Units Flashcards
nutritionist’s calories
Cal or kcal = 1000 cal
1 cal = ? J
4.18 J
The mass balance states
input = output
X + Y = 100
Standardization
the process where the fat content of milk products is adjusted by the addition of cream or skim-milk.
input-output = accumulation
steady state is achieved when
there is no accumulation of material, i.e. input = output
batch operations, normally runs on
runs on a time basis (hourly)
100 = m+C
[m = mass of water removed; C = mass of concentrate produced]
If 100 kg h-‘ of liquid containing 12% total solids is to be concentrated to produce a liquid containing 32% total solids, how much water is removed each hour?
100 = m+C
100 x 0.12= C x 0.32
It is assumed that the water leaving the evaporator contains no solid. Thus, C = 37.5kg , m = 62.5kg
Water needs to be removed at the rate of 62.5 kg h^-1
accumulation
input +production-output = accumulation
kgm^-3 is equivalent to
g l ^-1
In a spontaneous change, heat (energy) is always transferred from _______ to ___________, until ___________ is achieved
from an object at a high temperature to one at a lower temperature
until thermal equilibrium is achieved
- C = ? *F
* F = ? *C
- C = (*F- 32) x (5/9)
* F= (9/5) x *C +32
absolute zero = 0 K
all molecular motion stops and the kinetic energy of the molecule becomes zero.
K = ? *C
- 15 + *C
Carnot efficiency (CE)
a measure of the conversion of heat to work
CE = [(Heat 1 - Heat 2) / Heat 1] x 100
Electric current (A)
a measure of the flow of electrons
unit = ampere (A)
One ampere (1 A) is
flow of electrons which, when flowing down two long parallel conductors, of negligible cross-sectional area, placed 1 metre apart in a vacuum produces between the two wires a force of 2x 10^-7 N per metre of the length
Luminous intensity unit
candela (cd)
units of velocity
m s^-1
surface area of a circle
r x r x pi
surface area of a sphere
4 x pi x r x r = pi x Dx D
1 m^2 = ? cm^2 = ? ft ^2
10^4 cm^2 = 10.76 ft ^2
volumetric flow rate (Q)
units
Volume of fluid that passes through a given volume of space per unit of time
m^3 s^-1
volume of a sphere
(4/3) x pi x r^3
surface-area-to-volume ratio
[2 (r + h) ] / rh
When heating an object, maximize the surface-area-to-volume ratio will
maximize the heat transfer rate and reduce the time required