Week 2 - Introduction to Inverse Matrices Flashcards
Week 2
Name two characteristics of an elementary matrix.
(1) Corresponds to a particular elementary row operation.
(2) These matrices are always invertible.
What are the main three elementary row operations?
(1) Swapping two rows:
Ri <=> Rj
(2) Multiply a row by a non-zero constant:
Ri’ -> Ri
(3) Add a multiple of one row onto another:
Rj’ -> Rj + α Ri
When is matrix A invertible?
If there is a matrix B such that AB and BA are both identities.
What is the identity matrix? What happens when you multiply it with another matrix?
Pivot in every column, every other entry is zero.
Matrices multiplied by the identity is equivalent to multiplying by 1.
Write this property as an expression:
(1) The inverse of A and then the inverse of that, you get back the original matrix A.
(A^-1)^-1 = A
Write this property as an expression:
(2) Inverse of the product of A and B is the product of the inverses of A and B but in the opposite direction.
(A*B)^-1 = B^-1 A^-1
Write this property as an expression:
(3) The inverse of A multiplied by scalar c, is the product of the inverses of c and A.
(c*A)^-1 = c^-1 A^-1
Write this property as an expression:
(4) The transpose of the inverse of matrix A is the inverse of the transpose of matrix A.
(A^-1)^t = (A^t)^-1
What is the proof for property 2?
(A*B)^-1 = B^-1 A^-1
= A B B^-1 A^-1
= A I A^-1
= A A^-1
= I
How do you find the inverse of a square matrix?
Form augmented matrix (A | I ) and apply elementary row operations until the LHS is in RREF.
If you get (I | B), then the matrix is invertible –> A^-1 = B.
If not, then the matrix is not invertible.
What are the 7 conditions that allow us to determine the invertibility of a matrix?
(1) A is row equivalent to I.
(2) A is invertible.
(3) Ax = 0 has only the trivial solution x = 0.
(4) Ax = b has exactly one solution for an b ∈ ℝn.
(5) The columns of A span ℝn.
(6) There is a matrix B with AB = I.
(7) There is a matrix B with BA = I.
Explain how these conditions are dependent on each other:
(1) A is row equivalent to I.
(2) A is invertible.
Matrix A is only invertible if there is a matrix B such that AB and BA are both identities. This means that ERO’s need to be applied to acquire the identity matrix and this can only be achieved if the matrices are the same size. Therefore, it must be row equivalent.
Explain how these conditions are dependent on each other:
(2) A is invertible.
(3) Ax = 0 has only the trivial solution x = 0.
x = Ix (sub in I = A^-1A)
x = A^-1Ax (sub in Ax = 0)
x = A^-10
x = 0
Explain how these conditions are dependent on each other:
(3) Ax = 0 has only the trivial solution x = 0.
(1) A is row equivalent to I.
If A is not row equivalent to I then the RREF(A) will have a zero row and so fewer than n pivots –> non-trivial solution.
Explain how these conditions are dependent on each other:
(4) Ax = b has exactly one solution for an b ∈ ℝn.
(5) The columns of A span ℝn (the spanning set of the columns).
Finding a solution to Ax = b corresponds to finding a way of writing b as a linear combination of the columns of A.