week 4 Flashcards

1
Q

polyatomic MO diagrams and Walsh diagrams

A

see w4 videos 18-20

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

define hybrid atomic orbitals

A

the result of combining atomic orbitals to make orbitals that are appropriate to form bonds with direction and angle predicted by VSEPR

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

when forming HAOs, no. of atomic orbitals =

A

no. of HAOs

if you combine 4 atomic orbitals, you form 4 hybrid atomic orbitals

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

how do you make the following haos
sp
sp2
sp3

A

you always start with an s-orbital then add p-orbitals
s + p
s + p + p
s + p + p + p

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

2 similarities and 1 difference of haos of the same type, eg 2 sp haos

A

same energy
same overall shape

point in all different directions

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

sp HAOs

  • how many are there
  • how many bonds can be formed
  • angle they point away from each other
  • what happens to remaining p-orbitals
A
  • 2: one is in phase, one out of phase
  • forms two single bonds
  • 180°
  • remaining px and py orbitals are unhybridised and overlap to form 2 pi-bonds
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

sp2 HAOs

  • how many are there
  • how many bonds can be formed
  • angle they point away from each other
  • what happens to remaining p-orbitals
A
  • 3
  • forms three single bonds
  • point 120° away from each other in a plane
  • remaining p orbital is unhybridised overlaps to form one pi-bond
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

sp3 HAOs

  • how many are there
  • how many bonds can be formed
  • angle they point away from each other
  • what happens to remaining p-orbitals
A
  • 4
  • forms four single bonds
  • 109.5°
  • no more orbitals so forms 4 single bonds
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

how are hybrid molecular orbitals formed

A

HMOs made from overlapping HAOs with HAOs or AOds

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

which HAOs and HMOs are involved in the C-H bond in methane

A

C: is sp3 hybridised
H: just has outer 1s orbital

sp3 and 1s overlap to form a σ bonding HMO and a σ* anti-bonding HMO

see w4 vid22 for HCN example

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

which overlap is more constructive sigma or pi and why

A

sigma is more constructive

orbitals in sigma overlap point towards each other but in pi overlap they are parallel and so don’t overlap as constructively as sigma

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

what is meant by delocalised π-bonding in a molecule

A

bonding that involves out-of-plane 2p orbitals (π-bonds) from two or more atoms in the molecule

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

describe how benzene has delocalised π-system

A
  • each C in benzene is sp2 hybridised
  • each C has a 2p orbital that lies perpendicular to the plane of the ring
  • the π MOs are formed from all 6 2p AOs

see w4 vid23 for drawings of π MOs

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

describe how butadiene has a delocalised π-system

A
  • each C is sp2 hybridised
  • each C a 2p orbital perpendicular to plane of the alkene
  • the π MOs are formed from all four of these AOs
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

in the delocalised π-system in benzene, describe:

  • the lowest energy MO
  • the highest energy MO
  • the intermediate MO
A

lowest energy

  • all 6 2p orbitals in phase, lobes on top of the plane are same phase and lobes below the planes are the same phase
  • no nodal planes

highest energy

  • all 6 p orbitals are in alternating phases, adjacent p orbitals are opposite phases
  • 3 nodal planes

intermediate MOs

  • will have 1 or 2 nodal planes
  • MOs with same number of planes are degenerate
How well did you know this?
1
Not at all
2
3
4
5
Perfectly