13. Volume of distribution, Clearance and Half-life Flashcards

1
Q

Define volume of distribution. >

How can it be measured

What are the units

A

Volume of distribution (VD) is

the theoretical volume
into which a drug must disperse

in order to produce the

measured plasma concentration.

> 
It cannot be measured directly 
but instead it is derived from a log
concentration–time graph 
where VD = Dose/C0 

(see Chapter 10,
‘Exponential function’).

> Its units are typically mL.

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2
Q

What factors determine the volume of distribution of Drug

A
  1. > Lipid solubility of the drug.

2.
> Percentage plasma protein binding of the drug.

3.
> Percentage tissue protein binding of the drug.

4.
> Blood flow to the various tissues.

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3
Q

Define clearance

Constant / varied over time

What components take part

Sites

Derived

units

described

A

Clearance (Cl) is the

volume of plasma

completely cleared of

a substance per unit time.

> It is usually constant over
the therapeutic concentration range

because drug elimination systems
are not saturated (i.e. first-order kinetics).

> It is additive,
a function of elimination

by all participating organs such as

liver or kidney:

Cl systemic = Cl renal + Cl hepatic + Cl other.

> Kidney and liver are the
two most important sites for
drug elimination, but other sites

can include the
lungs,
muscle
and plasma.

> It can be derived from a concentration–time graph where Cl = Dose/AUC
(AUC = area under curve).

> Other equations used to calculate clearance include:

  • Cl = rate of elimination/plasma concentration
  • Cl = VD × k
  • Cl = VD × (0.693/t½) (where 0.693 = ln2)

> It is used to describe elimination in first-order kinetics.

> Its units are typically mL/min.

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4
Q

Define half-life.

Derived from

Equations to calculate

How much elim after 5 t 1/2

what is reached after 5

A

> Half-life (t½) is the time taken
for the plasma concentration
of a substance to
reduce to half its original value.

> It can be derived from a
concentration–time graph.

> Equations used to calculate t½ include:

  • t½ = 0.693 × VD/Cl
  • t½ = 0.693/k
  • t½ = 0.693τ

> After five half-lives,
elimination is 96.875% complete.

Steady-state conditions are typically
quoted to occur after five half-lives
(or three time constants).

> Used to calculate dosing schedules.

> Its units are typically minutes (min).

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5
Q

How are VD, Cl and t½ interrelated?

A

VD ∝ t½ × Cl

t½ ∝ VD/Cl

Cl ∝ VD/t½

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6
Q

How can VD, Cl and t½ be used to explain the different clinical effects of fentanyl and alfentanil?

A

> Fentanyl is significantly more
lipid soluble than alfentanil
(i.e. more potent)

and is therefore used in much smaller doses.

> Being more lipid soluble also
accounts for the higher VD of fentanyl

because the drug can better penetrate tissues.

> The differences in the onset
of effect can be explained
by the pKa values.

Both fentanyl and alfentanil 
are basic compounds, 
which means that they
become increasingly ionised 
below their pKa. 

At physiological pH 7.35
(which is above the pKa of alfentanil)

90% of alfentanil is in the un-ionised form

and

can therefore penetrate tissues easily
to produce a rapid effect.

For fentanyl, physiological pH is 
below its pKa 
and 
therefore the majority of this drug 
gets ionised such that only
9% remains in the un-ionised
form and this explains 
its longer onset of effect.

> The clearance of alfentanil
is a lot slower than that of
fentanyl but despite this

it has a shorter duration of action
because its smaller VD ensures a
shorter t½.

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7
Q

Table 13.1 Pharmacokinetic comparison of fentanyl and alfentanil

A

Drug Fentanyl Alfentanil

Dose (μg/kg) 1 10

Onset (min) 5 1–2

Duration of action (min) 30 10

Lipid solubility +++ +

pKa 8.4 6.4

Percentage un-ionised 9 90

VD (L/kg) 4 0.8

Cl (mL/min) 500–1500 300–500

t½ (min) 360 120

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