VL 24 (Michael Lenhard) Flashcards

1
Q

Is there a genetic
influence on variation in
a quantitative trait?

A
  • grow different genotypes under the
    same environment
    –> is there phenotypic variation?
  • intercross individuals (e.g. large with
    large and small with small)
    –> do progeny phenotypes resemble
    parental phenotypes?
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2
Q

The mean and the standard deviation can be used to describe a normal distribution

A
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3
Q

There is often no simple relationship between genotypes, phenotypes:

A
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4
Q

Francis Galton ́s quincunx:

A
  • Nails/pins in border
  • Containers in bottom
    –> Funnel → balls;
    Balls fall down in container
  • Result: normal distribution; chance of being displaced left/right = same
  • Left/right extreme: always deflected left/right (less probabile)

→normal distribution if final outcome depends on number of independent decisions; each decision contributes to final outcome
* Expect: normal distribution of trait values; trait variation influenced by variation in a number of different genes (each having small/large trait allele) → random allele combinations determine
what trait expression will be
* small + large trait alleles (mostly), few: small, few: large

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5
Q

What is the essential difference between qualitative and quantitative traits?

A

gene numbers with different alleles, that contribute to phenotypic variation

Example
* P: 3 loci; homozygous
* F1: heterozygous at all 3 loci
* F2: 2^3→8 gametes for female, male; 20 intermediate; 64 → normal distribution

Result:
* 30 loci → individual loci contribution would be smaller; much closer normal distribution approximation
* = number of loci that contribute to trait variation and inversely the strength of the individual locus contribution (quantitative traits)
* Mendelian: qualitative traits; single locus with 2 alleles → huge effect on phenotypic variation

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6
Q

Reaction norm describes relationship between given genotype and its phenotypes in different environments

A
  • Norm of reaction = describes phenotype range that a single genotype can give rise to under different environments

Example
* Homozygous, inbred drosophila strains→replicate same genotype
* Flies under different T
* for each T, genotype: count trait (number of abdominal bristles)

Result:
* different genotypes respond different to T; single high trait value genotype that would have highest trait value throughout all of different environments; complex interaction between genotype + environment

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7
Q

Determining norms of reaction:

A
  • Difficult, laborious, as many individuals of same genotype need to be grown under different environmental conditions
  • Reaction norm known for how many human traits?
    → no it is not; no way of replicating human genotypes
  • Plants: ability to vegetatively propagate plants by cuttings allow generation of genetically identical clones
    → clones in different environment
  • Plants, animals:
    inbreeding → pure lines → different environments
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8
Q

Implications for breeding

A
  • vary 2 different parameters (environmental quality = fertilizer amount)
  • inbred maize genotypes
  • measure yield
  • plot reaction norms
  • dense planting: under all conditions; blue outyields red → use blue
  • loose planting: red crosses blue → better at higher fertilizer amount
  • know for which environment type you breed (→different genotypes
    performing best in one environment)
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9
Q

Phenotypic similarity between relatives

A
  • Relatively easy for experimental organisms
  • Studies in human
    –> Very difficult to exclude environmental variation/influence
    –> Preferred method:
    comparing phenotypic similiarity between monozygotic – dizygotic twins

Picture
Parental generation
* Interbreed individuals with low trait values + high trait values →
trait distribution
–> Blue: same trait distribution (not heritable: parents phenotype doesn ́t predict offspring phenotype)
–> Red: lower/higher trait value distribution; heritable
–> not in humans possible

  • monozygotic (identical twins) – dizygotic (fraternal twins) under same environmental conditions
  • mono: two individuals are genetically identically
  • di: two individuals in twin pair aren ́t not more similar than brother + sister
    Phenotypic similarity between relatives:
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10
Q

Estimating the components of variance

A
  • phenotype (p) = genetic influence (g) + environment (e); cant measure them; look at variation in these traits
  • 2 * cov(ge) ignored (hard to measure)

Picture
* 1st mendelain law: cross 2 homozygous inbred parents
→ heterozygous, uniform F1
→ phenotypic variation in F1 without genetic basis
→ environmental influence
* larger because genetic + environmental variation contribute to trait variation
* result: genetic influence responsible for 54,5 % of phenotypic variation

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11
Q

The interpretation of H2

A
  • H2 relates to given population in given environment
  • H2 > 0, genetic variation plays role in generating phenotypic variation in this population, environment
  • H2 = 0, doesn ́t mean that trait is inheritable, means: genetic variation doesn ́t contribute to phenotypic variation (e.g. no relevant genetic variation segregating in this population)
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12
Q

Narrow-sense heritability:

A
  • Genetic variance sg2 = additive genetic variance (sa2) + dominance-dependent variance (sd2)
  • Sa2 relevant for selection, breeding
  • Proportion of overall phenotypic variance that is due to additive genetic variance
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13
Q

QTL mapping/Linkage analysis and association mapping:

A
  • Linkage analysis + association studies rely on co-inheritance of functional polymorphisms + neighboring DNA variants
  • Linkage analysis: few recombination opportunities to occur within families + pedigrees with known ancestry→low mapping resolution
  • Association mapping (b, showing haplotype): historical recombination + natural genetic diversity were exploitedc→chigh-res mapping
  • Linkage disequilibrium between functional locus + molecular markers = low, except for those within very short distance

QTL:
* cross parents (different phenotype) homozygous inbred lines
* F1: uniform, heterozygous
→ recombinant gametes via meiosis
* F2: gametes combined
→ F2 with phenotypic + genotypic segregation
* measure trait value (in example: height)
→ genotype them throughout whole genome; look: associations between parental alleles – trait expression
* middle: association: short homozygous for red allele; tall homozygous for blue allele

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14
Q

QTL (quantitative trait locus):

A
  • Chromosomal interval carrying different alleles that influence phenotype in question
  • Goal: trying to find these intervals
    → associating a parental allele in chromosomal interval with phenotypic values
  • Recombinant inbred lines
  • repeated measurements
    → more accurate phenotype estimate for given genotype (random error should, average out from multiple measurements)
  • allows studying genotype x environment interactions
  • only have to be genotyped once
    → for additional traits, only phenotyping required

Picture
* P=g+e
* Measurements on single individuals are problematic
* Recombinant inbred lines (RIL)
–> goal: measure multiple individuals with same genotype
→ trait estimate that is determined by this genotype
→ used for QTL
* parents → F1 → self F1 → F2
* 200 individuals from F2 selfed → progeny → pick 1 progeny and self again
* 200 inbred lines with homozygous genome; differs in genotype from other RILs
* Plant out 20 individuals → measure phenotype → phenotype estimate for genotype
* For every genotyped marker: difference between subpopulation by genotype at this position?
* 100 homozygous for red, 100 for blue allele

  • Are 100 homozygous red alleles on average different in there phenotype than 100 homozygous blue lines? Yes
    → allele near marker, that influences phenotypic variation
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15
Q

Linkage disequilibrium

A
  • 2^3→8 genotypes with frequencies in population

Alleles at SNP1 independet of SNP2 or are they associated with each other across the population?

  • SNP1: (14,5 + 14,5 + 0,3 + 0,3)% = 29,6% mit A
  • SNP2:(14,5+34,5+0,3+0,7)%=50%mitG
  • 0,5*0,296 = 0,148
  • AG: (14,5 + 0,3) = 14,8%→alle Werte passen in Tabelle 2 überein→SNP1 + SNP2 in linkage equilibrium; genotypes at these positions are independently distributed

Tabelle
* Observed not expected frequency →2 genotype combinations over /underrepresented
* Linkage disequilibirum between SNP2, 3 → not independent of each other in population
* Knowing SNP2 genotype → tell SNP3 genotype (98% accuracy)
e.g. physical proximity between loci

right:
* 20 possibilities for breaking chromosome + recombine it with other
→fragments = places where LD will appear = haplotypes

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16
Q

The length of haplotype blocks depends on the distribution of cross-over frequencyHaplotypes, linkage disequilibrium:

A
  • Peaks → high number of crossing over events in different meiotic divisions
  • Blocks between peaks→passed on generations; unrecombined
    →modern genomes = mosaics of haplotype blocks derived from ancestral chromosomes +
    recombined
  • Each population: individual genome = mosaics of haplotype blocks (each of which is present in only few different states, reshuffled + put together over generations)
  • 4-6 haplotype blocks
  • 1/4 or 1/6 haplotype blocks in certain genome region
17
Q

Logic of association mapping:

A
  • Chromosomes passed down many generations → meiotic events
  • Each haplotype block between 3-4 different haplotypes
  • Disease inducing mutation in todays generation: SNP close mutation
    in haplotype block in LD with mutation → SNP far away not in LD with mutation
18
Q

Genome-wide association mapping (GWAS)

A
  • based on LD between marker SNP + mutation
  • exploits recombination over many meiosis during population history
    → potentially very high resolution
  • only possible with high-density genotyping (the shorter the average haplotype bloks/LD are, the higher the density required; typical values 1 kb [Drosophila, Mais], 10 kb [Arabidopsis
    thaliana], 5-100 kb [humans])
  • based on “common disease/common variant” hypothesis

Limitations of GWAS:
* only works, if casual polymorphism is at reasonable frequency in population (> 5%)
* confounding due to unrecognized population structure
* does not work under allelic heterogeneity
* individual loci identified often only contribute little to phenotype or probability of disease