Unit Five: Nuclear Chemistry Flashcards
C-14 is a radioactive form of a very common element. C-12 is the most abundant and stable form. Based on the graph, where is C-14 relative to C-12 in the band of stability?
C-14 is above C-12 on the band of stability
The band of stability is above the line on the graph that has a slope of 1. What does this indicate about the number of protons and neutrons for the majority of elements?
The number of protons and neutrons are equal. This is the case with any nucleus that has up to 20 protons.
As the atomic number increases beyond 20, a different trend becomes apparent. In this range, it appears that a stable nucleus is able to accommodate more neutrons. Stable isotopes have a higher neutron toproton ratio, rising to 1.5/1 for elements having atomic numbers between 20 and 83.
What type of decay would stabilize an atom of uranium-238? The atomic number of uranium is 92.
Alpha decay
A nuclide has 90 neutrons and 60 protons. Will this nuclide undergo decay? If so, what type?
The nuclide will not decay because it has a 1.5 to 1 ratio of neutrons to protons.
A hypothetical isotope has 60 protons and 60 neutrons. What type of radioactive decay would it most likely undergo?
It would undergo alpha decay because ..