is produced in the small intestine and stimulates the pancreas to produce bicarbonate to neutralize the acidity of the chyme.

Cellulose does not stimulate the release of cholecystokinin; therefore the answer choice is incorrect. Cellulose cannot be broken down by the human digestive system, as we lack the necessary enzymes to break the beta-glucose linkages found in its polysaccharide structure. In ruminant digestive systems, cellulose is broken down by bacteria present.

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44
Q

The shaft of the long bone is called the:

    A. metaphysis.
    B. periosteum.
    C. epiphysis.
    D. diaphysis.
    E. medullary cavity.
A

D. diaphysis.

The diaphysis is the name of the shaft of a long bone, which is made of compact bone. The epiphysis is the rounded end of a long bone. The metaphysis is the wider portion of a long bone situated near the epiphysis, this is where the majority of growth happens during puberty. The periosteum is a membrane that covers the surface of all bones, except at the joints of long bones. It provides nourishment and sensation to the bones. The medullary cavity is the central cavity of bone shafts. It usually contains red bone marrow, which produces blood cells, and yellow bone marrow, which consists of adipose tissue.

The metaphysis is the area of long bone between the ends (epiphysis) and shaft (diaphysis); therefore the answer choice is incorrect. It contains the epiphyseal plate (or growth plate) where lengthening of the long bone occurs until adulthood, when the hyaline cartilage is replaced by bone and no further ossification occurs.

The diaphysis refers to the shaft of the long bone, so the answer choice is correct. Yellow bone marrow can be found inside the diaphysis (which contains adipose cells for fat storage), as well as red bone marrow (where hematopoiesis aka red blood cell production occurs).

Yellow bone marrow can be found in the medullary cavity (which contains adipose cells for fat storage), as well as red bone marrow (where red blood cell production occurs).

45
Q

Which germ layer produces the notochord?

    A. Ectoderm
    B. Mesoderm
    C. Endoderm
    D. Epiderm
    E. Hypoderm
A

B. Mesoderm

The notochord consists of cells on the surface of the mesoderm germ layer, which provides support in lower chordates. It is considered the first “backbone” in chordates.

Ectoderm: Epidermis of skin, hair, nails, neural tube, lens of eye, enamel of teeth

Mesoderm: Dermis of skin, muscle, skeleton, circulatory system, gonads, kidneys, respiratory tracts, notochord

Endoderm: Lining of digestive and layer of respiratory tracts, liver, pancreas

46
Q

Which of the following is a fundamental step in the cloning of an animal?

A. Revert a somatic cell into a totipotent state.
B. Extracting mRNA of all transcribed genes.
C. Differentiate pluripotent cells into totipotent cells.
D. Revert totipotent cells into embryonic germ layers.
E. Revert a pluripotent cell to a somatic cell.
A

A. Revert a somatic cell into a totipotent state.

Cloning is the process of taking a somatic cell from an animal and producing a genetic copy from that cell. It is different from fertilization in that there is no genetic variation; each clone is a genetic replica of the parent animal. This was best characterized by Dolly, the cloned sheep.

Somatic cells contain the full genome of an organism, but are usually specialized based on the tissue they are a part of. In contrast, totipotent cells can give rise to any and all human cells, and even an entire functional organism. To clone an animal with this method, a somatic cell would need to be reverted to its less specialized totipotent state such that it could give rise to a new, genetically identical animal.
Somatic cells contain the full genome of an organism, but are usually specialized based on the tissue they are a part of. In contrast, totipotent cells can give rise to any and all human cells, and even an entire functional organism. To clone an animal with this method, a somatic cell would need to be reverted to its less specialized totipotent state such that it could give rise to a new, genetically identical animal.

Totipotent:

  • This describes a single cell with the ability to divide and produce an entire organism. Can also produce extraembryonic membranes.
  • A zygote, up to a morula, consists of totipotent cells. Any one of these cells can produce an entire organism.

Pluripotent:

- A stem cell that can differentiate into any of the three germ layers: endoderm, mesoderm, or ectoderm.

  • They can give rise to any cell type, but they cannot develop an entire organism because they cannot develop extraembryonic tissue, like the placenta.
47
Q

Which of the following techniques would best allow a scientist to determine which genes are and are not expressed in a cell?

    A. ELISA
    B. Gel Electrophoresis
    C. Karyotyping
    D. PCR
    E. DNA microarray
A

E. DNA microarray

ELISA is a technology to determine if a specific antigen exists. Antibodies are placed into a microtiter plate, and if they bind to their specific antigen there will be a color change in the microtiter plate, indicating that a specific antigen exists.

Gel electrophoresis is a technique to separate macromolecules (DNA, RNA, proteins) by size and charge. Shorter macromolecules will move faster than longer macromolecules and travel further.

Karyotyping is a useful tool to count the number of chromosomes in a cell. This is useful in the diagnosis of trisomy diseases, or an abnormal number of chromosomes.

48
Q

All of the following are ways genetic variation can be introduced to bacteria EXCEPT for one. Which one is the EXCEPTION?

    A. Heat shock with CaCl2	
    B. Electroporation
    C. Binary fission
    D. Transduction
    E. Conjugation
A

C. Binary fission

Binary fission is a form of asexual reproduction in prokaryotes and some organelles within eukaryotes (mitochondria and chloroplasts). The DNA is duplicated and then the two copies migrate to opposite sides of the cell, and the cell then splits into two. The consequence of this is that all the bacteria and progeny are genetically identical.

There are numerous ways we can force bacteria to uptake new DNA. Plasmids are short, circular DNA molecules outside of the main chromosome. Placing the bacteria in a solution of CaCl2 and heat will force the bacteria to uptake plasmids and incorporate them into their genome, this process is a form of transformation.

A brief pulse of high voltage electricity in a solution of bacteria will force them to open their pores and allow for plasmids to enter the bacteria as well. This process is known as electroporation. Notice the root words “electro-” and “-poration”. You can guess it has something to do with electricity and pores in the membrane.

Transduction is the process of introducing new DNA through a bacteriophage, or virus. A virus carrying bacterial DNA injects that DNA into a host bacterium, and the DNA is then incorporated into the host genome.

Conjugation is the transfer of genetic material between two bacterial cells by cell-to-cell contact. The donor bacterium forms a pilus to connect to the recipient bacterium. The donor then sends DNA to the recipient, who can incorporate it into their genome

49
Q

Which enzyme in replication unzips the DNA to produce a replication fork?

    A. Topoisomerase
    B. Helicase
    C. Primase
    D. Ligase
    E. Telomerase
A

B. Helicase
At the beginning of replication, helicase unzips the DNA to produce a replication fork. The replication fork is held in place by single-strand binding proteins. As helicase unwinds the DNA upstream, further downstream the DNA actually becomes positively supercoiled. Topoisomerase removes these twists and knots induced by helicase. Telomerase is an enzyme that extends the template strand to add a short sequence of nucleotides to the replicated strand. This is because eukaryotes have linear DNA molecules and cannot replicate the ends of the original DNA, because no primer can be placed.

50
Q

What are the two abiotic factors that determine the distribution of terrestrial biomes?

    A. soil and sunlight
    B. sunlight and temperature
    C. rainfall and sunlight
    D. rainfall and temperature
    E. soil and temperature
A

D. rainfall and temperature

Biomes are classified based on the biological effects of temperature and rainfall on vegetation. The majority of biomes are dependent on these two factors. For example, deserts have a lack of rainfall and very high temperatures, giving them their characteristics. In contrast, rainforests have lots of rainfall and warm temperatures, providing an environment for a biologically diverse biome. Many descriptions you see on biomes will have a chart displaying their average temperature and rainfall throughout the year.

51
Q

Which of the following describes the law of parsimony?

A. The phylogenetic tree that has the least amount of assumptions is the most preferred.
B. The driving force for evolution is divergent evolution.
C. Homoplasy can help us develop phylogenetic trees.
D. The individual with more fitness will ultimately outcompete others.
E. Life evolved from the oceans, to land, and then air.
A

A. The phylogenetic tree that has the least amount of assumptions is the most preferred.

The law of parsimony, or Occam’s Razor, says that when choosing between competing hypotheses, the one that makes the least amount of assumptions is the most preferred. Another way to say it is that the simplest explanation is probably the most accurate. When developing phylogenetic trees, the tree that explains the evolution of organisms with the least amount of assumptions is most likely the correct one.

Homoplasy, also known as convergent evolution, is a phenomenon that describes when two distinct clades develop strikingly similar characteristics despite the fact that there is no common ancestor with the trait. A well-known example of this is the convergent evolution of wings in both birds and bats. Rather than making it easy to develop phylogenetic trees, this tends to confound attempts to make them. For instance, imagine a phylogenetic tree where flight was viewed as the most important characteristic. This would lead you to determine that birds and bats are the most closely related of all vertebrates, which is simply not true.

52
Q
  1. Which of the following directly contributes to cellular recognition?
    A. Clathrin-coated membrane
    B. Membrane glycoproteins
    C. Membrane cholesterol
    D. Degree of unsaturation in membrane fatty acids
    E. Resting membrane potential
A

B. Membrane glycoproteins

Clathrin is a protein that forms intracellular coats during receptor mediated endocytosis. This has nothing to do with cellular recognition.

Clathrin is a protein which aids in receptor mediated endocytosis. Endocytosis is when the cell membrane forms a vesicle (a package that is surrounded by plasma membrane) around something extracellular that the cell wants to internalize. When a membrane receptor binds certain substrates that the cell wants to internalize, the receptor signals for clathrin lattice formation. Clathrin forms a lattice around the incoming vesicle in pits, and this is known as a clathrin coated pit. Clathrin coating occurs intracellularly and has nothing to do directly with cell recognition.

While all cells have a resting membrane potential, only nerve and muscle cells are considered excitable cells – excitable cells are cells that can fire an action potential.

53
Q

Why do steroid hormones like testosterone and estrogen bind to protein carriers when travelling through the blood?

A. Steroid hormones are soluble in the blood, and will dissolve if not bound a protein carrier
B. Steroid hormones would activate non-target cells if not bound to a protein carrier
C. Steroid hormones are nonpolar and require a protein carrier to shield them from polar blood
D. The protein carriers will act as transmembrane protein channels for the steroid hormone, at the target cell
E. Protein carriers protect the steroid from being electronically reduced by dissolved oxygen
A

C. Steroid hormones are nonpolar and require a protein carrier to shield them from polar blood

Steroid hormones do not require transmembrane channels, they diffuse directly through the cellular membrane.

Hormones are only able to activate cells that produce a receptor for that hormone. This is how hormones are able to activate only certain cell types, even though they come into contact with a huge variety of cells during circulation. Hormones will not activate nontarget cells because nontarget cells will not produce a receptor to that hormone.

The amount of dissolved oxygen in the blood plasma is very small as most oxygen is transported inside red blood cells bound to hemoglobin. Additionally, even if there was sufficient oxygen dissolved in the cell, oxygen would oxidize agents, not reduce them.

54
Q

Which of the following will have a significant effect in stimulating development of cancer?

A. A base-pair mismatch during DNA replication which has been repaired
B. A cell that has one mutated allele of a tumor suppressor gene
C. p53 failing to activate
D. A cell that has two copies of proto-oncogenes
E. A decrease in reactive oxygen species
A

C. p53 failing to activate

Tumor suppressor genes require two mutated alleles in order to have loss of function (cancer-causing)

p53 is the tumor suppressor guardian of the cell; its failure to activate will encourage cancer.

Proto-oncogenes are the normal, noncancerous state of genes which regulate growth and division.

Reactive oxygen species (ROS) like hydrogen peroxide (H2O2) damage DNA and increase the rate of DNA mutations. A decrease in ROS would lower risk of developing cancer.

Tumor suppressor genes make protein products that protect the cell from cancer (tumor suppressor gene products will suppress tumors). A loss of that protective function causes cancer.

Tumor suppressor genes cause cancer through a loss of function mutation. Tumor suppressor gene mutations are recessive: a cell would have to lose function in both of its tumor suppressor genes in order to lose function.

This is because tumor suppressor genes are haplosufficient. One tumor suppressor gene has sufficient function to produce enough protein to have a tumor suppressor effect.

Tumor suppressor genes follow a ‘two hit hypothesis’, meaning that mutations are required in both of their genes in order to be cancer-causing.

55
Q

Tumor suppressor genes:

A
  • p53
  • p21: p21 is a cyclin dependent kinase (CDK) inhibitor. If p21 inhibits CDK, then p21 prevents cell division. Increasing the activity of p21 will increase the amount of inhibition of CDK, and p21 will decrease the amount of cell division.

Another tumor suppressor which has come up before on the DAT is retinoblastoma protein abbreviated rb. Being a tumor suppressor, it follows the two-hit hypothesis of inactivation (both copies mutated in order to cause cancer)

56
Q

Proto-oncogenes

A

Proto-oncogenes are the genes that regulate growth function within the cell.

A proto-oncogene is the noncancerous version of the gene that has a regular and an important role within the cell. Proto-oncogenes affect different processes such as cell growth and differentiation – but if these processes go awry, this will lead to cancer.

Proto-oncogene → mutation → oncogene

Oncogenes are the altered allele version of the proto-oncogene, where the ‘regulation of growth function’ has been dysregulated. The oncogene can cause cancer through a gain of function mutation (gain of growth). It only takes one copy of a gain of function mutation in an oncogene to cause cancer.

Contrast this with tumor suppressor genes which cause cancer through a loss of function mutation, and require both copies to have loss of function mutations in order to be cancer causing.

Oncogenes either make too much protein product or they make a protein product that is too active. These changes represent a gain in function, which causes the cell to become cancerous.

57
Q

If a cell homogenate is spun in a centrifuge, the homogenate is fractionated into parts based on relative differences in: I. mass II. density III. shape

    A. I only
    B. II only
    C. I and II only
    D. I and III only
    E. I, II, and III
A

E. I, II, and III
The sedimentation rate of a particle in a centrifuge tube will increase as the object increases in mass and density and as the shape becomes more compact. Therefore, all three of these features in the answer choice influence how a cell lysate is separated in centrifugation.

If a scientist wants to isolate a specific component of the cell within a sample of cells, the various components of the cell can be separated out through centrifugation.

First, the cells must be split open so that the components can be separated. This process is called homogenization, and is accomplished with a lab blender, or shear forces. The homogenate is the mixture of the split open cells, and is stored in an inert buffer to preserve the cell components.

A centrifuge spins the homogenate at very high speeds, in a circular path. The higher mass, denser, more compactly shaped particles will sediment to the bottom of the centrifuge tube, and this is known as the pellet. Whatever is not in the pellet is the ‘remainder on top’ and this is referred to as the supernatant.

The centrifugation process is repeated over and over to gradually separate out the different components of the cell. Cells and the nucleus come first, then dense organelles, then ribosomes and cytosol. The fractionated (isolated) components of the
cell can then be studied.

It was previously thought that only proteins worked as enzymes catalyzing reactions. However, more recent research has shown that some types of RNA is also capable of catalysis. Ribozymes are RNA molecules that can perform biological catalysis in the same manner as protein enzymes.

58
Q

The direct role of chaperonins is to

A. help eliminate reactive oxygen species from the cell
B. correct errors that occur during DNA replication
C. assist newly synthesized proteins in correct folding
D. formation of coated vesicles in receptor mediate endocytosis
E. assist in cellular digestion through their internal hydrolytic enzymes
A

C. assist newly synthesized proteins in correct folding

Chaperonins are proteins found in both prokaryotic and eukaryotic cells. Chaperonins assist newly synthesized polypeptides to fold into their correct shape.

Clathrin is a protein which aids in receptor mediated endocytosis.

When a membrane receptor binds certain substrates that the cell wants to internalize, the receptor signals for clathrin lattice formation. Clathrin forms a lattice around the incoming vesicle in pits, and this is known as a clathrin coated pit. Clathrin coating occurs intracellularly and has nothing to do directly with cell recognition.

59
Q
  1. During cellular respiration, in which of these stages is NADH produced?A. Glycolysis, pyruvate decarboxylation
    B. Glycolysis, citric acid cycle
    C. Pyruvate decarboxylation, citric acid cycle
    D. Glycolysis, pyruvate decarboxylation, citric acid cycle
    E. Glycolysis, pyruvate decarboxylation, citric acid cycle, electron transport chain
A

D. Glycolysis, pyruvate decarboxylation, citric acid cycle

Pyruvate decarboxylation is the step of cellular respiration that takes the 3 carbon pyruvate generated during glycolysis and processes that pyruvate to form a 2 carbon acetyl CoA, CO2, and NADH.

For every acetyl CoA, Krebs cycle produces 2 CO2, 3 NADH, 1 FADH2, and 1 ATP.

So for every two acetyl CoA that enters the Krebs cycle: 4 CO2, 6 NADH, 2 FADH2, and 2 ATP are produced.

60
Q

Epinephrine’s effects on tissues of the body is an example of what type of cell signaling?

    A. Paracrine
    B. Neuronal
    C. Endocrine
    D. Exocrine
    E. Autocrine
A

C. Endocrine

Paracrine signaling is when a cell signals to other cells in its surrounding vicinity. Examples include blood clotting factors and tissue healing.

Neuronal signaling is direct communication between neurons via the use of neurotransmitters being sent across a synapse.

Endocrine signaling is when hormones are secreted into the blood vasculature, and travel throughout the body. The hormone will be recognized and received by any cell that has a complementary target receptor. The sympathetic nervous system directly stimulates the adrenal medulla. The adrenal medulla then releases epinephrine (adrenaline) and norepinephrine (noradrenaline) into the blood. Epinephrine and norepinephrine will travel through the blood and act on any cell that has complementary adrenergic receptors.

Exocrine hormones are secreted from glands through a duct. Examples include sweat, salivary, mammary glands, and some of the pancreas and liver function.

Autocrine glands send extracellular signals to themselves. White blood cells are a common example of autocrine stimulation, as they release factors that stimulate themselves.

61
Q

If blood pressure is low, which of the following is true?

A. Antidiuretic hormone release is inhibited
B. Renin will partially cleave angiotensin II to activate it
C. Angiotensin II production would further decrease blood pressure
D. Vasoconstriction will increase total peripheral resistance
E. The kidneys would lower plasma salts levels
A

D. Vasoconstriction will increase total peripheral resistance

If blood pressure is low, antidiuretic hormone is produced and released to increased blood volume/pressure

Renin converts angiotensinogen to angiotensin I. Angiotensin converting enzyme converts angiotensin I to angiotensin II.

When blood pressure is low, angiotensin II levels increase, which increases levels of circulating aldosterone. This increases the amount of salt that is reabsorbed in the nephron, and therefore increases the amount of circulating salt.

When blood pressure is low, antidiuretic hormone (ADH) is released in order to preserve fluids. ADH helps us to reabsorb more water in the collecting duct of the nephrons, limiting how much we pee out. If we have more body water, blood volume increases. Higher blood volume = higher blood pressure.

62
Q

Angiotensin II has many effects in the body. The most important are:

A

– It stimulates additional aldosterone release from the adrenal gland cortex (so aldosterone levels increase).

– It increases Na+ reabsorption from the proximal tubule (and water will follow the salt).

– It is a potent systemic vasoconstrictor – causing vessels to constrict, thereby increasing total peripheral resistance (TPR).

– It makes the individual more thirsty – so they drink more and increase their blood liquid volume (increasing TPR).

Aldosterone is considered a mineralocorticoid hormone, and is produced by the adrenal cortex. Aldosterone functions to increase salt and water reabsorption, as well as potassium secretion in the distal tubules and collecting duct of the kidneys.

63
Q

Cardiac output = Heart rate (HR) x stroke volume (SV)

A

Heart rate is how fast the heart beats.

Stroke volume is the volume of blood that is pumped out of the heart with each beat.

Mean arterial blood pressure (MAP) is calculated from the cardiac output (CO) of the heart and the total peripheral resistance (TPR) of the vessels.

MAP = CO x TPR

MAP = (HR x SV) x TPR

So increasing either the rate at which the heart beats, the volume of blood the heart pumps, or the total peripheral resistance in the vessels will increase the blood pressure.

And we can increase TPR by constricting our blood vessels – making the diameter of the lumen of the vessel smaller (dilating the blood vessels would decrease TPR).

64
Q

Glial cells

A

non-neuronal cells in the nervous system that nourish, support, and protect the neurons and make to ensure the conditions are perfect for neuronal health.

There are two subcategories of glial cells: microglia and macroglia.

Microglial cells are the defenders of the CNS. They are specialized macrophages which protect the CNS.

Macroglia can be further broken down into subtypes.

The most important points about macroglia for DAT purposes are:

Schwann cells: these are the cells that form myelin sheath in the peripheral nervous system.

Oligodendrocytes: form the insulating myelin sheath in the central nervous system.

Astrocytes: the most abundant type of glial cell. They help provide blood supply to CNS neuron, recycle neurotransmitters, and maintain proper ion levels. They also help to form the very important Blood-Brain-Barrier – a barrier which helps ensure the brain’s cerebrospinal fluid (CSF) has unique, specific composition compared to composition of blood.

Satellite cells: have similar function to astrocytes, but satellite cells function in the PNS.

Ependymal cells: they create the cerebrospinal fluid which bathes the spinal cord and the brain.

65
Q

Insulin is a protein (peptide) hormone, and most directly promotes cells to uptake glucose by

A. increasing glucose transporter protein translation by acting as a transcription factor in the nucleus
B. increasing exocytosis of glucose into the vascular circulation
C. making the phospholipid bilayer directly permeable to glucose diffusion
D. stimulating translocation of vesicles containing glucose transporters to the cellular membrane
E. stimulating the hypothalamus to increase the body’s temperature
A

D. stimulating translocation of vesicles containing glucose transporters to the cellular membrane

Steroid hormone bind to receptors in the nucleus and act as transcription factors. Insulin is a protein hormone that binds to an insulin receptor tyrosine kinase on the cell surface

Glucose is a large molecule and cannot diffuse through the phospholipid bilayer. Insulin has no effect on this.

Insulin stimulates premade vesicles (membrane bound packages) of glucose transporter to translocate and fuse with the membrane. This increases the cell’s efficiency at bringing glucose into the cell.

Pyrogens are hormones that causes the hypothalamus to increase the body’s temperature.

66
Q

Which of the following are true regarding blood clotting components?

A. Platelets contain multiple nuclei
B. Fibrin converts prothrombin into thrombin
C. Platelets are the cell fragments of old red blood cells
D. Exposed collagen in damaged blood vessels activates platelets
E. Vitamin K aggregates to plug damaged blood vessels
A

D. Exposed collagen in damaged blood vessels activates platelets

Platelets are cell fragments, and do not contain a nucleus (anucleate). RBCs are also anucleate.

Thrombin is protease which converts circulating fibrinogen in the blood into long strands of the protein fibrin. Fibrin accumulates with platelets to form a blood clot.

Megakaryocytes are large bone marrow cells that are the precursor to platelets.

When a blood vessel is damaged, collagen fibers from the blood vessel wall that previously were internal are now exposed to the blood circulating through that vessel. Platelets that are circulating past this area are activated and bind. This begins the coagulation cascade.

Vitamin K is an important cofactor for some of the clotting factors in the clotting cascade. However, it does not form the clot itself – it is just a cofactor.

67
Q

Clotting Cascade:

A

a. Tissue is damaged. This tears blood vessel walls which exposes collagen that is within the wall.
b. Exposed collagen in the circulating blood causes the platelet activation and platelets begin to adhere and aggregate in the area of the blood vessel where the rip has occurred. This forms a platelet plug.
c. Activated platelets release thromboplastin (also known as tissue factor). Thromboplastin converts the precursor (inactive) prothrombin into its active form, thrombin.
d. Activated thrombin converts precursor fibrinogen to fibrin. Fibrin strands polymerize with other fibrin strands, and attach to platelets to form a blood clot (hemostatic plug).

Mnemonic: PTPT, TFF
Mnemonic: P(platelets) T(Thromboblastin) P (Prothrombin) T(Thrombin)
T (Thrombin) F (Fibrinogen) F (Fibrin)

68
Q

large bone marrow cells that are the precursor to platelets?

A

Megakaryocytes

69
Q

What does it mean if a bacteria is competent?

A. It can transfer genes through transduction
B. It can transfer genes through transformation
C. It can receive genes through transduction
D. It can receive genes via transformation
E. It can transfer and receive genes via conjugation
A

D. It can receive genes via transformation

70
Q

Which of these Animalia phyla has a true coelem?

    A. Nematoda
    B. Cnidarian
    C. Platyhelminthes
    D. Mollusca
    E. Porifera
A

D. Mollusca

Coelom is a fluid filled body cavity that has a lining derived from the mesodermal layer. The mesodermal lining of the coelom is known as the peritoneum.

71
Q

Which animals contain a coelom?

A

PR…ivileged… – PoRifera

Ch…ildren – Cn…idarian (Ch looks like Cn)

PLAY – PLAtYhelminthes

Nicely – Nematoda (only one N in the mnemonic)

ANd – ANNelida

Maturely – Mollusca (only one M in the mnemonic)

ARTHur – ARTHropoda

Ensures – Echinodermata (only one E in the mnemonic)

Cooperation – CHOrdata

Everything before Nematoda is acoelomate (lack a coelom). Everything after Nematoda is coelomate (contains a coelom).

Nematoda are considered pseudocoelomate (‘fake’ coelomate). Pseudocoelom is a body cavity that does not contain a full peritoneum. This pseudocoelom helps with nematode motility – they use the pseudocoelom as a hydrostatic skeleton. A hydroskeleton provides rigidity through fluid pressure.

72
Q

Which biome is best described as the largest terrestrial biome, that has very cold winters, and many cone bearing trees?

    A. Temperate deciduous forest
    B. Temperate grasslands
    C. Tundra
    D. Tropical rain forest
    E. Taiga-boreal forest
A

E. Taiga-boreal forest

The taiga-boreal forest is the largest terrestrial biome, characterized by cold winters (it has a far northern latitude) and coniferous (cone bearing) trees.

The tundra is far North, with very little precipitation and permafrost (a layer of permanently frozen soil). There is a short growing season, and low biotic diversity.

Deciduous forest goes through four different seasons. The leaves of trees change color in the autumn season and fall to the ground- this is what defines ‘deciduous’. Because of falling leaves, the soil has rich organic matter. There is vertical stratification of species – meaning different species exist at different altitudes (ground, in the branches of trees, and at the tops of trees).

Temperate grasslands are large, rolling hills of grass and flowers. There are very few trees and little rainfall. There are two main seasons: growing season and a dormant season. During the dormant season it becomes too cold and the ground too hard for anything to grow.

73
Q

Sebaceous glands can be found in all of the following areas EXCEPT for one. Which one is the EXCEPTION?

    A. Eyelids
    B. Palms
    C. Scalp
    D. Underarms
    E. Earlobes
A

B. Palms

Sebaceous glands are tiny glands in the skin that secrete an oil called sebum. They are located in the dermis of the skin and found nearly everywhere in human skin EXCEPT for the palms of the hands and soles of the feet. The body releases this oil to waterproof and protect the skin, but it also is a lipid and reduces friction. It doesn’t make sense to make your hands and feet slippery, so we can infer this must be the correct answer.

The palms of the hands (as well as soles of the feet) are the only areas of the body that do not contain sebaceous glands, so the answer choice is correct. Sebaceous glands produce oil (sebum) and are connected to hair follicles (of the answer choices listed, only the palms lack any hair follicles). The oil of sebaceous glands keeps the skin relatively acidic to discourage microbial growth. When these glands become plugged, acne results.

74
Q

What is the function of Haversian canals in long bones?

A. Provide flexibility to bones
B. Supply nutrients and nerve function in compact bone
C. Form dense lamellae to support the bone
D. Provide space for red bone marrow growth in cancellous bone
E. Surround and protect the shaft of the bone
A

B. Supply nutrients and nerve function in compact bone

A long bone is made of dense compact bone (cortical bone) on the outside and cancellous bone on the inside (less dense bone). The dense compact bone still needs nutrients and nerve function, and Haversian canals provide this function by having little tubes running parallel to the axis of the long bone. The Haversian canals house blood vessels, nerves, and lymphatic vessels.

Cancellous bone, also known as spongy bone, is less dense and houses red bone marrow and yellow bone marrow. Red bone marrow produces erythrocytes (red blood cells), platelets, and white blood cells. The periosteum surrounds the outer surface of all bones and provides nutrients.

Haversian canals are formed when osteoclasts burrow tunnels through the bone.

It is osteoblasts that form the dense lamellae to support the bone; therefore the answer choice is incorrect. After osteoclasts have burrowed tunnels forming the Haversian canals, osteoblasts lay down new matrix onto tunnel walls forming the concentric rings that are the lamellae.

75
Q

Which of these is known as the pacemaker of the heart?

    A. AV node
    B. Purkinje fibers
    C. SA node
    D. bundle of His
    E. vagus nerve
A

C. SA node

The sinoatrial node, or SA node, initiates the contraction of the heart and is known as the cardiac pacemaker. The SA node is located in the upper right atrium of the heart. It contracts the atria to fill the ventricles with blood and sends a delayed signal to stimulate the atrioventricular node, or AV node. The AV node sends an impulse through the bundle of His and Purkinje fibers, which results in the contraction of the ventricles. The vagus nerve is a cranial nerve that functions in parasympathetic activities. (you go to vegas, I don’t feel bad for you)

The Purkinje fibers – located in the walls of the ventricles – receives the impulse from the bundle of His and in turn causes contraction of both ventricles.

76
Q

Which of the following factors is involved in both specific and non-specific immunity?

    A. MHC II
    B. B cells
    C. Lysozyme
    D. Helper T cells
    E. Macrophages
A

E. Macrophages.

Macrophages can act as either non-specific or specific phagocytes. In non-specific defense, they engulf pathogens by phagocytosis. In specific defense, they engulf antibody-coated antigens by phagocytosis. Major histocompatibility complex II, or MHC II, and B cells are only used in specific immunity. Lysozyme is involved only in non-specific defense as an anti-bacterial enzyme. Helper T cells are lymphocytes that originate in the bone marrow like B cells, but mature in the thymus (hence why they’re called T cells). They have antigen receptors on their surface and only used in specific immunity.

The stomach is where digestion of proteins begins in humans, via the digestive enzyme pepsin that breaks proteins down into smaller polypeptides for further digestion.

While digestion takes place in the small intestine, the majority of it occurs in the duodenum – the jejunum and ileum primarily act in absorption.

77
Q

During the respiratory cycle, the intrapleural pressure of the lungs is most negative during the:

    A. end of exhalation.
    B. end of inhalation.
    C. beginning of exhalation.
    D. beginning of inhalation.
    E. peak relaxation of the diaphragm.
A

B. end of inhalation.

During inhalation our diaphragm contracts and therefore the volume in our lungs increases. This increase in volume leads to a decrease in pressure, which causes air to flow into our lungs. At the very end of inhalation is the point where we cannot breathe in anymore because our intrapleural pressure reaches its maximum negative value. During exhalation we relax our diaphragm, the volume of the lungs decreases, and air is pushed out of our lungs.

Intrapleural pressure is the pressure within the pleural space (the fluid filled space between the double layered membranes covering the lungs). It is negative relative to the atmospheric pressure. When a person breathes in, the diaphragm contracts and the lungs expand, causing the intrapleural pressure to become more negative. At the end of inhalation (peak expansion of the lungs), the intrapleural pressure is most negative, so the answer choice is correct. As exhalation begins, the diaphragm relaxes and lung volume decreases, causing the intrapleural pressure to rise (become less negative).

78
Q

In a nephron, which of the following changes would increase the osmolarity of the filtrate in the collecting duct?

    A. increase of water in the blood
    B. increase of water in the body cells
    C. increase in cortisol
    D. increase in ADH
    E. decrease in ADH
A

ADH, or vasopressin, is produced by the hypothalamus and released by the posterior pituitary. It allows the collecting duct of the nephron to become more permeable to water, and as a result more water is reabsorbed from the filtrate. If more water is reabsorbed, then the remaining filtrate will become more concentrated, or have a higher osmolarity.

When there is excess water in the body, the posterior pituitary secretes less ADH (there is less need to reabsorb water). Secreting less ADH would lead to a more dilute urine since the body is already well hydrated. Cortisol is a glucocorticoid released in response to stress. Cortisol provides several functions, including increasing blood glucose, suppressing the immune system, and aids in metabolism.

79
Q

Which of the following would increase the expression of a eukaryotic gene?

    A. Acetylation
    B. RNA interference
    C. Methylation
    D. Heterochromatin packaging
    E. Repressor proteins
A

A. Acetylation

DNA is coiled around histones in eukaryotes and some Archaea. The combination of DNA and histones is called a nucleosome. Recall that DNA has a slight negative charge. If we attach methyl groups to the histone, we will make the histone more positively charged. This will attract the negatively charged DNA more, and will bind the DNA to the histone tighter, decreasing transcription. If we add acetyl groups to the histones, we would make the histone groups more negative, and they would repel the negatively charged DNA to make the DNA more accessible, thus there will be more transcription and more expression of the gene. RNA interference is a method of gene control where siRNAs will degrade mRNA, which will decrease the expression of a gene. Heterochromatin is tightly packed DNA that consists of genes not transcribed. On the other hand, euchromatin consists of more “open” DNA that is transcribed and expressed.

80
Q

When a lipid hormone binds to an intracellular receptor, it does what?

    A. Activates a G protein
    B. Acts as a transcription factor
    C. Activates adentylate cyclcase
    D. Phosphorylates tyrosine residues
    E. Embeds into the cellular membrane
A

B. Acts as a transcription factor

Lipid hormones are small and nonpolar, and can diffuse through the cell membrane. If they bind to a cytosolic or nuclear intracellular receptor, it will translocate to the nucleus (if it is not already bound to DNA) and activate gene transcription as a transcription factor.

81
Q

In which of the following ways do CAM carbon fixating plants differ compared to C3 carbon fixating plants?

A. In CAM plants, thylakoid membranes do not contain chlorophyll
B. In CAM plants, the initial enzyme that fixes CO2 fixes the CO2 into a four carbon molecule
C. In CAM plants, there are no light independent reactions
D. In CAM plants, no CO2 is required to produce glucose
E. In CAM plants, the light dependent reactions are able to occur at night
A

B. In CAM plants, the initial enzyme that fixes CO2 fixes the CO2 into a four carbon molecule

82
Q

What type of enzyme removes phosphate from its substrate?

    A. Helicase
    B. Protein kinase
    C. Phosphatase
    D. Topoisomerase
    E. Ligase
A

C. Phosphatase

Kinases add phosphate to their substrate.

Helicase ‘unzips’ the DNA double helix.

A phosphatase is an enzyme which cleaves phosphate off of a substrate.

Topoisomerase prevents ‘tangles’ as the DNA helix is being unwound. It relieves this stress by creating ‘nicks’ in the backbone.

Ligase will ‘glue’ or ligate two unattached pieces of nucleic acid together.

83
Q

In eukaryotes, FADH2 is produced where?

    A. Intermembrane space of the mitochondria
    B. Outer mitochondrial membrane
    C. Inner mitochondrial membrane
    D. Mitochondrial matrix
    E. Cytosol
A

D. Mitochondrial matrix

FADH2 is produced during the Krebs cycle which occurs in the mitochondrial matrix.

Glycolysis occurs in the cell cytosol. Glycolysis does generate NADH, but not FADH2.

The mitochondrial matrix is the viscous fluid in the ‘inside’ of the mitochondria, which contains the mitochondrial DNA, ribosomes, and some enzymes.

Pyruvate decarboxylation is the step of cellular respiration that takes the 3 carbon pyruvate generated during glycolysis and process that pyruvate to form a 2 carbon acetyl CoA, CO2, and NADH. Pyruvate decarboxylation also occurs in the mitochondrial matrix.

84
Q

Which of the following represents a structural motif that is seen in regulatory proteins that bind to DNA?

    A. Leucine-finger motif
    B. Helix-turn-helix motif
    C. Alpha-zipper motif
    D. Leucine-tail motif
    E. Beta-turn motif
A

B. Helix-turn-helix motif

The four common structural motifs seen in regulatory proteins that bind to nucleic acids are:

Zinc-finger motif
Leucine-zipper motif
Helix-turn-helix motif
Helix-loop-helix motif

These are ‘structural’ components that occur again and again in the regulatory proteins that bind to nucleic acids. For the purposes of the DAT, being familiar with their names and their function (they are structural components seen in proteins that bind DNA) is sufficient.

85
Q

An exergonic reaction

A. receives a net input of energy from the environment
B. is a nonspontaneous reaction
C. requires an enzyme in order to react
D. has an activation energy requirement
E. absorbs heat from the environment
A

D. has an activation energy requirement

Even though there is a net release of energy, all reactions require some energy of activation.

In thermodynamics, work is equal to energy. Exergonic reactions release energy, so exergonic reactions do work on the environment. Endergonic reactions absorb work from the environment.

86
Q

Fatty acid beta oxidation directly

A. produces glucose which enters glycolysis
B. produces acetyl CoA which enters Krebs cycle
C. produces cholesterol which embeds in the cell membrane
D. excretes lipids to eliminate them from the cell
E. produces phosphate which buffers the blood
A

B. produces acetyl CoA which enters Krebs cycle

87
Q

Regarding the lymphatic system, all of the following are true EXCEPT one. Which one is the EXCEPTION?

A. Contains valves which ensures unidirectional lymph flow
B. The main white blood cell types in lymph are neutrophils, and macrophages
C. Lymph is propelled by contraction of smooth muscle as well as skeletal muscle
D. Connects into the blood circulatory system
E. Controls interstitial-fluid levels
A

B. The main white blood cell types in lymph are neutrophils, and macrophages

The main white blood cell types in the lymphatic system are the lymphocytes; lymphocytes are T cells and B cells

The lymphatic system relies on both smooth muscles in the vessels and contraction of the vessels by adjacent skeletal muscle in order to be propelled

The lymphatic system contains valves, which ensure that lymph (the fluid that circulates through the lymphatic system) moves in a unidirectional, ‘forward’ direction. This is important, as the lymphatic system has no central pump (it is not ‘pumped’ by the heart, like the blood circulatory system is), and is a low pressure system. This is similar to veins, which have valves to ensure unidirectional flow, for the same reason (low pressure system).

Remember, the lymphatic system is a low pressure system, and there is no pump. Lymph moves in the ‘forwards’ direction both by the contraction of smooth muscle in the walls of the lymphatic vessels AND by contraction of skeletal muscle that is adjacent to the lymphatic vessels. When the adjacent skeletal muscle is flexing (for example, think of a bicep flexing), it creates pressure in the area, which causes the lymph to be pushed forwards (and remember, it can only travel one way because of the unidirectional valves).

88
Q

Which of the following describes trypsinogen?

A. an inactive form of a nuclease
B. an inactive form of a protease
C. an active form of a nuclease
D. an active form of a protease
A

B. an inactive form of a protease

A zymogen is the inactive precursor of an enzyme. Trypsinogen is the inactive form of trypsin which is a protease in the GI tract.

When food enters the duodenum, glands in the duodenum release enteropeptidase. Trypsinogen is activated by entereopeptidase to active trypsin. Active trypsin then cleaves chymotrypsinogen to form the activated chymotrypsin.

When a food bolus enters the stomach, the stomach is distended (stretched). This stretching is a signal for G cells of the stomach to release gastrin. Gastrin is a hormone which stimulates parietal cells of the stomach lining to release gastric juice (very acidic solution with high hydrochloric acid). Gastrin also stimulates chief cells of the stomach lining to secrete pepsinogen. Pepsinogen is a zymogen.

Secretin is a hormone released by the duodenum in response to highly acidic gastric juice entering into the small intestine. Secretin causes the pancreas to secrete bicarbonate (HCO3–) into the duodenum. Bicarbonate is alkaline (basic) and will neutralize the acidic gastric juice that has entered the small intestine by way of the stomach.

89
Q

Gamma aminobutyric acid (GABA

A

major inhibitory NT in the body. It generates an inhibitory effect by opening ion channels that allow more chloride (Cl–) into the neuron and/or potassium ions (K+) out of the neuron.

Because chloride is a negatively charged ion, if chloride enters the neuronal cell, the cell will become more negative; because potassium is a positively charged ion, if potassium leaves the neuronal cell, the cell will become more negative. If the neuron becomes more negatively charged, it is less likely to fire an action potential, ie. It is inhibited.

90
Q

If a person has circulating anti-A and anti-B antibodies, what is their blood type?

    A. Type A
    B. Type B
    C. Type O
    D. Type AB
    E. Type ABO
A

C. Type O

Another blood cell surface protein is the Rhesus factor (Rh). You either have the Rh or do not have the Rh. So you are either Rh positive (+) or Rh negative (-). This is where (+) and (-) designations in blood typing come from, eg. my blood type is B+ (B positive).

If a donor is Rh+ they cannot donate to someone who is Rh- as the Rh+ donor has Rh antigens on the blood cell surface.

The universal donor (donor who can donate to anyone) is O-. O blood type has neither A nor B surface antigens, and O negative blood also does not have an Rh surface antigen. This means there are no blood cell surface antigens that would stimulate immune clearance.

The universal acceptor is AB+. Because an AB+ person has both A and B cell surface antigens, as well as an Rh surface antigen, they can receive any blood type and not mount an immune response Any blood cell surface antigen they receive would be something their blood cells already have.

91
Q

Which of the following is part of the adaptive immune response?

    A. Macrophage phagocytosis
    B. Lysozyme
    C. Histamine release
    D. The complement system
    E. Antibodies
A

E. Antibodies

Innate immunity is the body’s first line of defense, and is a nonspecific response.

Innate immunity continues with the inflammatory response. There are five signs associated with inflammation: heat, redness, swelling, loss of function, and pain. Inflammation is associated with certain innate immune response cells like neutrophils, monocytes/macrophages, eosinophils, and basophils/mast cells

Inflammation is associated with certain innate immune response cells like neutrophils, monocytes/macrophages, eosinophils, and basophils/mast cells

While the innate immune response is nonspecific, the adaptive immune response is specific.

92
Q

Acronym for remembering the relative number of leukocytes (white blood cells) circulating in the blood from highest number of cells to lowest number of cells:

A

Never Let Monkeys Eat Bananas

Never = Neutrophils

Let = Lymphocytes (Natural Killer, T cells, B cells)

Monkeys = Monocytes/macrophages

Eat = Eosinophils

Bananas = Basophils (which form mast cells)

93
Q

Adaptive Immunity lymphocytes

A

The adaptive immunity lymphocytes are B cells and T cells. They are both produced in the bone marrow from blood stem cells. B cells mature in the bone marrow, while T cells travel to the thymus to mature.

94
Q

Which of the following best describes the function of a gizzard?

A. It acts as the site of oxygen exchange in Cnidaria
B. It is a sex organ in Porifera
C. It is the voice box in Arthropoda
D. It is a site of digestion in Annelida
E. It forms a rudimentary backbone in Echinodermata
A

D. It is a site of digestion in Annelida

The gizzard is the site of mechanical digestion in a group of animals, including the annelida (earth worm).

The gizzard is part of the digestive tract that has muscular walls which function to pulverize food. Often the food is mixed with other organic matter like soil that aids in breaking down (digesting) food.

95
Q

Which of the following is equivalent to the inner cell mass of a mammalian embryo?

    A. The blastocoel
    B. The blastodisc
    C. The vitelline layer
    D. The primitive streak
    E. The allantois
A

B. The blastodisc

The inner cell mass is the bilaminar part of the mammalian blastula that will form the actual embryo. The blastodisc is the bilaminar part of the bird, reptile, and fish embryo that will form the actual embryo.

The zona pellucida is the mammalian equivalent to the vitelline layer of the sea urchin. This is a glycoprotein layer that is on the exterior of the egg, which helps bind sperm during fertilization.

The primitive streak is the site of gastrulation. Mammalian embryos also have a primitive streak that forms within the inner cell mass.

The allantois is an extraembryonic membrane, and aids in gas exchange for the embryo.

96
Q

Which of the following best describes an ecological community?

A. A specific species, that live in one location
B. A specific species, that live in one location and the abiotic factors that species interacts with
C. All organisms that live in one location
D. All organisms that live in one location and the abiotic factors the organisms interact with
E. The abiotic factors in one location
A

C. All organisms that live in one location

An ecosystem represents all the organisms in one location (community) and the abiotic factors that interact with them.

97
Q

Which part of the prokaryotic RNA polymerase allows the enzyme to have increased binding specificity at promoter regions?

    A. Spliceosome
    B. Lysosome
    C. Sigma factor
    D. rRNA
    E. Hemoglobin
A

C. Sigma factor

Sigma factor binds to core RNA polymerase to form RNA polymerase holoenzyme. Sigma factor makes prokaryotic RNA polymerase have more specific binding to promoter regions.

Prokaryotic RNA polymerase holoenzyme is the combination core RNA polymerase with sigma factor.
Prokaryotic core RNA polymerase is able to bind to prokaryotic DNA, but it lacks the ability to target promoter sites that are upstream of the gene to be transcribed.

Prokaryotic core RNA polymerase will combine with sigma factor to form RNA polymerase holoenzyme. The sigma factor provides RNA polymerase holoenzyme the ability to target the promoter region of bacterial DNA.

98
Q

Which of the following is true of natural killer immune cells? Natural killer cells

A. help the immune system retain immunological memory
B. are recruited to the sites of action after T lymphocytes
C. induce apoptosis in cancerous cells
D. are precursors to monocytes
E. contain a high amount of histamine granules
A

C. induce apoptosis in cancerous cells

Natural killer cells are part of the innate immune system. The innate immune system has no immunological memory.

Natural killer cells are part of the innate immune system, whereas cytotoxic T cells are part of the adaptive immune response. The innate immune system is quicker acting as it does not require activation. The adaptive immune system requires activation, and this means it is slower to begin acting

Natural killer cells defensive actions include creating holes in the cellular membrane of its target, which causes target cells lysis, and inducing apoptosis (programmed cell death) in rapidly dividing cells.

Monocytes are the precursor cells to macrophages.

Basophils, mast cells, and eosinophils contain high amounts of cytoplasmic histsamine.

While the innate immune response is nonspecific, the adaptive immune response is specific. The innate immune response is a generalized approach whereas the adaptive immune response is a targeted approach.

99
Q

Innate immunity lymphocytes:

Adaptive immunity lymphocytes:

A

Innate immunity lymphocytes: Natural killer cells.

Adaptive immunity lymphocytes: B and T cells

Natural killer cells (NK) are part of the innate immunity, and share many similarities to cytotoxic T cells (CD8) which are part of the adaptive immunity. As the adaptive immune system requires activation, but the innate immune system is always ‘on’, NK cells are often the first to act, and CD8 cells will come in to help once the adaptive immunity has been stimulated. NK cells therefore have a speed advantage as they don’t need to be activated before they can do their job. However, CD8 cells have a specificity advantage, and will be more targeted as they have been activated to the specific antigen.

100
Q

Eosinophils

A

Eosinophil cell cytoplasm are filled with granules, and eosinophils are granulocytes. Eosinophils contain a variety of proteins that are damaging to both pathogens as well as host tissues. Eosinophils are important in fighting parasites.

Two important proteins to remember that are found in eosinophils are major basic protein, and eosinophil cationic protein.

101
Q

Basophils/Mast cells:

A

Like eosinophils, basophils/mast cells are granulocytes. The cell cytoplasm of these cells is filled with granules that can be released through degranulation. These cells are also packed with histamine as well as heparin, and are important mediators of inflammation/the allergic response. Histamine causes vasodilation, and heparin helps to prevent clots from forming – both of which promote more blood entry. Basophils leave bone marrow as mature cells and remain circulating in the blood, whereas mast cells leave the bone marrow and circulate the blood as immature cells, only maturing when they enter the tissue.

102
Q

Which of the following is a type of intramolecular force that is seen in the tertiary structure of a protein, but not in the secondary structure of a protein?

    A. Subunit bonding
    B. Hydrogen bonding
    C. Peptide bonding
    D. Covalent bonding
    E. Hydrophobic interactions
A

E. Hydrophobic interactions

Hydrophobic interactions are only found in tertiary structure but not secondary structure.

103
Q

All of the following statements are true about receptor tyrosine kinases EXCEPT one. Which one is the EXCEPTION?

A. The protein passes through the membrane seven times
B. They often bind to growth factors
C. They often form dimers after extracellular signaling
D. Phosphatases turn the receptor off
E. The ligand binding site is extracellular
A

A. The protein passes through the membrane seven times

Receptor tyrosine kinases are single transmembrane – they only pass through the membrane once.

They also bind hormones and cytokines.

Phosphatases remove phosphate. Phosphorylation of the receptor tyrosine kinases activates a receptor tyrosine kinase, and therefore a phosphatase inactivates it.

The receptor tyrosine kinase has an extracellular ligand binding domain.

One of the defining traits of G protein coupled receptors (GPCRs) is that they are seven transmembrane (meaning the GPCR protein passes back and forth through the membrane seven times). Receptor tyrosine kinases are single transmembrane – they only pass through the membrane once.

104
Q

What type of microscopy is best for viewing live, unstained cell specimens?

    A. Cryo-electron microscopy
    B. Scanning electron microscopy
    C. Phase contrast microscopy
    D. Transmission electron microscopy
    E. It is not possible to view live cells with a microscope
A

C. Phase contrast microscopy

105
Q

What part of the inner ear is directly responsible for transducing a sound wave into a neuronal signal?

    A. Tympanic membrane
    B. Cochlea
    C. Stapes
    D. Semicircular canal
    E. Oval window
A

B. Cochlea

The cochlea is the ‘snail shaped’ portion of the ear which is responsible for the signal transduction (converting one signal into another type of signal) of auditory waves into a signal to the brain.

The semicircular canals are fluid containing canals whicih give the brain information about motion.

The oval window is the entrance for the sound waves to the cochlea.

106
Q

All of the following are true of red blood cells EXCEPT one. What is the EXCEPTION?

A. The kidneys influence the rate of red blood cell production
B. Components of hemoglobin can be excreted from the body through the gastrointestinal tract
C. Red blood cells are the most abundant type of blood cell
D. Red blood cells are rigid in order to prevent damage to the cell
E. More than 95% of oxygen traveling through the blood is traveling within red blood cells
A

D. Red blood cells are rigid in order to prevent damage to the cell

An important feature of red blood cells is their flexibility. Flexibility allows them to fit inside capillaries that are more narrow than the diameter of the red blood cell.

Cells in the kidney produce the hormone erythryopoietin (EPO). EPO stimulates stem cells in the bone marrow to increase production of red blood cells. Memory tool: Lance Armstrong used exogenous EPO because he wanted to increase his red blood cell count. Having a higher red blood cell count would increase the amount of oxygen he could carry, allowing his muscles to have increased cellular respiration.

Plasma is the noncellular, liquid component of the blood.

The remainder of carbon dioxide travels in the blood in the form of bicarbonate ion (HCO3–). Red blood cells are packed with an enzyme known as carbonic anhydrase. Carbonic anhydrase combines CO2 with H2O into carbonic acid H2CO3 which dissociates into bicarbonate HCO3– and protons H+:

107
Q

chloride shift.

A

HCO3– is able to diffuse out of the cell, but H+ cannot. HCO3– is negatively charged and as HCO3– diffuses out of the cell, the cell loses a negative charge, and becomes more positive (due to H+). Negatively charged chloride ions Cl– must diffuse into the cell to replace the lost negative bicarbonate. This is known as the chloride shift.

108
Q

What is a likely symptom if a person does not produce adequate thyroid hormone?

    A. Fast heart beat
    B. Sweating
    C. Weight loss
    D. Feeling cold
    E. Accelerated growth in a developing child
A

D. Feeling cold

Hypothyroidism would result in lowered metabolic rate, and less metabolic heat production, making the hypothyroid patient feel cold.

Fast heartbeat, sweating, weight loss, and stunted growth would all be caused by inefficient, high levels of metabolism.

Thyroid hormone stimulates a cell’s metabolic rate (the amount of energy it is producing from the nutrients it has). If a person does not produce enough thyroid hormone, they will have a low metabolic rate, and their body will ‘slow’ down. A side product of metabolism (and energy creation) is heat. When metabolic rate goes down, heat production in the body also goes down. As such, hypothyroid patients often feel cold.