W7.3_Stability Testing Flashcards

1
Q

Regarding stability testing, differentiate the stress testing in active pharmaceutical ingredients (API) and finished pharmaceutical products (FPP).

A
  • API: help identify the likely degradation products, can help establish the degradation pathways, carried out in single batch, include temperature/humidity, (oxidation/ photolysis), evaluate susceptibility to hydrolysis across different pH
  • FPP: photostability testing on at least one primary batch
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2
Q

Regarding stability testing, differentiate the container-closure system in API and FPP.

A
  • API: same as/stimulates packaging proposed for storage and distribution
  • FPP: on dosage form packaged in primary container-closure systems proposed for marketing/ secondary container- closure systems/ semi-permeable container
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3
Q

Regarding stability testing, differentiate the specification in API and FPP.

A
  • API: include testing of stability- indicating attributes (physical/ chemical/ biological/ microbiological)
  • FPP: API + preservative (ex. antioxidant/antimicrobial) content, functionality tests (ex. dose delivery system)
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4
Q

Regarding stability testing, differentiate the storage conditions in API and FPP.

A
  • API: thermal stability, sensitivity to moisture, long-term/accelerated studies
  • FPP: under intended country’s climatic conditions, with possible specified tolerances
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5
Q

What are the aim, necessity, and reason for chemical and physical stability testing? State some of the common tests carried out in solid forms and aqueous solutions.

A
  • Aim: provide evidence of quality, establish shelf life, determine recommended storage conditions and container closure system suitability
  • Necessity: chemical degradation leads to degradation of drug concentration, toxic product may form
  • Reason: assurance to patient/therapeutic efficiency guarantee, economic considerations/restocking, legal requirement
  • Solid form: heat, humidity, physical stress
  • Aqueous solution: pH, light, oxidation
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6
Q

Explain the routes of chemical degradation that requires testing.

A
  • Hydrolysis by pH (H+/OH-), buffer (ions in buffer chemical components), solvent (catalysed water, co-solvent or organic solvents), heat and humidity, drug concentration
  • Oxidation
  • Photolysis (light causing decomposition/heat/emission of light)
  • Chelating agents (bonding of ions/molecules with metal ions to form unwanted complexes)
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7
Q

Explain the properties of pH stability testing. Differentiate specific acid-base catalysis and general acid-base catalysis. How may pH affect some drugs? How about reconstituted drugs?

A
  • Catalysed by H+, OH-, water, buffer components
  • Specific acid-base catalysis: absence of buffer
  • -d[A]/dt=(k(0)+k(H+)[H+]+k(OH-)[OH-])[A]k(0) = rate constant of water
  • Lowest point on graph = most stable to store/formulate
  • General acid-base catalysis: presence of buffer
  • Buffer components will affect drug components and their stability
  • Buffer needs to be carefully selected to avoid drug decomposition
  • pH may affect oxidation of drugs (ex. adrenaline, vitamins)
  • Reconstituted drugs have lower stability, thus shorter shelf life
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8
Q

Describe the accelerated stability testing on temperature. Explain the use of Arrhenius equation in shelf life prediction and state it.

A
  • To evaluate kinetics of decomposition rapidly
  • Higher temperature -> lower activation energy -> increase in probability of collision/ decomposition (Maxwell Boltzman distribution)
  • Each 10C increase -> decomposition increased 2-5 folds
  • Arrhenius equation used to predict shelf life (assuming mechanism of decomposition does not change with temperature increase)
  • k=Ae^(-E(a)/RT) -> log k=log A-(E(a)/2.303R*T)
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9
Q

Describe how shelf life is determined from a data set of rate constants.

A
  • Determine rate constants of decomposition between 30C and 60C (through graphs above)
  • Extrapolate Ea and k of reaction at room temperature (20C) in this graph
  • Determine shelf life (t(90)) using equation above
  • Zeroth order: 0.9A=A-k(T=20C)*t(90)
  • First order: t(90)=-2.303*log(0.9)/k(T=20C)
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