10 Basic Game Theory Flashcards
Prove via iterated strict dominance, that for the Prisoner’s Dilemma (D,D) is a (pure, strict)
Nash-Equilibrium!
- No matter what player 2 does: D gives player 1 a strictly higher payoff than C
- Player 2 knows that player 1 will not play C -> D is better than C
- -> (D, D) is the best option for both players
What is the rational behavior in an infinitely repeated Prisoner’s Dilemma? Give a short
reasoning!
- Cooperation is rational because of two reasons
- If one defects the other player might punish by defecting in the next run
- Testing cooperation (and possibly getting the sucker’s payoff) is not tragic,
because on the long run a few sucker’s payoffs are statistically not important
Explain why a pure strategy may be dominated by a mixed strategy even if it is not strictly
dominated by any pure strategy, using the following example game:
- For player 1: M not dominated by U and M not dominated by D
- If player 1 plays σ1 = (½, 0, ½) the expected utility u is u(σ1) = ½ regardless of
how player 2 plays - Compared to the pure strategy of playing M, where the payoff is always 0 shows
that M gets dominated by σ1
Prove that a mixed strategy may be dominated even if it assigns positive probabilities to
pure strategies that are not even weakly dominated, using the following example:
- U and M are not dominated by D for player 1
- Playing σ1 = (½, ½, 0) gives expected utility u(σ1) = -½, no matter what player 2
plays - D dominates σ1
What is a Vickrey Auction? Name the rational strategy in a Vickrey auction (no
explanation required)!
- An auction “game” where the good’s valuation v_i is assumed to be common
knowledge - Bids s_i
- Winning condition is to bid higher than everyone else
- The price r_i to be paid when you win is the highest bid that was not the winning
bid - Winners utility: u_i = v_i – r_i
- Other players utility = 0
- E.g. ebay
- The rational strategy is to bid the true valuation
Assume that in a 2-player game the mixed strategy profile ((a,b,0),(c,d,0)) is a mixed
strategy NE. Does the Indifference Condition in a mixed strategy NE imply that a = b = ½ ?
Give a short reasoning!
- No, this depends on the payoff of each strategy. (E.g. could be a = 2/3 and b =
1/3
Explain, why ((1/2, 1/2); (1/2, 1/2)) is a mixed strategy NE in the Matching Pennies game!
- If player 2 plays (1/2, ½) then player 1’s expected payoff is ½1 + ½(-1) = 0 when
playing H and ½(-1) + ½1 = 0 when playing T - -> player 1 is also indifferent
Derive the mixed strategy NE in the battle of the sexes, using the Indifference Condition!