vectors Flashcards
eqns of a plane
scalar product form: r.n =p
vector form: r = a + λb + μc
cartesian form: ax + by + cz = d
angle between line and plane
angle between n and d, then 90-
angle between two planes
angle between the normal vectors
eqns of line
r = a + μd
(r-a) x d = 0
x-x’/a = y-y’/b =z-z’/c
cross product
a x b = |a||b|sinx n
n is the unit vector n
area of a triangle between two vectors
1/2 |a x b|
area of parallelogram between two vectors
|a x b|
intersection of a line and plane
plane in cartesian, sub in terms of λ then solve for the point with given λ
intersection of two planes
parallel planes = nun and same n
line of intersection, has direction perpendicular to both n, fix some point on the intersection
shortest distance between two skew lines
for two lines : r = a + λb and r = c + μd
(a - c).(b x d)/|b x d|
this imagines each line lies on parallel planes and is some multiple (a -c) of the unit vector n
shortest distance between parallel lines
fix point on one of lines
general vector from point to other line
direction vector of line . new vector = 0
find || of vector
shortest distance between planes
intersect = 0
r . n is the shortest distance to the origin given that n is the unit vector
difference between two distances