Week 9 Part 2 - Resolving Complex Antibody Mixtures Flashcards

1
Q

Examples of Complex Antibody Mixtures

A

Unexplained reactions
Antibodies to high and low frequency antigens
Multiple antibodies
High titre, low avidity “like” antibodies
Positive auto control

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2
Q

Examples of Unexplained Reactions

A

Reactions that don’t match a pattern on panel sheet
Technique/reagent problem
Antibody against reagent
Antibody against a low/high frequency antigen not listed on panel sheet
Antibody demonstrating dosage
- anti-Jka and anti-M as examples

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3
Q

Low Frequency Antigens

A

Occurs in <10% of population
Kpa, Cw, Lua, Jsa, Dia, etc
Antibodies against these are rare
Not identified on screen
Identified in combination with another antibody, or after an incompatible XM with a neg screen
Easy to find blood for transfusion

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4
Q

High Frequency Antigens

A

Present in > 98% of the population
k, U, Kpb, Jsb, Lub, Coa
Antibodies against these are rare
All panel cells pos w/ uniform rxn strength, neg auto control

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5
Q

How to identify High Frequency Antigens?

A

Want to test cells that are negative for high incidence antigens
Enzyme-treated/chemically modified cells
- eg. DTT destroys Kell and Lutheran ag’s
- rare Rhnull and K0 cells
Phenotyping

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6
Q

Diego Blood Group

A

Contains 22 antigens
Dia/Dib; Wra/Wrb; Wu/DISK - antithetical pairs
16 low-incidence
Carried on band 3 - RBC integral membrane protein
The Di(a-b+) is the most prevalent phenotype
Anti-Dia
- IgG
- causes HTRs and HDNB

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7
Q

Results seen with Multiple Antibodies

A

Positive reactions against many panel cells
A single antibody doesn’t account for the pattern of reactions
Varying strength of reactions
Negative autocontrol

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8
Q

Anti-G

A

G antigen
- an antigen in the Rh blood group
- present on C and D antigens, and therefore C+ and/or D+ RBCs
Individuals who are G- can produce an anti-G antibody
- most Rh(D) neg individuals are rr, and therefore are also G-
- sensitised to G antigen after exposure to r’r cells

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9
Q

Anti-C+D vs Anti-G

A

Anti-G will react to C+ D+ cells on ID
Is the antibody present anti-G, or are two aby’s present (i.e. anti-C+D)?
- anti-C+D anti-D component is usually stronger than anti-C
- anti-G - apparent anti-C component (i.e. reactivity against D-C+ cells) is stronger than apparent anti-D component (i.e. reactivity against D+C- cells)

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10
Q

Why is it Important to Differentiate between Anti-C+D and Anti-G

A

Because someone producing anti-G (or anti-C+G) is eligible for Rh(D)Ig, whereas someone producing anti-D+C is not

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11
Q

Phenotyping

A

React patient RBCs with known antibody to determine which antigens they express
Can’t phenotype if recently transfused (< 3 months)

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12
Q

Controls used in Phenotyping

A

Need to ensure that the system can detect the weakest examples of antigen expression
Positive Control
- RBCs which have heterozygous expression of the target antigen
- i.e. M+N+
Negative Control
- RBCs which do not express the target antigen
- i.e. M-N+

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13
Q

Adsorption to Separate Multiple Antibodies

A

Plasma is mixed with cells expressing only one of the antigens to which the suspected antibodies are directed
- i.e. D+, Fy(b-) and D-, Fy(b+)
Antibody binds to antigen
Single antibody remaining in adsorbed plasma

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14
Q

Antigen Separation to Separate Multiple Antibodies

A

Chemical treatment of cells to enhance or degrade antigen

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15
Q

Antigen Modification - Enzyme Treatment of Cells

A

E.g. ficin, papain, bromelin, trypsin
Inactivate Duffy, MNS, Ch, Rg, antigens (others too)
Enhance Rh, Kidd, Lewis, P, I antigens
Can only cross-out antigens which are not destroyed

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16
Q

Antigen Modification - DTT or AET Treatment of Cells

A

Reducing agents
Destroy Kell antigens

17
Q

Neutralisation to Separate Multiple Antibodies

A

Some antigens are soluble and are found in various fluids/substances
Incubated with plasma before antibody ID to neutralise the antibody present

18
Q

Examples of Soluble Antigens that Require Neutralisation

A

Lewis antigens - plasma or saliva of Le(a+b-) and Le(a-b+) individuals
P1 substance - hydatid cyst fluid, pigeon droppings, turtledove egg whites
Sda - urine of Sd(a+) individuals
Chido and Rodgers antigens - plasma of most people

19
Q

High Titre, Low Avidity ‘Like’ Antibodies (HTLA)

A

Formerly known as HTLA antibodies
React against most panel cells w/ neg auto control
Tubes - weak-1+ agglutination that easily break up
Cards - 1-2+ agglutination

20
Q

HTLA Titre

A

Classically have high titres
Titre
- doubling dilutions of patient plasma containing Aby
- react against cells carrying corresponding Ag
- reciprocal of the highest dilution giving a 1+ reaction

21
Q

HTLA-‘Like’ Antibodies - Chido/Rodgers (Ch/Rg)

A

Components of C4 complement protein
Rg - C4a, Ch - C4b
Adsorbed onto RBC surface from plasma
Ch/Rg neg individuals can make anti-Ch/Rg antibodies
Antigens are destroyed by enzymes, resistant to reducing agents

22
Q

Testing Setup for HTLA-‘Like’ Antibodies Ch/Rg

A

Identify by neutralising antibodies by plasma containing Ch/Rg
Test sample - patient plasma + normal plasma (1:1 ratio)
Control sample - patient plasma + albumin (1:1 ratio)
Test both using same method that detected suspected aby
If aby is anti-Ch/Rg, reactivity will become negative

23
Q

HTLA-‘Like’ Antibodies - John Milton Hagen (JMH)

A

Antigen is present on CD108, a glycosylphosphatidylinositol (GPI) linked protein
Destroyed by enzymes and reducing reagents

24
Q

HTLA-‘Like’ Antibodies - Knops

A

Antigens are present on CR1, the RBC C3b/C4b receptor
- Kna, McCa, Sla, Yka
Weakened by enzymes, destroyed by reducing agents

25
Q

Patient has anti-D and anti-Fyb antibodies. Requires two units of blood. Have 56 units of ABO group-specific blood in the fridge. Are 2 compatible units likely to be present? How many units do you need to screen to find 2 compatible units?

A

19.7% of the population are Fy(b-)
17.9% of the population are D-
Found in frequency table
Convert numbers to decimals then multiply together
- i.e. 0.197 x 0.179 = 0.035, which = 3.5%
So 3.5% of the population should be D-, Fy(b-)
Number of compatible units in fridge
- total no of units x % of popn that is compatible
- 56 x 3.5%
- 1.96 units
How many units do I need to screen to find 2 compatible units?
- no. of units reqd / % of popn that is compatible
- i.e. 2/0.035, = 57.14 units