Week 8 Flashcards
hydrobromation details
step 1: BH3, THF (no intermediates!)
step 2: NaOH, H2O2
alkene fills B’s empty p orbital
one step to BH2 on less substituted C and H on other
b/c of transition state - more subbed C can better stabilize positive charge
ALWAYS SYN B/C OF TRANSITION STATE
oxymercuration details
step 1: Hg(OAc)2 and H2O
step 2: NaBH4 (cleaves Hg-C and replaces Hg with H)
one step to 3 membered cyclic ring
be SUPER careful with stereochemistry of methyl group getting pushed back and forward by 3 membered ring and then water
what 2 reasons account for hydroboration connectivity? why is it non-Markovnikov?
- steric strain of methyl with B
- in transition state, higher degree C better stabilizes positive charge
hydrogenation
H2 gas
Pd/C (only alkenes)
syn
carbene
CHCl3 in base -> CCl3(-) but chlorine is happier alone so -> CCl2
simmon-smith
hydroboration
- BH3, THF
- H2O2, NaOH
oxymurcuration
- Hg(OAc)2, H2O/THF (3 mem. ring, water attacks from opp. face)
- NaBH4 (replaces C-Hg with C-H)
halogenation in water vs THF vs. with NBS
both start with halonium ion formation. then,
a) THF - remaining halogen ion attacks from opp. face resulting in anti X’s
b) water - water attacks instead of halogen ion then depronated by another water to give an anti halogen and alcohol… BROMOHYDRIN
c) NBS - for example with Br2, it’s nasty so want to use NBS in H2O/DMSO
hydration (not oxymercuration or hydrobromation)
add H2O (which becomes acid H3O+) and heat in H2SO4 catalyst
3 types of hydration
water and heat with H2SO4 catalyst
epoxidation
TRANS DIOLS
1. MCPBA (per benzoic acid O-O) makes 3 mem ring with O
2. acid like H3O+ in water
dihydroxylation
SYN DIOLS
1. alkene nuc attacks O on OsO4, forms structure with entire OsO4
3. water breaks O-Os bonds and adds hydrogen onto O’s, NMO regenerates OsO4
alkene cleavage
a) dihydroxylation then 1,2-diol cleavage
1. OsO4, NMO
2. HIO4 in H2O/THF (creates structure with HIO4 complex, electrons from one I-O bond create double bond to C and electrons from C-C bond create other C=O bond, that’s why it needs to be syn dihydroxylation and not anti epoxidation)
b) ozonolysis
1. O3
2. Zn/CH3COOH