Weeks 1-6 (written notes) Flashcards

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1
Q

(A) What is the main difference between electromagnetic waves and mechanical waves?

(B) What are two kinds of mechanical waves?

A

Electromagnetic waves (e.g. light/Xray) do not require a medium for propagation. Mechanical waves do require a deformable elastic medium for propagation.

1 - Transverse (such as waves in ocean)
2 - Longitudinal (e.g. echo - particle motion in same plane as wave direction)

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2
Q

Explain the propagation of sound through a medium in terms of compression and refraction

A

The compression wave causes a force that pushed a molecule toward the next one, thus compressing the “spring”. This force then pushed onto the next molecule. As the wave passes, an area of refraction (reduced pressure) occurs immediately behind the wave.

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3
Q

Explain why speed of sound varies through different materials.

A

One reason is due to the different weight of molecules making up the material. Heavier molecules transmit sound with lower velocity, due to the inertia of heavier molecules. I.e. the molecular “spring” compresses more before the following molecule moves away, and this takes more time. Vice versa for lighter molecules.

The second reason is due to differences in strength of intermolecular forces. In more compressible materials (e.g. air) the sound transmits at lower velocity. The preceding molecules must move further before enough force is applied to the next molecule (due to weaker intermolecular forces). Conversely, with stiffer (less compressive) materials such as bone, the sound transmits at a high velocity.

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4
Q

What is the difference between power and intensity in ultrasound?

A

Power is the rate of doing work. Electrical power from the machine is converted into sound (in mW for echo). Intensity is power per area (mW/cm^2). It is the intensity of the beam that affects the strength of an echo, and therefore the brightness on the monitor. The intensity of the beam is not constant (e.g. higher intensity at focal point - where the beam’s power is compressed into a smaller area).

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5
Q

How can a sonographer increase the intensity of the beam?

A
  1. Increase the power output - this is a control on the machine.
  2. Decrease the area of the beam by moving the focus to the area of interest

(Remember intensity = power/area)

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6
Q

Explain the relationship between echo intensity and pixel brightness.

A

NON-LINEAR

–> A doubling of intensity is required each time to produce equal changes in display brightness. It therefore requires a greater increase in intensity to cause a single shade in colour as brightness increases. This is why we use logarithms (to create a linear representation…. the decibel)

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7
Q

What is the decibel in ultrasound applications?

A

Used to compare differences in intensity/power/amplitude of two beams (or two different parts of the beam. Decibels are relative units, and two intensities are required for calculation.

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8
Q

What are two kinds of sound-tissue interactions that are important to understand for image formation?

A

1 - Refraction
2 - Attenuation

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9
Q

What are the types of attenuation in sound-tissue interaction?

A
  1. Absorption
  2. Divergence
  3. Scattering
  4. Reflection
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10
Q

Briefly describe refraction in ultrasound.

A

Refraction is the change in direction of an ultrasound beam when it crosses a boundary at an angle. Refraction obeys “Snells Law”.

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11
Q

Explain Snell’s Law, provide examples.

A

Snells law is used to understand beam refraction. The angle of refraction is measured from the normal of the interface (perpendicular to interface). When the beam is travelling from a higher velocity medium into a lower velocity, the beam bends back towards the perpendicular. When travelling from lower velocity to higher velocity medium, it will bend the other way, and approach 90 degrees. When the angle reaches 90 degrees, no sound is transmitted. This is the critical angle.

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12
Q

Describe the term critical angle?

A

Refraction of an ultrasound beam, whereby the beam is travelling from a lower velocity medium into a higher velocity. The critical angle is where the in beam refraction, the beam changes direction to reach 90 degrees from perpendicular to the interface, and no sound is transmitted through the interface.

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13
Q

What are the factors that beam attenuation depend on?

A

Material involved (a coefficient), the distance travelled, and the frequency of the beam.

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14
Q

1 Absorption is a form of ____?_____ in ultrasound. It is a result of ________. It directly removed ultrasound energy from the beam, which is converted to ____.

A

Attenuation

Result of internal frictional forces.

Directly removes ultrasound energy from the beam, which is converted to heat.

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15
Q

What does beam absorption depend on?

A
  1. The material itself
    (A) Viscosity (more viscous = more engery expended to move molecules = more absoprtion)
    (B) Molecule relaxation time (if slow to return to realxed position, molecules are still returning when next wave hits. More energy is required to stop the movement and reverse it, than if the molecule is at rest
  2. Frequency of the beam
    (A) increased freq = faster molecules are moved = more energy expended)
    (B) increased freq = shortner wavelength = less time to return to position (relaxation time)
  3. Depth of the tissue (further travel = further absoprtion
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16
Q

What is Divergence?

What is another word for Divergence?

A

The spreading of an ultrasound beam as it moves further from the source

Diffraction

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17
Q

What happens with increased divergence?

A

Increased diffraction (spread) = increased attenuation.

Remember, intensity = power per area. As area increased, intensity decreases

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18
Q

How does beam frequency impact beam absorption (attenuation)

A

Two ways
1 - A higher frequency will mean the molecules are moved faster, and more energy is expended as heat. Therefore more absoptionn attenuation.
2 - With higher frequency/shorter wavelength, the molecules have less tie to return to their rest position. This can mean molecules are still returning to rest the next wave hits, and it takes more energy to stop the movement and reverse it.

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19
Q

Give 5 examples of when beam divergence occurs?

A
  1. In the far field of a non-focussed transducer
  2. Beyonf the focal zone of a focussed tranducer
  3. After refraction from a convex interface
  4. After refraction at a curved interface
  5. After passing through a small aperture
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19
Q

Can divergence occur with reflected wavefronts?

A

Yes, divergence attenuation can occur on a pulsed wave and a returning echo wave

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20
Q

What is scattering in ultrasound?

A

A form of attenuation

The dispersion of the u/s beam in many directions. It occurs when the u/w wave strikes a very small object.

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21
Q

Discuss how scattering is affected by wavelength? What is this called? Provide an example.

A

When the interface is very small (i.e. much smaller than the wavelength), scattering occurs equally in all directions.

This is called Rayleigh Scattering

E.g. Occurs from blood cells (v small diameter relative to wavelength)

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22
Q

Rayleigh Scattering is ________ dependent.
Explain the relationship.

A

Frequency

The intensity of the reflected echo is approximately proportional to the fourth power of the frequency
I ~= F^4

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23
Q

How does scattering affect image formation?

A

A) With scattering only a very small portion of the beam returns to the transducer and is used as part of the image

B) The many scattered waves interact with each other (through interference) to form backscatter patterns (This contributes to the organ texture we see on the image)

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24
Q

Reflection is a form of ______ and is the major contributor to _____

What are the two types of reflection?

A

Attenuation
Image formation

Non-specular (diffuse) and specular

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25
Q

What is non-specular reflection?

A

Occurs when a sound wave strikes a rough or irregular surface. The echo returned back to the transducer is SMALL, but is NOT angle dependent of the incident beam (i.e. the sound beam can strike the surface at a wide range of angles and some echoes will return to the transducer).

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26
Q

What is specular reflection?

A

Occurs when a sound wave strikes a large smooth surface. The reflection from a specular reflector is very LARGE, however det4ection is highly dependent on the angle of incidence. If that beam does not strike at or close to 90deg, the reflected echo will not travel back to the transducer (therefore not be detected)

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27
Q

The percentage of an US beam reflected back to the transducer depends on …..

A
  1. The angle of incidence
  2. The reflecting surface texture
  3. The acoustic property differences of the two tissues (we can use acoustic impedance of different materials to calculate)
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28
Q

Explain acoustic impedance and how is it calculated in ultrasound? What are its units of measurement?

A

Acoustic impendence is an acoustic property of a material, used to understand the percentage of ultrasound that is reflected and transmitted at an interface.

It is the product of the materials density, and the velocity of ultrasound in the material (Z = P V)
where p = density of material, V = velocity of sound in material

Rayls (aka kg.m^-2.s^-1x10^-6)

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29
Q

What does a reflection coefficient represent?

A

The fraction of the ultrasound beam that is reflected at an interface.

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30
Q

What is the average U/S beam attenuation? How to we account for attenuation in image formation?

A

On average, an U/S beam intensity is attenuated by 1dB/cm/MHz in soft tissue, therefore echoes returning from deeper structures become progressively weaker and weaker. These echoes would be represented on the B-Mode image monitor much darker (less brightness).
To overcome this, we used time gain compensation to amplify the deeper echoes more than the closer echoes, which can produce equal brightness from similar interfaces regardless of there depth.

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31
Q

What is the purpose of time gain compensation?

A

To produce equal brightness of echoes from similar interfaces, regardless of their depth in the patient (i.e. amplify deeper echoes)

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32
Q

There are several aspects of TGC. What are these?

A
  • Near gain
  • Slope
  • Far gain
  • The delay
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33
Q

What is near gain vs far gain

A

Near gain represents the amount of gain applied to the closest echoes. Since these echoes are relatively strong, minimal gain is required. Far gain is the amount of gain applied to distant echoes, where normally higher gain is required to produce equal amplitude/brightness of echoes.

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34
Q

What is the slope adjustment in TGC?

A

Slope adjusts the rate at which the amplification is increased for deeper echoes. Tissues which attenuate the signals more will require an increase in the TGC slope. For example, a fatty liver.

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35
Q

What is the delay adjustment in TGC?

A

The delay control regulates the time (depth) at which the TGC begins to be applied. A delay would be useful when the superficial echoes are of no interest (such as strong echoes from the skin surface) and in fact, amplification would be detrimental to the image.

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35
Q

Discuss the two main systems of TGC control in US

A

(A) 3 or 4 function systems (older U/S systems). These have a single control for each of a number of the following adjustments (near gain, slope, fair gain, delay)

(b) Segmental system (modern system). There is separate controls for each of a number of individual depths in the patient. Most machines have presets, and the controls for TGC are designed just to adjust the settings for individual patients.

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36
Q

List the main features of a simple transducer (which all transducers have)

A
  • PZT crystal
  • Case
  • Electrodes
  • Dampening material
  • Matching layer
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37
Q

What is the piezoelectric crystal and how does it work?

A

The PZT is the main functional components of the transducer. The crystal expands and contacts to send out ultrasound waves. This expansion/contraction occurs by the application of an AC voltage. The crystal expands/contracts and then “rings” (or resonates) like a bell for a short time. The frequency at which it resonates is called its resonant frequency.

The two main functions
1. Convert electrical energy into mechanical energy (transmit echoes)
2. Concert mechanical energy into electrical energy (receive echoes)

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38
Q

What is the critical dimension of a PZT crystal?

A

This is its thickness.

The thickness of the crystal is 1/2 the wavelength of its resonant frequency.

39
Q

Do thicker crystals resonate at higher or lower frequencies? Why?

A

Lower.
Because a crystals thickness is half the wavelength of its resonant frequency –> increased thickness = increased/longer wavelength = lower frequency.

40
Q

What is the role of the electrodes in a basic transducer?

A

The electrodes’ role is to energise the PZT crystal. This may be a thing plating for gold or silver, with an electrical connector to the crystal.

41
Q

What is dampening material used for? Where is it found?

A

Dampening material is found in all basic U/S transducers. It is used to stop the resonance of the PZT crystal in order to produce short U/S pulses. If the crystal was able to ring down unhindered, a long ultrasound pulse would result, which is not ideal as short pulses are required for high resolution. The dampening material also stops the sound waves from passing back into the transducer and bouncing back into the crystal and causing artifact/noise.

42
Q

What is the purpose of a matching layer built inside the U/S transducer?

A

The acoustic impedance of the PZT crystal is very different to that of the skin. Therefore, a large % of sound intensity would be reflected at this interface and not transmitted. A matching layer is therefore placed immediately in front of the PZT crystal to match the acoustic impedance of the crystal and soft tissue. Modern impedance matched transducers have multiple matching layers to maximise transmission.

42
Q

How is a matching layer in a basic transducer calculated?

A

It is designed to be the geometric mean of the materials it is matching to maximise U/S transmission.

43
Q

What is a multi-element transducer? What are these transducers also called? Why are they used?

A

These are now most modern transducers. They have many small crystal elements for the formation of each ultrasound pulse. Each element produces a small wavefront, and they each combine to form a single wavefront. The individual elements must be acoustically and electronically isolated from each other.

Known as ARRAY TRANSDUCER (as they form an array of elements)

This technique allows for greater flexibility in beam formation.

44
Q

What are the types of array transducers?

A

Linear
Convex
Phased
Annular

45
Q

Explain the types of wave interference? How is this considered in transducer manufacturing?

A
  1. Constructive interference - waves are in-phase and add together (higher amplitude).
  2. Destructive interference - waves are out-of-phase and negate each other (amplitude lower).
  3. Complex interference (mix of both above)

Transducers can be designed to optimise constructive interference to get a narrow and thin beam (increasing amplitude in the middle), and create timings to facilitate destructive interference on the outside of the beam for to optimise image.

46
Q

The rate at which pulses are emitted by the transducer is known as ___?

A

Pulse repetition frequency (PRP)

47
Q

What is the pulse repetition period? What is the main reason this is important for imaging?

A

The time from the start of one pulse, to the start of the next pulse.

The PRP must be long enough to allow all required echoes to be received by the transducer, so ultimately, this is the DEPTH CONTROL on the machine (listening time)

48
Q

The length of time we wait for an echo to return can tell us ____

A

How deep the echo came from

49
Q

What is the difference between pulse duration and duty factor

A

Pulse duration is the time taken for one pulse in seconds. Duty factor is the FRACTION of time that the unit is transmitting (pulse duration divide PRP)

50
Q

What is spatial pulse length (SPL) and how is it determined?

A

The actual length of on pulse measured in metres. SPL is determined by the length of one cycle, so, the wavelength x number of cycles in one pulse.

51
Q

A pulsed ultrasound beam consists of sound waves of multiple frequencies. The range of frequencies is called _______. Where is this normally measured?

A

The bandwidth

Usually measured at the half intensity (or amplitude) level.

52
Q

A shorter U/S pulse has a ____smaller or larger?_____ range of frequencies? What does this mean for the bandwidth?

A

Larger range

Increased bandwidth

53
Q

What is the centre frequency of the beam? What happens to the centre frequency as the pulse passes through tissue?

A

The maximum intensity = resonant frequency of the crystal

The centre frequencies change because higher frequency components are attenuated to a greater degree than the lower frequency components.

54
Q

The beam emitted from a typical diagnostic U/S transducer is not uniform. It will vary in both ____ and time ___.

A

Space and time

(I.e. spatial variation and temporal variation)

55
Q

What is spatial variation?

A

This is the variation of intensity of an U/S beam over a distance. It varies with
(a) distance from the transducer and
(b) cross-sectional area of the beam

56
Q

What is the difference between spatial peak and spatial average

A

Spatial peak occurs along the axis of the beam at the focal point. The spatial average is the average intensity across the beam, at a specified distance from the transducer (usually the focal point)

57
Q

The spatial ___ can be up to _x the spatial ____

A

The spatial peak can be up to 25x the spatial average

58
Q

What is temporal variation?
Briefly explain temporal variation with pulsed echo.

A

The variation of intensity of an ultrasound beam with time.

Pulse echo u/s uses short pulses of sound, separated with long periods of rest. During the time between pulses, intensity falls to zero. Temporal variation even occurs during a pulse (cycling change in intensity within each pulse)

59
Q

List some of the times that beam intensity can be measured (i.e with respect to temporal variation)

A
  • Temporal peal: the maximum amplitude/intensity of the pulse
  • Pulse average: the average intensity over the duration of a single pulse
  • Temporal average: The average intensity taken over one whole on/off beam cycle (including rest time).. much lower
60
Q

What is the temporal average? How is it calculated?

A

The average intensity taken over one whole on/off beam cycle (including rest time). It can be up to 1000x less than the temporal peak due to the large rest time between pulses.

TA intensity = PA intensity x Duty Factor

(duty factor = pulse duration/PRP)

61
Q

Describe the near field in beam profiling?

A

Characterised by a non-diverging beam (sometimes called frenzel zone). This is the LENGTH in a non-focussed transducer.

62
Q

What are two factors that affect the near field and far field calculations?

A

Size of transducer (diameter) and the operating frequency of the transducer (specifically wavelength)

63
Q

Describe the far field in beam profiling?

A

Characterised by a diverging beam (sometimes called the fraunhofer zone). This is the ANGLE of divergence in a non-focussed transducer.

64
Q

What are side lobes?

A

Weak “off shoot” beams of sound of low intensity. They occur in all planes due to the complex interference of the wavelets emitted, and give off artifacts that degrade the image

65
Q

What is the 3rd dimension of an U/S beam that is not apparent in the 2D image created?

A

Slice thickness

66
Q

Considering beam width, what are the two common definitions for intensity?

A

The 3 DB edge
- The beam width edge is taken as the point in intensity that the beam has fallen to 1/2 its max value

The 10dB edge (more common)
- The beam width edge is taken as the point in intensity that the beam has fallen to 1 10th its max value

67
Q

What are grating lobes?

A

A special type of side lobe occurring in array transducers. They occur only in the scan plane and tend to be of higher intensity then conventional side lobes - they can often cause artifact.

68
Q

What can transducer manufactures do to reduce grating lobes?

A

(A) Apodisation
- Controls the intensity across the beam, by decreasing the voltage of the pulse to outer elements of a firing group. Therefore wavelets from outer elements have less intensity (and also reduced sensitivity on receive of echo)

(B) Decrease the element spacing
- Reduced spacing can allow the grating lobe angle to reach 90deg, where the lobe artifact would tranvel “backwards”. There is a limit to how much this can be done, so elements can also be SUBDICED.

69
Q

What is element subdicing?

A

Where normal crystal elements are “subdiced” into multiple smaller elements, each transmitting its own wavelet, acting like an individual crystal. A technique used to reduce grating lobe artifact

70
Q

What are the four ways in which beam focussing is accomplished?

A
  1. Curved crystal
  2. Lens
  3. Focussed mirror
  4. Electronic (Arrays) - very common
71
Q

With beam focussing, what will decreasing the radius of curvature do?

A
  • Decrease the focal depth
  • Decrease the beam width at the focal depth
72
Q

We focus the beam to improve what kind of resolution?

A

Lateral resolution

73
Q

How is the focal zone defined?

A

The depth range of the beam that is less than twice its minimum width. It is the portion of the beam with the highest intensity (decreased area)

74
Q

What is another name for electronic focussing

A

Array focussing

75
Q

How does electronic focussing work?

A

By slightly delaying the firing time of the inner elements of an array, the combined individual wavelets form a beamfront (Hyugens principle) which is focussed. A delay circuit is used to achieve this.

76
Q

What happens when the delays are increased in electronic focussing?

A

The radius of curvature decreased, therefore the focal point moves closer to the transducer (shorter focal zone). At the same time, increased focussing beams the focal zone is narrower.

77
Q

What is the benefit of modern transducers having multiple focal zones? What is the compromise?

A

There can be a narrow beam path over the entire depth. However, this will require a reduced frame rate because of the extra time taken to produce each line of echoes.

78
Q

What is Dynamic Aperture?

A

A form of beam focussing to further reduce beam width close to the transducer, by having fewer crystal elements used for the echo pulses. It is effectively the same as reducing crystal diameter.

79
Q

What is dynamic recieve focussing?

A

Similar to array focussing, delays can be used to “hold up” the inner elements of a returning echo wavefront, so that the curved wave is processed at the same time. This allows a short high amplitude output to be produced.

80
Q

How can we tell how deep a structure/interface is from an echo that has returned?

A

Based on the time it took for the echo to return.

81
Q

How is depth altered in U/S

A

By adjusting the PRF - the rate at which the pulses are emitted from the transducer. I.e. deeper tissues require a longer time for the transducer to wait until all echoes are returned, therefore a lower PRF.

82
Q

What is A-Mode ultrasound

A

An older form of U/S, whereby the returning echoes were displayed on the screen as an amplitude variation, whereby amplitude represented echo strength. It could not produce images of anatomy.

83
Q

Increased line density = increased ______

A

lateral resolution

84
Q

What is line density and what does it affect?

A

A term used to describe how close the beam lines are. When line density increased, that will improve lateral resolution.

85
Q

Does line density change with depth?

A

Yes, in sector or convex transducers. Even with a large number of lines, the line density can become quite poor in the far field.

86
Q

What is compound imaging?

A

A form of B-Mode imaging that uses electronic steering to create several angled beam paths from each point. The echoes received from all the beam paths are combined to form a single frame. This helps to image interface that lay along (parallel to) an otherwise straight beam path.

87
Q

What would be one downside to compound imaging?

A

It can reduce shadowing and enhancement because the beam paths will be able to write into these areas. This is only an issue when shadowing is being looked for/ suspected, for example in breast u/s. It should be turned off if required.

88
Q

What is M-Mode Ultrasound? How would it be read on the monitor?

A

Used to geographically demonstrate any movement of organs or structures. It uses many of the principles of B-Mode ultrasound, but does not build up an image with multiple beam paths.

If there is no movement, the lines a straight.
If there is movement, it will be displayed like a wave, indicating movement towards or away from the transducer (depth on y axis, time on x axis)

89
Q

When might M-Mode ultrasound be used?

A

To detect foetal heart movement

To measure heart value opening times and cusp displacement in echo

90
Q

Define frame rate

A

The rate at which B-Mode frames are processed

91
Q

What is real time imaging?

A

The propagation of rapid, sequential frames of images. The rate at which these B-Mode frames are produced is the frame rate.

92
Q

What two factors does frame rate depend on?

A
  • The number of scan lines in each frame
  • The time required for each scan line
93
Q

Explain the ways that frame rate can be increased

A
  1. Decreasing depth of penetration (less depth = less “wait” time)
  2. Decreasing the number of scan lines (less scan lines = less time to produce entire frame). There are three ways scan line can be reduced
    (A) Decreasing the field of view
    (B) Decreasing the line density
    (C) Decreasing the number of focal zones (each focal zone is
    equivalent to another scan line)
94
Q

What changes will occur if the maximum depth of the field of view is increased?

A
  • The image will extend over greater depth
  • The line density will remain the same, unless in a phased array
    transducer, density will decrease with increased depth.
  • The PRF will be reduced
  • The frame rate will be reduced (more anatomy seen with compromised frame rate)
95
Q

What will occur to the image if the sector angle is decreased?

A

The FOV will decrease
AND either one of the following (depending on the
machine/brand):

The line density remains the same (same spatial image quality) and the frame rate will increase (because each frame takes a shorter time to produce - temporal image quality will improve - good for moving structures)
OR
The line density will increase (spatial image quality increases) but the frame rate will not change.