Vectors Flashcards
(a,b,c).(x,y,z)?
= ax + by + cz
Angle between two vectors?
Cos theta = (a.b)/lallbl
What is the dot product of two perpendicular lines
The dot product is 0.
Cos 90 = 0 = (a.b)/lallbl
Given a = (2, 5, -4) and b = (4, -8, 5) find the vector perpendicular to a and b
Let this vector be (x, y, z)
Then (2, 5, -4).(x, y ,z) = 0
And (4, -8, 5).(x, y, z) = 0
Let z = 1
2x + 5y = 4
4x - 8y = -5
=> x = 7/4, y = 3/2, z = 1
So a possible vector is (7/4, 3/2, 1)
Equation of plane in vector form?
Let the normal to the plane = n
a and r are points on the plane
AR . n = 0
=> (r - a).n = 0
r.n - a.n = 0
r.n = a.n (often denoted by d)
Equation of a plane in Cartesian form?
n = (n1,n2,n3) and a = (a1,a2,a3) and r = (x,y,z) (any vector on the plane)
Then for r.n - a.n = 0:
n1x + n2y + n3z -a.n = 0
n1x + n2y + n3z + d = 0 (where d = -a.n)
A = (2, 3, -5) on a plane, normal to the plane is (-4,2,1) find Cartesian equation
n1x + n2y + n3z + d = 0
Cartesian eqn = -4x + 2y + z + d = 0
To find d, either sub in a point on the plane:
-4(2) + 2(3) + 1(-5) + d = 0 => d = 7
Or d = -a.n = -(2,3,5).n = 7
What happens if you change d in the Cartesian equation
What do the coefficients of x,y,z and d determine in the Cartesian equation
The planes are parallel (but still have the same normal)
X,y,z determine the direction of the plane, d determines its location
What is the equation of the plane parallel to 3x - y + 2z + 5 = 0 which contains the point (1,0,-2)? The normal is (3,-1,2)
Any parallel plane has equation 3x - y + 2z + d = 0
d = -a.n
= - (3x1 + -1x0 + 2x-2)
d = 1
Equation is 3x - y + 2z + 1 = 0
Given 3 points A, B and C on a plane, how would you find the equation?
Substitute the points into ax + by + cz + d = 0
A plane contains the points (1,1,1), (1,-1,0) and (-1,0,2). Find the equation of the plane
sub each point into Cartesian equation:
a(1) + b(1) + c(1) = -d
=> a + b + c = -d
a - b = -d
-a + 2c =-d
See photograph
How do you find the angle between two planes?
Angle between planes is equal to the angles between their normals. Find their normals and use the cos theta thing
What are the 5 ways that three planes can intersect?
- if two of the planes are parallel, there are 2 possibilities for the arrangement of the third:
It can either be parallel to the other two (so all three parallel) or it can cut the other two (two parallel, and one cuts both - there is no common intersection between all three therefore no solutions) - if none of the planes are parallel, there are three possibilities:
The planes intersect in a single point (so only one distinct solution)
The planes form a sheaf (the three planes share a common line, so there are an infinite number of points of intersection)
The planes form a triangular prism (each pair of planes intersects in a straight line; the three lines are parallel. So there is no common intersection)
Find the unique point of intersection of the three planes:
2x+y-2z=5, x+y+z=1, x-y-3z=-2
Set up matrix simultaneous equations
Rearrange to find x, y and z. This the the unique point of intersection
If the matrix of coefficients for the three points (when finding their intersection) is non-singular…
The planes intersect at a single point